What is –15 ÷3/5 ?

A.–25

B.–9

C. -1/9

D. -1/25

Answers

Answer 1
Answer: -15 is equivalent to -15/1  Now use keep change flip.  -15/1*5/3
-15*5=-75
3*1=3
-75/3=-25 simplified
A is the answer


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There are 48 students in a school play. The ratio of boys to girls is 5:7. How many boys are in the school play? Explain how you found your answer
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(5,?) is on the line below. Find the other half of the coordinate.
y = 2/3x + 7

Answers

We need to plug 5 in place of x into the equation of the line and find the y-value.

y = (2/3)x + 7

y = (2/3)5 + 7

y = 10/3 + 7

y = 10/3 + 21/3

y = 31/3

y = 10 1/3

The point is (5, 10 1/3) OR (5, 31/3).
(x,y) = (5, ?), so x = 5. Substitute 5 into the function for x to find the value of y when x = 5. y = 2/3 (5) + 7 = (2 x 5) / 3 + 7 = 10/3 + 7 = 10/3 + 21/3 = 31/3, which equals 10 1/3 or 10.3 repeating.

What survival rate in the 10th year would make the average rate of loss over the 10-year period equal to 38.0%?

Answers

Answer: 63%

Step-by-step explanation:

First find the rate of loss that would cause the average rate of loss over the 10-year period equal to 38.0%.

Assume that rate is x.

38 = (36.2 + 29.0 + 46.2 + 37.5 + 40.9 + 40.0 + 32.6 + 40.5 + 40.1 + x) / 10

38 = (343 + x ) / 10

380 = 343 + x

x = 380 - 343

x = 37%

The survival rate is the opposite of the rate of loss which means that the survival rate is;

= 1 - rate of loss

= 1 - 37%

= 63%

I HAVE ASKED THIS QUESTION LIKE 8 TIMES TODAY AND NO ONE WILL HELP ME:( PLEASE HELP ME I BEG YOU GUYS!!!A radioactive substance decays at a rate of 2% per day. If there are 50 grams of the
substance left after 34 days, how much was there at the beginning of the 34 days?
Round to two decimal places.

Answers

Answer:

156.25 grams

Step-by-step explanation:

Well, for starters we know that the substance decays by 2% each day and its been decaying for 34 days. Therefore, the substance has decayed by 68%        

34 x 2 = 68

Hence, 50 grams is 32% because the substance has already decayed by 68%

100 - 68 = 32

So now we know 50 grams is 32%. Now we need to find how much 100% is.

50 - 32%

X   - 100%

We cross multiply.

50 x 100 = 5000

And divide.

5000 / 32 = 156.25

Thus, in the beginning, there were 156.25 grams in the substance.

Hope this helps! :)

How many ft is in 96 inch

Answers

Good evening,

96 inch=96*1/12 feet=96/12 feet=8 feet

Use substitution to solve the
following system of equations.
-3x + 2y = 5 AND x = 2y - 3

Answers

Step-by-step explanation:

everything can be found in the picture

Some the system of equationsY=2x^2 - 3
Y=3x - 1

How many real number solutions are there to the equation 0=3x^2 + x - 4?

What are the solutions of the system
Y=x + 5
Y=x^2 - x + 2

Answers

y = 2x² - 3
y = 3x - 1

                             2x² - 3 = 3x - 1
                                  + 1        + 1
                             2x² - 2 = 3x
                      2x² - 3x - 2 = 0
                2x² - 4x + x - 2 = 0
2x(x) - 2x(2) + 1(x) - 1(2) = 0
          2x(x - 2) + 1(x - 2) = 0
                 (2x + 1)(x - 2) = 0
     2x + 1 = 0    or    x - 2 = 0
           - 1 - 1              + 2 + 2
           2x = -1      or      x = 2
            2     2
             x = -0.5

      y = 3x - 1            or           y = 3x - 1
      y = 3(-0.5) - 1        or        y = 3(2) - 1
      y = -1.5 - 1          or          y = 6 - 1
      y = -2.5            or             y = 5
(x, y) = (-0.5, -2.5)    or    (x, y) = (2, 5)
————————————————————————————————
                       3x² + x - 4 = 0
              3x² - 6x + 2x - 4 = 0
3x(x) - 3x(2) + 2(x) - 2(2) = 0
           3x(x - 2) + 2(x - 2) = 0
                  (3x + 2)(x - 2) = 0
      3x + 2 = 0    or    x - 2 = 0
            - 2  - 2             + 2 + 2
            3x = -2      or      x = 2
             3      3
              x = ⁻²/₃
There are two real number solutions in the equation.
————————————————————————————————
y = x + 5
y = x² - x + 2

   x + 5 = x² - x + 2
+ x             + x
 2x + 5 = x² + 2
       - 2         - 2
 2x + 3 = x²
         0 = x² - 2x - 3
         0 = x² - 3x + x - 3
         0 = x(x) - x(3) + 1(x) - 1(3)
         0 = x(x - 3) + 1(x - 3)
         0 = (x + 1)(x - 3)
         0 = x + 1    or    0 = x - 3
       - 1       - 1         + 3      + 3
        -1 = x       or       x = 3

      y = x + 5        or        y = x + 5
      y = -1 + 5        or       y = 3 + 5
      y = 4           or           y = 8
(x, y) = (-1, 4)    or    (x, y) = (3, 8)