What volume of 0.335 molar hydrochloricacid solution would be required to neutral-
ize completely 39 mL of 0.137 molar sodium
hydroxide solution?
Answer in units of mL.

Answers

Answer 1
Answer:

The volume of 0.335 molar hydrochloric acid solution would be required to neutralize completely 39 mL of 0.137 molar sodium hydroxide solution is 15.95mL.

How to calculate volume?

The volume of a substance in a neutralization reaction can be calculated using the following formula;

CaVa = CbVb

Where;

  • Ca = concentration of acid
  • Va = volume of acid
  • Cb = concentration of base
  • Vb = volume of base

According to this question, 0.335 molar hydrochloric acid solution would be required to neutralize completely 39 mL of 0.137 molar sodium hydroxide solution.

0.335 × Va = 39 × 0.137

0.335Va = 5.343

Va = 15.95mL

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In the nuclear transmutation represented by 168o(p, \alpha) 137n, the emitted particle is ________.
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At this location, it is summer in the Northern Hemisphere because the North Pole is tiltedAway from the sun Towards the sun

Adding charts and graphs helps a scientistO To state the problem
O To determine trends
O To simplify results
O Both B and C
O All of the above

Answers

Answer:

b and c

Explanation:

the problem was solved through the experiment and tested

Adding charts and graphs helps a scientist to determine trends and to simplify results

of all the hydrogen nuclei in the ocean, 0.0156 how much deuterium could be obtained from 1.0 gal of ordinary tap water

Answers

Answer:

Poop Butt.

Explanation: Poop Butt.

3. Theoretically how many grams of magnesium is required to produce to 5.0 g ofMagnesium oxide?

Answers

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2  → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

Final answer:

To produce 5 grams of magnesium oxide, you would theoretically need approximately 3.013 grams of magnesium, based on the mole ratio and molecular weights of magnesium and magnesium oxide.

Explanation:

To calculate the amount of magnesium needed to produce magnesium oxide, we first need to understand the balanced chemical equation for the reaction: Mg + 1/2O2 → MgO. This equation shows that a mole of magnesium (24.31 g) reacts with half a mole of oxygen (8 g) to produce a mole of magnesium oxide (40.31 g). Therefore, if we want to produce 5g of magnesium oxide, we'll need: (5 g MgO * 24.31 g Mg) / 40.31 g MgO = 3.013 g Mg, approximately which is the theoretical amount of magnesium needed.

Learn more about Theoretical Amount of Magnesium here:

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15.2 grams of CO2 = ? molecules of CO2

Answers

Answer:

2.11 molecules of CO₂

Explanation:

Given data:

Mass of CO₂ = 15.2 g

Molecules of CO₂ = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 15.2 g/ 44 g/mol

Number of moles = 0.35 mol

Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.35 mol × 6.022 × 10²³ molecules / 1 mol

2.11 molecules of CO₂

What is the toto number of neutrons in an atom of 73 li

Answers

The 73 in Li means that there are 73 protons and neutrons in this atom. To find the number of neutrons, simply subtract the number of protons, which is equal to the atomic number (which is 3 in this case).

70 neutrons.

When a polar bond is formed between 2 atoms which atom receives a partial positive charge

Answers

Answer:

The less electronegative atom

Explanation:

Water contains polar bonds. Water is made up of oxygen and hydrogen. Oxygen is more electronegative then hydrogen so it is partial negative (because electron spend more time around oxygen in the polar bond), whereas, hydrogen has a  partial positive charge as it is less electronegative (electrons spend less time around hydrogen in this polar bond).