The bond angles in each of the compounds are determined by their electron-pair geometry and molecular structure.
The correct values for the indicated bond angles in each of the given compounds are:
Bond angles are determined by the electron-pair geometry and molecular structure of a compound. The given values correspond to these geometries and structures.
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The bond angles are determined by their molecular structures - SO2 is 120°, BF3 is 180°, SCl2 is 120°, CO2 is 180°, PF3 is slightly less than 109.5°, and CH4 is 109.5°.
The bond angles in various compounds are determined by the molecule's electron-pair geometry and molecular structure. For the SO2 compound, O-S-O angle corresponds to a bent molecular structure with a bond angle of 120° (electron-pair geometry: trigonal planar). The F-B-F angle in BF3 has a linear molecular structure that leads to a bond angle of 180° (electron-pair geometry: linear). In SCl2, the Cl-S-Cl angle is 120° due to its bent structure (electron-pair geometry: trigonal planar). For CO2, the O-C-O angle is 180° because of its linear structure (electron-pair geometry: linear). In PF3, the F-P-F angle is slightly less than 109.5° because of its trigonal pyramidal structure (electron-pair geometry: tetrahedral). Finally, in CH4, the H-C-H is 109.5° as it has a tetrahedral structure (electron-pair geometry: tetrahedral).
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Answer:
D. CH₃CH₂C(CH₃)₂C≡CCH(CH₃)₂
Explanation:
You start numbering from the end closest to the triple bond (on the right). The triple bond is between C3 and C4, and there is one methyl group on C3 and two on C5.
A. CH₃CH₂CH(CH₃)C≡CCH₂CH(CH₃)₂ is wrong. The longest chain has eight C atoms, so the compound is an octyne.
B. CH₃CH₂CH(CH₃)C≡CC(CH₃)₃ is wrong. This is a molecule of 2,2,5-trimethylhept-3-yne.
C. (CH₃CH₂)₂C≡CCH₂CH₃ is wrong. This is a molecule of 6-ethyl-5-methylhept-3-yne.
E. CH₃CH₂CH₂CH(CH₃)C≡CC(CH₃)₃ is wrong. The longest chain has eight C atoms, so the compound is an octyne.
Answer: Hey Brother by Avicii
b. 72.8 g c2h6o in 2.34 l of solution
c. 12.87 mg ki in 112.4 ml of solution
The molarities of the given solutions: (a). 0.38 mol of LiNO₃ in 6.14 L of solution has a molarity of 0.062 M. (b). 72.8 g of C₂H₆O in 2.34 L of solution has a molarity of 0.675 M. (c). 12.87 mg of KI in 112.4 mL of solution has a molarity of 0.000688 M.
To calculate the molarity (M) of a solution, you can use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
a. 0.38 moles of LiNO₃ in 6.14 L of solution:
Molarity (M) = 0.38 moles / 6.14 L = 0.062 M
b. 72.8 grams of C₂H₆O (ethyl alcohol) in 2.34 L of solution:
First, you need to convert grams to moles using the molar mass of C₂H₆O.
Molar mass of C₂H₆O = 2(12.01 g/mol) + 6(1.01 g/mol) + 1(16.00 g/mol) = 46.08 g/mol
Now, calculate moles of C₂H₆O:
moles = 72.8 g / 46.08 g/mol = 1.58 moles
Molarity (M) = 1.58 moles / 2.34 L = 0.675 M
c. 12.87 mg of KI in 112.4 mL of solution:
First, convert milligrams to grams (1 g = 1000 mg):
12.87 mg = 12.87 g (since 12.87 mg / 1000 = 0.01287 g)
Now, convert mL to liters (1 L = 1000 mL):
112.4 mL = 0.1124 L
Calculate moles of KI:
Molar mass of KI = 39.10 g/mol (for K) + 126.90 g/mol (for I) = 166.00 g/mol
moles = 0.01287 g / 166.00 g/mol = 7.75 × 10⁻⁵ moles
Molarity (M) = (7.75 × 10⁻⁵ moles) / 0.1124 L = 0.000688 M
So, the molarities of the solutions are as follows:
a. 0.062 M
b. 0.675 M
c. 0.000688 M
To know more about moles:
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SpongeBob
SpongeBob
Patrick
Patrick
Larry
In the experiment, SpongeBob is the control group because regular lotion is used instead of the muscle cream. This allows a comparison with Patrick(rightly known as the experimental group) who uses the special muscle cream.
In the given scenario, SpongeBob represents the control group. In any experiment, the control group is the one that is kept normal or unchanged to be able to compare the effects of the variable being tested. In this case, it's the use of the special muscle cream. Patrick, whose arms and back are lathered with the muscle cream before each session, represents the experimental group because he is exposed to the variable being tested, which is the muscle cream. On the other hand, SpongeBob, who is given regular lotion instead of the special muscle cream, is part of the control group because he helps to provide a baseline for comparison.
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Answer:
It is a heterogeneous mixture
Explanation:
A mixture is a substance that is formed by several components (two or more), which do not lose their properties and characteristics due to the mixing because there is no chemical reaction between them.
Homogeneous mixtures: Those mixtures whose components cannot be distinguished with the naked eye. The homogeneous mixtures of liquids are known as solutions and consist of a solute and a solvent, the first being the one in smaller proportion and also usually the liquid. For example, water mixed with mineral salts or sugar, water would be the solvent and sugar the solute.
Heterogeneous Mixtures: A heterogeneous mixture is one that has a non-uniform composition in which its components can be distinguished with the naked eye and is formed by two or more substances, physically different, unevenly distributed. The parts of a heterogeneous mixture can be separated mechanically. For example, water and sand, water and sludge, water and oil
Answer:
The glass cup falling from the counter
Explanation:
the glass isn't changing in any chemical way. it's still made of the same material, just broken apart.
Physical changes involve the alteration of the state or appearance of matter, without changing the composition. An example is solid wax turning into liquid wax when heated, or steam condensing inside a cooking pot.
The question asks for an example of a physical change. Physical changes involve alterations in the state or appearance of matter, without changing its composition. For example, solid wax turning into liquid wax when heated is a physical change. The wax is still the same substance, it's just in a different state. Similarly, steam condensing inside a cooking pot is also a physical change. The water vapor turns back into liquid water, but it's still water. These are distinguished from chemical changes, which transform one substance into a different substance.
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