Predict the product when 2-methylbutanol is oxidised with pyridium chlorochromate in dichloromethane (PCC/CH2C12) a. CH3CH2CH(CH3)COOH b. CH3CH2CH2CH(CH3)CHO C. CH3CH2CH(CH3)CHO d. CH3CH2CH(CH3)OH 8:40 PM Type a message​

Answers

Answer 1
Answer:

Answer:

c. CH3CH2CH(CH3)CHO

Explanation:

Hello there!

In this case, according to the process for the one-step oxidation of a primary alcohol with a moderately strong oxidizing agent like pyridinium chlorochromate (PCC), whereby an aldehyde is produced, we infer that the corresponding product will be 2-methylbutanal, which matches with the choice c. CH3CH2CH(CH3)CHO according to the following reaction:

CH_3CH_2CH(CH_3)CH_2OH\rightarrow CH_3CH_2CH(CH_3)COH

Regards!


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The information below describes a redox reaction.Cr3+(aq)+2Cl-(aq)---->Cr(s)+Cl2(s)
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What is the final, balanced equation for this reaction?
1.) 2cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g)
2.) 2Cr3(aq)+2Cl-(aq)+6e- --->Cl2(g)+2Cr(s)
3.) Cr3+(aq)+6Cl-(aq)+3e- ---->2Cr(g)+3Cl2(g)
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Answers

Answer: option 1)  2Cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g)

Explanation:

1) Write the oxidation half-reaction:

2Cl^-(aq)---\ \textgreater \ Cl_2(g)+2e^-

2) Write the reduction half-raction:

Cr^(3+)(aq)+3e^(-)---\ \textgreater \ Cr(s)

3) Multiply each half-reaction by the appropiate coefficient to equal the number of electrons of both half-reactions.

6Cl^(-)(aq)---\ \textgreater \ 3Cl_2(g)+6e^(-) 2Cr^(3+)(aq)+6e^(-)---\ \textgreater \ 2Cr(s)

4) Add both half-reactions

2Cr^(3+)+6Cl^(-)(aq)---\ \textgreater \ 2Cr(s) +3Cl_2(g)

And that is the answer. You can count the atoms and charges on every side and check they are equal.

Answer:

A

Explanation:

got it correct on edge

Draw a line-bond structure for CBrN. Explicitly draw all H atoms. You do not have to include lone pairs in your answer. In cases where there is more than one answer, just draw one.

Answers

Answer:

Br - C ≡ N

Explanation:

To draw the Lewis line-bond structure we need to bear in mind the octet rule, which states that in order to gain stability each atom tends to share electrons until it has 8 electrons in its valence shell.

  • C has 4 e⁻ in its valence shell so it will form 4 covalent bonds.
  • Br has 7 e⁻ in its valence shell so it will form 1 covalent bond.
  • N has 5 e⁻ in its valence shell so it will form 3 covalent bonds.

The most stable structure that respects these premises is:

Br - C ≡ N

It does not have any H atom.

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Explanation:

Answer:

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Explanation:

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Answers

Answer

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Answers

Answer:

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