Aqueous solutions of barium chloride and silver nitrate are mixed to form solid silver chloride and aqueous barium nitrate. The complete ionic equation contains which of the following species (when balanced in standard form)? A. NO (aq)
B. 2Ba (aq)
C. 2Ag (aq)
D. CI(aq)

Answers

Answer 1
Answer:

Answer:

Option C

Explanation:

Consider the ionic equation of this chemical equation. We are given barium chloride and silver nitrate as the reactants, and silver chloride and barium nitrate as the products. We can thus conclude that the ionic equation ( not balanced yet ) should be as follows -

Ba( 2 + ) + Cl ( - ) + Ag ( + ) + NO3 ( - ) ------> AgCl + Ba( 2 + ) + NO3( - )

As you can see these compounds are present in aqueous solutions, and are thus dissociated.

______________________________________________________

Now let us take a look at the number of elements on the reactant and product sides, and balance this chemical equation out -

Ba( 2 + ) + 2Cl ( - ) + 2Ag ( + ) + 2NO3 ( - ) ------> 2AgCl + Ba( 2 + ) + 2NO3( - )

Solution = Option C!


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What is impossible for a machine to do?A. do a greater amount of work than the amount of work done on the machine
B. apply a force in a direction that is different than the direction of the force applied to the machine
C. move an object a greater distance than the distance that part of the machine was moved
D. apply a force that is less than the force that is applied to the machine

Answers

Answer:

C

Explanation:

move an object a greater distance than the distance that part of the machine was moved

Answer:

a, sorry for late answer!!

Explanation:

What is the purpose of a catalyst?O A. To change the potential energy of the reactants
O B. To lower the activation energy of a reaction
O C. To increase the kinetic energy of the reactants
O D. To shift the equilibrium position of a reaction

Answers

B. To lower the activation energy of a reaction

Answer:

To lower the activation energy of a reaction

Explanation:

i just took the test and got it right ...... i hope this helps :)

Fatty acids are carboxylic acids with a long, unbranched hydrocarbon chain. There are three main classes of fatty acids. Classify the fatty acids as saturated, monounsaturated, or polyunsaturated.

Answers

Answer:

Coconut oil, Olive oil and Sunflower oil

Explanation:

Fatty acids are carboxylic acids with a long unbranched chain of carbon and hydrogen atoms.

There are three main classes of fatty acids which are explained as under:

1. Saturated Fatty acids: These fatty acids have long carbon chain with two hydrogen atoms bonded to each carbon atom. This saturation of fatty acids make the fatty acids more stable towards high temperature. These fatty acids becomes solid at room temperature. Coconut oil and butter are the examples of saturated fatty acids.

2. Monounsaturated Fatty Acids: In a long carbon chain, if there is a carbon atom which is double bonded with another carbon atom and rest is saturated with hydrogen atoms, because of this single double-bond, the fatty acid is termed as monounsaturated fatty acids. These fatty acids are liquid at room temperature but solidify in refrigerator. Olive oil is an example of such fatty acids.

3. Polyunsaturated Fatty Acids: In a long carbon chain, if there are two or more than two carbon atoms which are double bonded with each other and rest is saturated with hydrogen atoms, because of multiple double bonds, such fatty acids are termed as polyunsaturated fatty acids. Because of higher unsaturation, these fatty acids are liquid in both normal room temperature and in refrigerator. Such unsaturation also make them unfit for cooking purposes. Sunflower oil, Soyabean oil and Flaxseed oil are examples of polyunsaturated fatty acids.

lucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.200 mM. i) What is the concentration of glucose in the E. coli cell in mg/mL?

Answers

Answer:

The concentration is 0.036 mg/mL

Explanation:

Concentration = 0.2 mM = 0.2/1000 = 2×10^-4 M = 2×10^-4 mol/L × 180,000 mg/1 mol × 1 L/1000 mL = 0.036 mg/mL

38. Consider the following equilibrium:2CO(g) + O2(g) =2CO2
Keg=4.0 x 10-10
What is the value of Key for 2CO2(g) + 2COR + O2g) ?​

Answers

Answer:

Key=2.5x10^(-9)

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)

By knowing that the equilibrium expression is actually:

Key =([CO]^2[O_2])/([CO_2]^2) =(1)/(Keg)

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

Key =(1)/(4.0x10^(-10))\n\nKey=2.5x10^(-9)

Regards!

If a student weighs out 0.744 g Fe ( NO 3 ) 3 ⋅ 9 H 2 O , what is the final concentration of the ∼0.2 M Fe ( NO 3 ) 3 solution that the student makes?

Answers

Answer:

Molar concentration of Fe(NO3)3 . 9H2O = 0.12M

Explanation:

Fe(NO3).9H2O --> Fe(NO3)3 + 9H2O

By stoichiometry,

1 mole of Fe(NO3)3 will be absorb water to form 1 mole of Fe(NO3)3 . 9H2O

Therefore, calculating the mass concentration of Fe(NO3)3;

Molar mass of Fe(NO3)3 = 56 + 3*(14 + (16*3))

= 242 g/mol

Mass concentration of Fe(NO3)3 = molar mass * molar concentration

= 242 * 0.2

= 48.4 g/L

Molar mass of Fe(NO3)3 . 9H2O = 56 + 3*(14 + (16*3)) + 9* ((1*2) + 16)

= 242 + 162 g/mol

= 404g/mol

Concentration of Fe(NO3)3 . 9H2O = mass concentration/molar mass

= 48.4 /404

= 0.12 mol/l

Molar concentration of Fe(NO3)3 . 9H2O = 0.12M