What is the total mass (amu) of carbon in each of the following molecules?(a)CH4
(b)CHCL3
(c)C12H10O16
(d)CH3CH2CH2CH2CH3

Answers

Answer 1

Answer:

The mass of carbon in $\rm CH_4$ is 12.007 amu, $\rm CHCl_3$ is 12.007, $\rm C_1_2H_1_0O_1_6$ is 144.084 amu, and $\rm CH_3CH_2CH_2CH_2CH_3$ is 60.035 amu.

What is the mass of one Carbon atom?

The mass has been given as the sum of the atomic mass unit in the compound. The mass of 1 atom of carbon is 12.007 amu.

The mass of carbon in the following compounds is given as:

$\rm CH_4$

The number of Carbon units = 1

The mass of carbon in compound = 12.007 amu

$\rm CHCl_3$

The number of Carbon units = 1

The mass of carbon in the compound = 12.007 amu

$\rm C_1_2H_1_0O_1_6$

The number of carbon units =12

The mass of carbon in the compound:

$\rm 12\;*\;12.007\;amu\n=144.084\;amu$

$\rm CH_3CH_2CH_2CH_2CH_3$

The number of carbon units = 5

The mass of carbon in the compound:

$\rm 5\;*\;12.007\;amu\n=60.035\;amu$

Learn more about the mass of an atom, here:

brainly.com/question/5566317

Answer 2

Answer:

Answer:

The atomic mass of carbon (C) is 12.0107 amu, so if you want to calculate the total mass in each molecule, you just need to multiply the number of carbon atoms in the substance by 12.017. In (a) there is one atom of C, (b) have also one atom of C, (c) have 12 atoms of C, and (d) have five atoms of C. Thus, the total mass (amu) of carbon is:

(a) 12.017 amu

(b) 12.017 amu

(d) 60.085 amu

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A sample of solid calcium hdroxide, Ca(OH)2 is allowed to stand in water until a saturated solution is formed. A titration of 75.00mL of this solution with 5.00 x 10-2 M HCl 36.6 mL of the acid to reach the end pointCa(OH)2 + 2HCl ? CaCl + 2H2O
What is the molarity?

Answers

Answer: The concentration of $Ca(OH)_2$ is 0.0122 M.

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\nM_1=5.00* 10^(-2)M=0.05M\nV_1=36.6mL\nn_2=2\nM_2=?M\nV_2=75mL$

Putting values in above equation, we get:

$1* 0.05* 36.6=2* M_2* 75\n\nM_2=0.0122M$

Hence, the concentration of $Ca(OH)_2$ is 0.0122 M.

Please help with this

Answers

Answer:

Explanation:

Light refracts when it passes through something transparent at an angle so that eliminates the other 3.

or put differently

Light refracts whenever it travels at an angle into a substance with a different refractive index (optical density)

A solution of salt and water is 33.0% salt by mass and has a density of 1.50 g/ml. what mass of the salt in grams is in 5.00l of this solution?

Answers

To answer this item, we solve first for the mass of the solution by multiplying the density by the volume. That is,

m = (density)(volume)

Substituting the known values,
m = (1.50 g/mL)(5L)(1000 mL/1L)
m = 7500 grams

To determine the mass of the salt in the solution, multiply the calculated mass of the solution by the decimal equivalent of the percent salt in the solution.

m of salt = (7500 g)(0.33)
m of salt = 2475 grams

Answer: 2475 grams

When a liquid sample is taken from sea level to a higher elevation, what happens to the external (atmospheric) pressure on the liquid and the boiling point of the liquid

Answers

Answer:

The external atmospheric pressure decreases and so does the boiling point of the liquid.

Explanation:

We know that pressure decreases with height. Thus atmospheric pressure decreases at higher elevation.

The implication of this is that, if I take a liquid from sea level to a higher elevation, the external atmospheric pressure on the liquid will decrease and so does its boiling point.

Hence, the liquid boils at a lower temperature when placed at a higher elevation. For this reason, the boiling point of a liquid is lower on the mountain.

ΔH is always positive for a ...........a. endothermic reaction
b. exothermic reaction
c. spontaneous reaction.
d. nonspontaneous reaction.

Answers

Answer:

a. endothermic reaction

Explanation:

In an endothermic reaction, heat is absorbed from the environment. This leaves the surrounding at a colder temperature compared to the system.

ΔH, the change in enthalpy is assigned a positive sign because the heat energy level of the final state is higher than that of the initial state.

Some examples are mostly dissolution substances in water.

What data should be plotted to show that experimental concentration data fits a first-order reaction? A) 1/[reactant] vs. time B) [reactant) vs. time C) In[reactant] vs. time D) In(k) vs. 1/1

Answers

The data that should be plotted to show that experimental concentration data fits a first-order reaction is: C. In [reactant] vs. time.

What is a first-order reaction?

A first-order reaction can be defined as a type of chemical reaction in which the reaction rate (rate of reaction) is directly proportional to the concentration of the reacting chemical substance or elements.

Mathematically, the integrated rate law equation for a first-order reaction is given by this formula:

$A=A_o e^(kt)$

Where:

A is the concentration after time (t).

$A_o$ is the initial concentration of the reactant.

t is the time.

k is the rate constant.

Taking the ln of both sides, we have:

$ln(A)=ln(A_o)-kt$

Therefore, the data that should be plotted to show that experimental concentration data fits a first-order reaction is In[reactant] versus time.

Read more on rate constant here: brainly.com/question/24749252

Answer:

C) In[reactant] vs. time

Explanation:

For a first order reaction the integrated rate law equation is:

$A = A_(0)e^(-kt)$