CHEMISTRY COLLEGE

A 25.0mL solution acetic acid (CH3CO2H) is titrated with 0.20M NaOH and reaches the endpoint after the addition of 16.3mL of NaOH. What is the concentration of acetic acid in solution

Answers

Answer 1

Answer:

Answer: 0.1304M

Explanation: Please see the attachments below

Answer 2

Answer:

Final answer:

The concentration of acetic acid in the solution is 0.1304 M.

Explanation:

To determine the concentration of acetic acid in solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between acetic acid and sodium hydroxide. The balanced equation is:

CH3CO2H + NaOH -> CH3CO2Na + H2O

From the balanced equation, we can see that 1 mole of acetic acid reacts with 1 mole of sodium hydroxide. In order to calculate the moles of acetic acid, multiply the volume of NaOH used (16.3 mL) by the molarity of NaOH (0.20 M), then divide the result by 1000 to convert mL to L:

Moles of acetic acid = (16.3 mL NaOH x 0.20 M NaOH) / 1000 = 0.00326 moles

Now, to calculate the concentration of acetic acid in the solution, we divide the moles of acetic acid by the volume of the solution in litres:

Concentration of acetic acid = (0.00326 moles) / (25.0 mL x 1 L/1000 mL) = 0.1304 M

This means that the concentration of the acetic acid in the solution is 0.13M.

Learn more about Concentration of acetic acid here:

brainly.com/question/31096445

#SPJ3

Related Questions

What is the symbol of the element that is classified as an alkali metal and is in period 4?
3. Theoretically how many grams of magnesium is required to produce to 5.0 g ofMagnesium oxide?
For the reaction ? NO + ? O2 → ? NO2 , what is the maximum amount of NO2 which could be formed from 16.42 mol of NO and 14.47 mol of O2? Answer in units of g. 003 1.0 points For the reaction ? C6H6 + ? O2 → ? CO2 + ? H2O 37.3 grams of C6H6 are allowed to react with 126.1 grams of O2. How much CO2 will be produced by this reaction? Answer in units of gram
How many moles of MgS2O3 are in 223 g of the compound
What is the correct noble gas configuration for oxygen?

The federal limit for cadmium in drinking water is 0.010 mg per liter of solution. What is the molar concentration of a Cd solution that has reached the limit?

Answers

Thank you for posting your question here. The molar concentration of a Cd solution that has reached the limit is 8.89x10^-8 mols/L. The equation to be used M=n/L to solve the above problem. Below is the solution:

.010mg/L = .00001g/L
.00001g / 112.41g/mol = 8.89x10^-8 mols/L

Answer:

$M=8.9x10^(-8)M$

Explanation:

Hello,

In this case, one can assume 1L as the volume of the solution, so we've got 0.010mg of cadmium. Now, as we're asked to know its molarity, one computes the moles of cadmium as follows:

$n_(Cd)=0.010mg*(1x10^(-3)gCd)/(1mgCd)*(1molCd)/(112.4gCd)=8.9x10^(-8)molCd$

Now, one obtains the molar concentration (molarity) as shown below: $M=(8.9x10^(-8)molCd)/(1L)\n M=8.9x10^(-8)M$

Best regards.

What factors govern the position of an IR absorption peak? Select one or more correct answers.(A) strength of the bond
(B) effect of a magnetic field on nucleus spin
(C) masses of the atoms involved in the bond
(D) the type of vibration being observed

Answers

Answer:

The factors that govern the position of an IR absorption peak are:

(A) strength of the bond

(C) masses of the atoms involved in the bond

(D) the type of vibration being observed

Explanation:

In infrared spectroscopy the molecules absorb the frequencies that are characteristic of their structure. These absorptions occur at resonance frequencies, that is, the frequency of the absorbed radiation coincides with the frequency of vibration. The energies are affected by the shape of molecular potential energy surfaces, the masses of atoms and the associated vibronic coupling. The resonance frequencies are also related to the strength of the bond and the mass of the atoms at each end of it. Therefore, the frequency of vibrations is associated with a particular normal movement mode and a particular type of link.

Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer the following questions regarding the addition of 14.0 g of KOH to water: Does the beaker get warmer or colder? Is the reaction endothermic or exothermic? What is the enthalpy change for the dissolution of the 14.0 grams of KOH?

Answers

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

$n = (m)/(M)$

Where:

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

$n = (m)/(M) = (14 g)/(56.1056 g/mol) = 0.249 mol$

The enthalpy change is:

$\Delta H = -43 (kJ)/(mol)*0.249 mol = -10.71 kJ$

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

3.What do we call materials
that let heat pass through
them easily?
Thermal conductors
Thermal insulators
Transparent

4.
Which of these is a good
thermal conductor?
Plastic
Wood
Steel

5.
Which of these is a good
thermal insulator?
Steel
Iron
Polystyrene

6.
To save on heating bills, do
you think the roof of a
building should be lined with...
a thermal conductor
a thermal insulator
nothing

7.
How does heat travel?
From cold things to hotter things
From hot things to colder things
Between things of the same temperature

Answers

Answer:

thermal conductors

steel

polystyrene

thermal insulator

between things of the same temp?

sorry to ask but if its ok with you, may i get brainly, i need to rank up all i need is two more, if not its fine. thank you and yours truly golden

(II) To make a secure fit, rivets that are larger than the rivet hole are often used and the rivet is cooled (usually in dry ice) before it is placed in the hole. A steel rivet 1.872cm in diameter is to be placed in a hole 1.870cm in diameter in a metal at 22°C. To what temperature must the rivet be cooled if it is to fit in the hole

Answers

Given:

Rivet diameter, $d_(r)$ = 1.872 cm

Hole diameter, $d_(h)$ = 1.870 cm

Temperature, $T_(2)$ = 22 °C

Formula Used:

$\alpha = (\Delta d)/(d* \Delta T)$

where,

$\alpha$ = coefficient of linear expansion

$\Delta d$ = change in diameter = $d_(h) - d_(r)$

$\Delta T}$ = change in temperature = $T_(2) - T_(1)$

Solution:

we know that coefficient of linear expansion of steel, $\alpha$ = $12* 10^(-6)/^(\circ)C$

Using the above formula :

$\alpha = (\Delta d)/(d* \Delta T)$

$12* 10^(-6)/^(\circ)C$ = \frac{1.870 - 1.872}{1.872\times \T_{2} - T_{1}}[/tex]

$T_(2) - 20/^(\circ)C$ = \frac{1.870 - 1.872}{12\times 10^{-6}}}[/tex]

$T_(2) = -67.03/^(\circ)C$

Therefore, the rivet must be cooled to $-67.03/^(\circ)C$

Final answer:

The question involves the concept of thermal expansion in Physics. By knowing the initial diameter of the rivet and hole, as well as the ambient temperature, we can use the thermal expansion formula to calculate the temperature to which the steel rivet must be cooled to fit into the hole.

Explanation:

The subject in question pertains to Physics and specifically to the concept of thermal expansion. This indicates how objects (in this case, a steel rivet) tend to change in volume or shape as a response to a change in temperature. The diameter of the rivet when cooled will decrease slightly, allowing it to fit into the smaller hole.

To find the temperature to which the rivet needs to be cooled, we require knowledge of the thermal expansion coefficient of steel, which (for generalization) can be averaged to around 0.000012 (1/°C). The formula to calculate the change in diameter (Δd) is:

Δd = α * d * ΔT

where α is the coefficient of linear expansion, d is the original diameter, and ΔT is the change in temperature. Knowing the initial diameter of the rivet and the hole it must fit into, together with the ambient temperature (22°C), we can rearrange this formula to find the cooling temperature needed for the rivet to fit into the hole.