use the reaction that occours when magnesium burns in oxygen to show how a reaction might be included in more than one category of reaction

Answers

Answer 1

Answer: 2Mg+O₂⇒2MgO
It can be a combustion reaction, or it can be a combination reaction

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Determine the pressure change when a constant volume of gas at 2.50 atm is heated from 30.0 °C to 40.0 °C.

Answers

Answer:

The pressure changes from 2.50 atm to 2.58 atm (an increase of approximately 0.08 atm) when the gas is heated from 30.0°C to 40.0°C.

Explanation:

As the given volume of gas is constant, we can use Gay-Lussac's law to solve this problem as it relates pressure to temperature.

Gay-Lussac's law

$\boxed{\sf (P_1)/(T_1)=(P_2)/(T_2)}$

where:

P₁ = Initial pressure
T₁ = Initial temperature (in kelvins)
P₂ = Final pressure
T₂ = Final temperature (in kelvins)

First, we need to convert the given temperatures from Celsius to Kelvin by adding 273.15:

$\implies \sf T_1=30+273.15=303.15\;K$

$\implies \sf T_2=40+273.15=313.15\;K$

Therefore, the values to substitute into the equation are:

P₁ = 2.50 atm
T₁ = 303.15 K
T₂ = 313.15 K

As we are solving for the final pressure, rearrange the equation to isolate P₂:

$\sf P_2=(P_1T_2)/(T_1)$

Substitute the values into the equation and solve forP₂:

$\implies \sf P_2=(2.50 \cdot 313.15)/(303.15)$

$\implies \sf P_2=(782.875)/(303.15)$

$\implies \sf P_2=2.58246742...$

$\implies \sf P_2=2.58\;atm\;(3\;s.f.)$

Therefore, the pressure changes from 2.50 atm to 2.58 atm (an increase of approximately 0.08 atm) when the gas is heated from 30.0°C to 40.0°C.

Silicon-30 contains 14 protons. It also contains ?

Answers

16 neutrons
Since the atomic mass (30) is equal to the number of protons + the number of neutrons
in an equation, it would be 30=14+x
x=16

Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH-] is 1 x 10-11 mol/L. Is this solution acidic, basic, or neutral? Show your work

Answers

You can use the fallowing equations:
pH=-log[H⁺]
pH=14-pOH
pOH=-log[OH⁻]
[H⁺]=K(w)/[OH⁻] (K(w)=1.01×10⁻¹⁴)

You can use any of those equation in what ever order to find the [H⁺] and then pH. If pH>7, the solution is basic. If the pH<7, the solution is acidic.

I will show you how I would find it but there is more than one way to do it.
[H⁺]=(1×10⁻¹⁴)/(10⁻¹¹)
[H⁺]=0.001M
pH=-log(0.0010)
pH=3.00
Therefore the solution is acidic.

I hope this helps. Let me know in the comments if anything is unclear.

Answer:

If we have $[H+][OH-] = Kw = 1.0 x 10^-^1^4$

Then $[H+]= Kw/ [OH-]= 1.0x 10^-^1^4/ 1 x 10^-^1^1 =1 x 10^-^3 mol/L$

$pH = - log [H+] = - log 1 x 10^-^3 = 3$ $< 7$

This is a Acidic Solution

hope this helps

give brainliest if you please

505 grams of KOH are required to completely react with 4.50 mole of sulfuric acid. How many moles of products are produced?

Answers

Answer : The moles of products $K_2SO_4$ and $H_2O$ are, 4.50 and 9 moles.

Explanation : Given,

Mass of water = 5.2 g

Molar mass of water = 18 g/mole

Molar mass of $O_2$ = 32 g/mole

The balanced chemical reaction will be,

$2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O$

First we have to calculate the moles of KOH.

$\text{Moles of }KOH=\frac{\text{Mass of }KOH}{\text{Molar mass of }KOH}$

$\text{Moles of }KOH=(505g)/(56g/mole)=9.018mole$

Now we have to calculate the limiting and excess reactant.

From the balanced reaction we conclude that

As, 1 mole of $H_2SO_4$ react with 2 mole of $KOH$

So, 4.50 moles of $H_2SO_4$ react with $4.50* 2=9$ moles of $KOH$

From this we conclude that, $KOH$ is an excess reagent because the given moles are greater than the required moles and $H_2SO_4$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of products $K_2SO_4$ and $H_2O$ .

From the balanced chemical reaction, we conclude that

As, 1 moles of $H_2SO_4$ react to give 1 moles of $K_2SO_4$

So, 4.50 moles of $H_2SO_4$ react to give 4.50 moles of $K_2SO_4$

and,

As, 1 moles of $H_2SO_4$ react to give 2 moles of $H_2O$

So, 4.50 moles of $H_2SO_4$ react to give $4.50* 2=9$ moles of $H_2O$

Therefore, the moles of products $K_2SO_4$ and $H_2O$ are, 4.50 and 9 moles.

A given sample of oxygen occupies 500 mL when the pressure is 800 mmHg. What volume will the gas occupy at 200 mmHg, provided the temperature remains constant?

Answers

Answer:

The volume of the gas at 200 mmHg will be 2 L.

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P * V = k

Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1 * V1 = P2 * V2

In this case:

P1= 800 mmHg
V1= 500 mL
P2= 200 mmHg
V2= ?

Replacing:

800 mmHg* 500 mL= 200 mmHg* V2

Solving:

$V2=(800 mmHg* 500 mL)/(200 mmHg)$

V2= 2,000 mL= 2 L (being 1,000 mL=1 L)

The volume of the gas at 200 mmHg will be 2 L.

The invisible electric force field around charged objects depends on

Answers

The invisible electric force field around charged objects depends on the amount of charge, distance involved, and shape of the objects.

What does the formation of charged object depend on ?

The formation of charged matter is depends on the transfer of electrons, either within a material or between two materials. There are three ways this can occur are known as conduction, polarization, and friction.

Charged objects surround themselves with an imperceptible electric force field. The charge, distance, and shape of the items are only a few of the factors that affect strong field.

The electric charge on the particles and the separation between them determine the strength of the electric force. Greater force is produced by larger charges.

Thus, The invisible electric force field around charged objects depends on the amount of charge, distance involved, and shape of the objects.

To learn more about charged object, follow the link;

brainly.com/question/535279

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The electric charge of the object and the medium.

The electrlc force fiel is proportional to the electric charge and the constant of proportionality depends on the media (air, water, oil, etc).

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