Answers
Answer:
Go ahead and plug in the percentages and time to find the answer.
Explanation:
The amount of a substance with half-life h, that remains after time t is 0.5t/h
Since 26% has decomposed, 74% remains.
So .74 = 0.580/h
ln .74 = (80/h) ln 0.5
h/80 = ln 0.5 / ln .74
h = 80 ln 0.5 / ln .74
h = 184.16 minutes
Related Questions
A Carbon-10 nucleus has 6 protons and 4 neutrons. Through radioactive beta decay, it turns into a Boron-10 nucleus, with 5 protons and 5 neutrons, plus another particle. What kind of additional particle, if any, is produced during this decay
Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample
Convert 50g of calcium carbonate, CaCO3, into moles
How many molecules are there in 4.27 mol of tungsten(VI) oxide, WO3
Answers
Answer: C2H4S5
Explanation:
Since the total mass is 5.000g
Mass of sulphur = 5.000-(0.6357+0.1070)
Mass of sulphur = 4.2573g
Using Empirical relation
C= 0.6357 H= 0.1070 S= 4.2573
Divide through by their molar mass to obtain the smallest ratio
C= 0.6357/12 H=0.1070/1 S=4.2573/32
C= 0.053 H= 0.1070 S= 0.133
Divide through by the smallest ratio (0.053)
C=0.053/0.053 H=0.1070/0.053 S=0.133/0.053
C=1 H=2 S=2.5
1:2:2.5 ,multiply through by 2 ,to obtain whole numbera
2:4:5
Therefore the empirical formula is C2H4S5. Thus only gives the ratio
Molecular formula is the chemical formula .
(Empirical formula) n = molecular formula
(C2H4S5)n = molar mass
[(12×2) + ( 1×4) +(32×5)]n = 188.4
188n=188.4
n= 1
Molecular formula = (C2H4S5)×1
Therefore the chemical formula of
lenthionine is C2H4S5
Answers
(B) Ca3PO6
(C) Ca4P2O4
(D) Ca3P2O8 (or Ca3(PO4)2)
(E) CaPO4
Answers
Answer:
D) empirical formula is: C₃P₂O₈
Explanation:
Given:
Mass % Calcium (Ca) = 38.7%
Mass % Phosphorus (P) = 19.9%
Mass % oxygen (O) = 41.2 %
This implies that for a 100 g sample of the unknown compound:
Mass Ca = 38.7 g
Mass P = 19.9 g
Mass O = 41.2 g
Step 1: Calculate the moles of Ca, P, O
Atomic mass Ca = 40.08 g/mol
Atomic mass P = 30.97 g/mol
Atomic mass O = 16.00 g/mol
Step 2: Calculate the molar ratio
Step 3: Calculate the closest whole number ratio
C: P: O = 1.50 : 1.00 : 4.00
C : P : O = 3:2:8
Therefore, the empirical formula is: C₃P₂O₈
Final answer:
The mass percentage composition of a compound can be used to determine its empirical formula. For a compound with 38.7% calcium (Ca), 19.9% phosphorus (P), and 41.2% oxygen (O), the empirical formula is Ca3(PO4)2.
Explanation:
To solve this problem, we're going to use the atomic mass percentages to determine the empirical formula of the compound.
We do this by assuming we have a 100g sample of the compound. Therefore:
The mass of calcium (Ca) is 38.7g.
The mass of phosphorus (P) is 19.9g.
The mass of oxygen (O) is 41.2g.
Next, we calculate how many moles we have of each element:
- Ca: 38.7g / 40.08g/mol (the atomic mass of calcium) = 0.965 moles
- P: 19.9g / 30.97g/mol (the atomic mass of phosphorous) = 0.643 moles
- O: 41.2g / 16.00g/mol (the atomic mass of oxygen) = 2.575 moles
Then, we divide each of these numbers by the smallest number of moles, which is 0.643 (P):
- Ca: 0.965/0.643 = 1.5 (~1)
- P: 0.643/0.643 = 1
- O: 2.575/0.643 = 4
Learn more about Empirical Formula here:
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B) It is short-wave.
C) 40 percent is reflected by the atmosphere.
D) 60 percent reaches Earth's surface.
E) None of the rays are harmful.
Answers
Answer:
Your answers are B,C, and D
Explanation:
Because a and e are wrong it is these three.
Edit pls mark brainliest
In codominance, both allels are expressed in the offspring; In incomplete dominance, only one allele is expressed in the offspring.
In codominance, both alleles are expressed in the offspring; in incomplete dominance, the offspring demonstrate an intermediate form of the alleles from the parents.
In codominance, the offspring demonstrate an intermediate form of the alleles from the parents; in incomplete dominance, both alleles are expressed in the offspring.
Answers
Answer:
C Because im in 3rd grade and just did the test
Explanation:
im smart im in third grade but your doing this in college
Answer:
answer is c: In codominance, both alleles are expressed in the offspring; in incomplete dominance, the offspring demonstrate an intermediate form of the alleles from the parents.
Explanation:
Answers
Answer:
See attachment
Explanation:
The amine group of N,N-dimethylaniline is an electron-donating group and will cause the benzene ring to act as a nucleophile in an electrophilic aromatic substitution reaction with the diazonium salt of sulfanilic acid.