Which statements about velocity are true?Check all that apply.

A. The SI units of velocity are m/s.
B. For velocity, you must have a number, a unit, and a direction.
C. To calculate velocity, divide the change in the distance by time.
D. The symbol for velocity is .

Answers

Answer 1
Answer:

Answer

A. The SI units of velocity are m/s.

B. For velocity, you must have a number, a unit, and a direction.


Explanation

Velocity is the rate of change of displacement. Velocity unlike speed it is a vector quantity. This means that it has both direction and magnitude. The SI unit of displacement is metres while that of time is seconds. So, the SI units of velocity will be Metres per second. From the choices in the question the statements that are true about velocity are ;

A. The SI units of velocity are m/s.

B. For velocity, you must have a number, a unit, and a direction.

Answer 2
Answer:

Answer:

A. The SI units of velocity are m/s.

B. For velocity, you must have a number, a unit, and a direction.

C. To calculate velocity, divide the change in the distance by time.

Explanation:

A - SI units for velocity are meters per second. SI (International System) of units is the metric equivalent for units, and m/s are the standard units chosen for velocity under the SI standards.

B - Velocity is a vector, meaning it has magnitude and direction. Because velocity is essentially a speed with direction, it must have units for how fast an object is moving.

C - One method of calculating velocity is distance over time: v = Δ(d/t)

D. Not sure because I'm not seeing a variable here, but the variable for velocity is generally displayed by the letter v


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6. What makes an object float rather than sink?

Answers

An object will float in any solution rather than sink, when the density of the object is less than that of the solution in which it is floating. This statement does not mean that the object has to be lighter in weight than the fluid in which it is floating. A great example is a ship floating in water. I hope the answer helps you.

At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant acceleration 2.60 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 8.5 cm, initial velocity 5.20 cm/s, and constant zero acceleration.(a) At what time, if any, do the two cars have equal speeds?

(b) What are their speeds at that time?

(c) At what time(s), if any, do the cars pass each other? ...?

Answers

(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then 
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

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A roller coaster cart of mass m = 223 kg starts stationary at point A, where h1 = 26.8 m and a while later is at B, were h2 = 14.7 m. The acceleration of gravity is 9.8 m/s 2 . What is the speed of the cart at B, ignoring the effect of friction?

Answers

Answer:

vB = 15.4 m/s

Explanation:

Principle of conservation of energy:

Because there is no friction the mechanical energy is conserve

ΔE = 0

ΔE : mechanical energy change (J)

K : Kinetic energy (J)

U: Potential energy (J)

K = (1/2)mv²

U = m*g*h

Where :

m: mass (kg)

v : speed (m/s)

h : hight (m)

Ef - Ei = 0

(K+U)final - (K+U)initial =0

(K+U)final = (K+U)initial

((1/2)mv²+m*g*h)final = ((1/2)mv²+m*g*h)initial , We divided by m both sides of the equation:

((1/2)vB² + g*hB = (1/2 )vA²+ g*hA

(1/2) (vB)² + (9.8)*(14.7) =  0 + (9.8)(26.8 )

(1/2) (vB)² = (9.8)(26.8 ) - (9.8)*(14.7)

(vB)² = (2)(9.8)(26.8 - 14.7)

(vB)² = 237.16

v_(B) = √(237.16)

vB = 15.4 m/s : speed of the cart at B

Answer:

the guy above me is correct

Explanation:

This is heat or electrical transfer by contact.

Answers

Answer:

The correct answer for this problem is conduction.

Explanation:

I just did the test and conduction was the correct answe.

The asthenosphere is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isostatic adjustments. Which is NOT true about the role of the asthenosphere in plate tectonics?

Answers

Complete option to the question:

A. The asthenosphere is broken up into large continental- and ocean-sized plates.

B. Convection currents within the asthenosphere push magma upward to create new crust.

C. Heat from deep within Earth is thought to keep the asthenosphere malleable.

D. The asthenosphere is the repository for parts of the lithosphere that are dragged downward in subduction zones.

Answer: The correct option is A (The asthenosphere is broken up into large continental- and ocean-sized plates.)

Explanation:

Among the components that makes up the earth crust are the lithosphere and the asthenosphere.

The LITHOSPHERE is the outer layer of the earth structure which consists of the upper part of the mantle and the crust.

The ASTHENOSPHERE is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isostatic adjustments. It is denser and weaker layer of the upper mantle which permits the movement of tectonic plates in the lithosphere.

The asthenosphere is the repository for parts of the lithosphere that are dragged downward in subduction zones.Heat from deep within Earth is thought to keep the asthenosphere malleable. And the convection currents within the asthenosphere push magma upward to create new crust. But it is not broken up into large continental- and ocean-sized plates.

1. What is meant by half-life?The time for a radioactive sample to reduce to half of its radioactivity.
The time for half of a radioactive sample to decay into new substances.
The time for a radioactive sample to reduce to half of its original mass.
The time for half of a radioactive sample to lose its radioactivity.

4. The isotope uranium-232 has a half-life of 68.9 years. How long will it take for 60% (N/N0 = 0.60) of the original sample to decay?

5.8 years
50.8 years
93.5 years
407 years

5. The isotope barium-133 has a half-life of 10.51 years. Of a 10 kg sample, how much will remain after 50 years?

0.37kg
4.53kg
8.64kg
270kg
6. A piece of bone from a horse found in an archaeological site is dated using carbon-14 dating. It is found that the bone has 78% of the carbon-14 that it would have when the horse was alive. Approximately how long ago did the horse die?

900 years ago
2,000 years ago
14,100 years ago
35,800 years ago
7. At an physics research facility 0.0027 kg of a new isotope is made in an atomic collider. After 6 seconds, 0.00147 kg remain. What is the half-life of the isotope?

0.25 seconds
5.26 seconds
6.84 seconds
500 seconds

Answers

1. The time for a radioactive sample to reduce to half of its original mass.
4. 10% of 232 is 23.2 times 6 equals 139.2
68.9 x6 equals 413.4
5. 0.37kg
6. 2000 years
7. 6.84 seconds