Which of the following is not a reason why chemical bonds are important

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Answer 1
Answer: What are the followings?

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When 282 gr of glycine are dissolved in 950 gr of a certain mystery liquid, the freezing point of the solution is 8.2 C less than the freezing point of pure. Calculate the mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point. The van't Hoff factor for iron(III) chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Answers

Answer: 1.4* 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i* K_f* m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like glycine)

K_f = freezing point constant = ?

m= molality

\Delta T_f=i* K_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}

Weight of solvent = 950 g = 0.95 kg

Molar mass of glycine = 75.07 g/mol

Mass of glycine added = 282 g

8.2=1* K_f* (282g)/(75.07 g/mol* 0.95kg)

K_f=2.2^0C/m

Thus freezing point constant is 2.2^0C/m

2) \Delta T_f=i* K_f* m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

i= vant hoff factor = 4 (for FeCl_3)

K_f = freezing point constant = 2.2C/m

m= molality  

\Delta T_f=i* K_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}

Weight of solvent = 950 g = 0.95 kg

Molar mass of FeCl_3 = 162.2 g/mol

Mass of  FeCl_3 added = ?

8.2=4* 2.2* (xg)/(162.2 g/mol* 0.95kg)

x=1.4* 10^2g

Thus mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point is 1.4* 10^2g

Answer:

mass_(FeCl_3)=1.5x10^2gFeCl_3

Explanation:

Hello,

In this case, by using the given data for glycine, one computes the freezing point constant of the mystery liquid as shown below, considering the molality of the glycine and its van't Hoff factor equal to the unity:

\Delta T=i*Kf*m_(Glyc)\n\nKf=(\Delta T)/(i*m_(glyc)) =(8.2^oC)/(1*(282gGlyc)/(950gX)*(1molGlyc)/(75.07gGlyc)*(1000gX)/(1kgX) ) \n\nKf=2.1^oC/m

Now, as we are looking for the mass of iron(III) chloride at the same conditions of the aforesaid case, at first, one solves for the molarity of such compound considering that its theoretical van't Hoff factor is 4 as follows:

m_(FeCl_3)=(\Delta T)/(i*Kf) =(8.2^oC)/(4*2.1^oC/m_(FeCl_3)) =0.98m

Now, one obtains the requested mass via:

mass_(FeCl_3)=0.98(molFeCl_3)/(kgX)*0.95kgX*(162.35gFeCl_3)/(1molFeCl_3)  \n\nmass_(FeCl_3)=151.1gFeCl_3\nmass_(FeCl_3)=1.5x10^2gFeCl_3

Best regards.

Estimate how much heat in joules is released when 25.0 g of water (C = 4.184 J/g°C) is cooled from 80.0°C to 30.0°C?

Answers

The amount of heat will be 5230 j.

What is heat?

Heat is a type of energy that is transferred between both the system and its surroundings as a result of temperature variations.

Calculation of heat.

Given data:

Mass = 25.0 g = 0.025 kg

C = 4.184 J/g°C

T_(1) =  80.0°C

T_(2) = 30.0°C

Q= ?

By using the formula of heat.

Q = MC (T_(2) - T_(1))

Put the value of given data in heat equation.

Q(heat)  = 0.025  × 4.184  ( 30 - 80)

Q(heat) = 5230 J.

Therefore, the amount of heat will be 5230 J.

To know more about heat.

brainly.com/question/13860901.

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Answer:

5230 J

Explanation:

m = 25 g = 0,025 kg

c = 4,184 J /(g * °C) = 4184 J /(kg * °C)

t_(1) = 80 °C

t_(2) = 30 °C

The formula is Q = c *m * (t_(2) - t_(1))

Calculating:

Q = 4184 * 0,025 * (30 - 80) = 5230 J

Note that we get a negative heat (-5230 J). It just means that it is released.

What is the hydrogen concentration of a pH of 6.95, 7.25 and 8.1?

Answers

Explanation:

pH is use calculate the acidic strength of a substance ,

The value of pH is calculated as , negative log of the concentration of Hydrogen ions .

Therefore ,

pH = - log [ H ⁺]

rearranging the above equation , to find the hydrogen ion concentration .  log [ H ⁺] = pH

log [ H ⁺] = - pH

[ H ⁺] =  antilog ( - pH )

Hence , from the question , the hydrogen ions can be calculated by using the above equation ,

( 1 )

pH = 6.95

Since ,

[ H ⁺] =  antilog ( - pH )

[ H ⁺] = antilog ( - 6.95 )

[ H ⁺] = 1.12 * 10 ⁻⁷  

( 2 )

pH = 7.25

Since ,

[ H ⁺] =  antilog ( - pH )

[ H ⁺] = antilog ( - 7.25 )

[ H ⁺] = 5.62 * 10 ⁻⁸

( 3 )

pH = 8.1

Since ,

[ H ⁺] =  antilog ( - pH )

[ H ⁺] = antilog ( - 8.1 )

[ H ⁺] = 7.94 * 10 ⁻⁹  

The osmotic pressure, π, of a solution of glucose is 132 atm . find the molarity of the solution at 298 k.

Answers

The formula for osmotic pressure is:

\Pi = iMRT

where \Pi is osmotic pressure, i is van't Hoff's factor, M molarity, R is Ideal gas constant, and T is Temperature.

\Pi = 132 atm

The van't Hoff's factor for glucose, i = 1

R = 0.08206 Latmmol^(-1)K^(-1)

T = 298 K

Substituting the values in the above equation we get,

132 atm = 1* M* 0.08206 Latmmol^(-1)K^(-1)* 298

M = (132 atm)/(1* 0.08206 Latmmol^(-1)K^(-1)* 298) = 5.4797 molL^(-1) \simeq 5.48 molL^(-1)

So, the molarity of the solution is 5.48 molL^(-1).

1. What is the angular distance north or south from the earth's equator beginning at0° at the equator and ending at 90° at either pole?
a. Weather
b. Altitude
c. Latitude
d. Climate

Answers

Answer:

c. Latitude

Explanation:

The angular distance north or south from the earth's equator beginning at 0° at the equator and ending at 90° of either pole is the latitude.

The equator is a line of latitude that divided the earth into two hemispheres.

Only the equator is a great circle as a line of latitude. Others are small circles.

  • Weather is the atmospheric condition of a place over a short period of time
  • Climate is the average weather condition at a place over a long period of time.
  • Altitude of a place is its elevation above a reference plane.

What have you observed when you fill in a basin with water? how do you do it?​

Answers

When you fill a basin with liquid water, you can see that the water takes the shape of the container in which it is contained. This is because in the liquid state, water has molecules farther apart than in the solid state.

You can notice this property when performing an experiment with liquid and solid water.

When filling a glass, liquid water takes on the shape of a glass, and solid water, such as an ice cube, remains the same shape when placed in a glass.

Therefore, when filling a basin with water we perceive a property of the physicalstate of water, in liquid form. Water is one of the few substances that can be found naturally in liquid, solid and gaseous states.

Learn more here:

brainly.com/question/23650420

Answer:

Cautiously and avoiding filling in the central area so that it does not overflow when filling, since being very beach makes filling difficult.

Explanation:

The basins are shallow, that is why filling is difficult, the filling must be slow, low intensity and at the edges not placing the water filling in the center of the basin.