Describe the crystallization process as applied in salt preparation
Answers
Explanation:
The principle used in the preparation of these salts is to dissolve
the cystine in an alcoholic alkali solution to which just sufficient
water to effect solution has been added, and, after filtering from
excess cystine, to precipitate the salt by addition of a suitable
indifferent solvent. While various solvents, such as acetone,
ether, or large amounts of alcohol caused precipitations, these were
either oily or amorphous. Only acetonitrile was found to possess
the power of initiating regular crystallization in the salt solutions.
While the solutions of the different salts require different amounts
of the solvent for complete precipitation, a partial substitution of
absolute ether for acetonitrile was found expedient in the case
of the most soluble of the salts, the K salt.
Answer:
It is simply a process of forming crystal.
Explanation: When salt is heated and dissolve in the liquid mainly water then its called saturated solution. When we further add salt and increase heat in order to dissolve it then it forcibly dissolve in liquid it's called supersaturated solution. After we slowly cool down the temperature then the salt we have put in supersaturated solution arises in the form of crystal. Hence its called crystalization.
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In a nuclear fusion reaction, the mass of the products is(1) less than the mass of the reactants because someof the mass has been converted to energy (2) less than the mass of the reactants because some of the energy has been converted to mass (3) more than the mass of the reactants because some of the mass has been converted to energy (4) more than the mass of the reactants because some of the energy has been converted to mass
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By using flame test we can identify the elements because colors which are given by elements with flame test are unique.
During the flame test, the electrons of the atom which are in ground state absorb energy and go to upper level. This is called electron excitation. Excited electrons are unstable. Hence, they come back to the ground state by emitting the energy as photons.If that released energy has a frequency which belongs to visual light, then that wave gives a color.
The colors observed during a flame test are caused by the presence of certain metal ions. When these metal ions are heated by a flame, the electrons in their outer energy level get excited and move to higher energy levels. As they return to their original energy levels, they release energy in the form of light, which we perceive as different colors.
During a flame test, the colors observed are caused by the presence of certain metal ions. When these metal ions are heated by a flame, the electrons in their outer energy level get excited and move to higher energy levels. As they return to their original energy levels, they release energy in the form of light, which we perceive as different colors.
For example, when a copper compound is heated, it emits a green color. This is because copper ions are responsible for this color. Different metal ions will emit different colors, allowing us to identify them by their characteristic flame color.
Therefore, the colors observed during a flame test are a result of the specific metal ions present in the substance being tested.
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B. This represents a chemical change only.
C. This represents both a physical and a chemical change.
D. This represents neither a physical change nor a chemical change.
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Answer:
What is filteration:
Filtration, the process in which solid particles in a liquid or gaseous fluid are removed by the use of a filter medium that permits the fluid to pass through but retains the solid particles. ... In some processes used in the production of chemicals, both the fluid filtrate and the solid filter cake are recovered.
Whendoweuseit:
Filtration is used to separate particles and fluid in a suspension, where the fluid can be a liquid, a gas or a supercritical fluid. Depending on the application, either one or both of the components may be isolated.
Inordertoseparateasalt-watermixture,
shouldastudentusefiltration:
The mixture can be separated by filtration, by dissolving the mixture in water. Salt will dissolve in the water, whereas sand will not.
Explanation:
hope it help's. pls mark as the brainliest.Rocket out.
Answers
The combustion reaction of the unknown compound can be written as follows:
Other part of the question is discussed below:
We know that 3.50 g of the compound produced 5.13 g of carbon dioxide and 2.10 g of water. This means that 1.63 g of oxygen were also produced in the reaction.
The mass of oxygen in the original sample is equal to the mass of oxygen produced in the reaction, so the original sample contained 1.63 g of oxygen.
The total mass of carbon and hydrogen in the original sample is equal to the mass of the sample minus the mass of oxygen, which is 3.50 g - 1.63 g = 1.87 g.
We can find the number of moles of hydrogen in the original sample by dividing the mass of hydrogen by the molar mass of hydrogen (1.008 g/mol). This gives us 1.87 g / 1.008 g/mol = 1.86 moles of hydrogen.
Therefore, the answer is 1.86
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Final answer:
By dividing the mass of water produced in combustion by the molar mass of Hydrogen in water, we find that the original compound contained 1.05 mol of Hydrogen.
Explanation:
To determine the mole amount of Hydrogen in the compound, you have to consider the reaction applied, and how it applies to the law of conservation of mass. Combustion of the compound produces carbon dioxide (CO2) and water (H2O). For water, one mol equals to the molar mass of H which is 1 g/mol, times the amount of H in water which is 2 to get 2 g/mol. Now knowing that 2.10 g of water were produced from combustion, we divide this by the molar mass of H-in-water to get the number of hydrogen moles in the original sample. So, the calculation will be 2.10 g/ 2 (g/mol) = 1.05 mol. So, the original compound contained 1.05 mol of hydrogen.
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Answers
Answer:
Yes, this reaction will be spontaneous.
Explanation:
A reaction is spontaneous if ΔG < 0.
The coupling of glycerol to glycerol-3-phospate with ATP gives:
glycerol + HPO₄²⁻ ⟶ glycerol-3-phosphate + H₂O ΔG = +9,2 kJ/mol
ATP + H₂O ⟶ ADP + HPO₄²⁻ ΔG = -30,5 kJ/mol
glycerol + ATP ⟶ ADP + glycerol-3-phosphate
ΔG = +9,2 kJ/mol - 30,5 kJ/mol = -21,3 kJ/mol
As ΔG<0, this reaction will be spontaneous
I hope it helps!
Answer;
Yes; this reaction be spontaneous if coupled with the hydrolysis of ATP.
Explanation;
The reaction converting glycerol to glycerol-3-phosphate (energetically unfavorable) can be coupled with the conversion of ATP to ADP (energetically favorable):
Glycerol + HPO42 ⟶glycerol-3-phosphate+H2O
ATP + H2O⟶ ADP + HPO42− + H+
Answers
Answer:
See the answer below
Explanation:
A neutralization reaction is a reaction that involves acid and base with the production of salt and water as the end products. An example is as below:
HCl + NaOH --> NaCl + H2O
The salt produced here is NaCl. In solution, NaCl will ionize as:
Hence, the salt's positive ion (Na+) was contributed by the base (NaOH) while its negative ion (Cl-) was contributed by the acid (HCl).
Final answer:
In a neutralization reaction involving Ba(OH)2 and HNO3, the salt's positive ion comes from the base and the negative ion comes from the acid. In the molecular and net ionic equations, spectator ions, which are unaltered in the process, are included and excluded respectively.
Explanation:
In a neutralization reaction, an acid and a base react to produce water and a salt. Taking the provided reaction of Ba(OH)2 (aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H₂O(1), the salt's positive ion (Ba²+), also known as the cation, comes from the the base, Ba(OH)2. The salt's negative ion (NO3-), also known as the anion, comes from the acid, HNO3. This reaction also represents a molecular equation where all reactants and products are represented as neutral substances. A net ionic equation would exclude the spectator ions, ions whose presence is required to maintain charge neutrality but are chemically and physically unaltered by the process.
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