How many moles of MgS2O3 are in 223 g of the compound

Answers

Answer 1

Answer:

Answer: 1.63 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023* 10^(23)$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=$

Given mass = 223 g

Molar mass = 136.4

$\text{Number of moles}=(223g)/(136.4g/mol)=1.63moles$

Thus there are 1.63 moles in 223 g of the compound.

Answer 2

Answer: Moles of MgS2O3 = 223/molar mass of MgS2O3

= 223/136.42
= 1.634 moles.

Hope this helps!

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50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximately 1. 74 X 10 -5. What is the pH of the resulting solution?

Answers

Answer:

4.76

Explanation:

In this case, we have to start with the buffer system:

$CH_3COOH~->~CH_3COO^-~+~H^+$

We have an acid ( $CH_3COOH$ ) and a base ( $CH_3COO^-$ ). Therefore we can write the henderson-hasselbach reaction:

$pH~=~pKa+Log([CH_3COO^-])/([CH_3COOH])$

If we want to calculate the pH, we have to calculate the pKa:

$pH=-Log~Ka=4.76$

According to the problem, we have the same concentration for the acid and the base 0.1M. Therefore:

$[CH_3COO^-]=[CH_3COOH]$

If we divide:

$([CH_3COO^-])/([CH_3COOH])~=~1$

If we do the Log of 1:

$Log~1=~zero$

So:

$pH~=~pKa$

With this in mind, the pH is 4.76.

I hope it helps!

Animal fats tend to be _______________ with hydrogen atoms. (fifth paragraph of this sub-section

Answers

Animal fats tend to be _______________ with hydrogen atoms. Fats are long chain amino acids, mostly carbon and hydrogen. The answer is "Animal fats tend to be single bonded to or surrounded by or saturated with hydrogen atoms." Saturated means the maximum number of hydrogen atoms are bonded to the carbon atom.

Answer:

Saturated.

Explanation:

Hello,

Animal fats are lipids derived from animals which are commonly solid at room temperature and mainly constituted by triglycerides which are strictly chemically saturated with hydrogen, it means they do not tend to have double or triple bonded carbon atoms but just single-bonded carbons. This fact suggests that animal fats provide more energy than vegetable fats because they have more C-H bonds that when broken increase the total provided energy.

Best regards.

You are asked to prepare 500 mL 0.300 M500 mL 0.300 M acetate buffer at pH 4.904.90 using only pure acetic acid ( MW=60.05 g/mol,MW=60.05 g/mol, pKa=4.76), pKa=4.76), 3.00 M NaOH,3.00 M NaOH, and water. Answer the questions regarding the preparation of the buffer. 1. How many grams of acetic acid will be needed to prepare the 500 mL buffer? Note that the given concentration of acetate refers to the concentration of all acetate species in solution.

Answers

The quantity of acetic acid that is needed to prepare the 500 mL buffer is 9.0075 grams.

Given the following data:

Volume of acetate buffer = 500 mL to L = 0.5 L.

Molarity of acetate buffer = 0.300 M.

pH = 4.90.

MW = 60.05 g/mol.

pKa = 4.76.

How to calculate the mass of acetic acid.

First of all, we would write the equilibrium chemical reaction for acetate-acetic acid as follows:

$CH_3COOH \rightleftharpoons CH_3COO^(-)+H^+$

Next, we would calculate HA by applying Henderson-Hasselbalch equation:

$pH =pka+ log_(10) (A^-)/(HA)$

Where:

HA is acetic acid.

$A^-$ is acetate ion.

Substituting the given parameters into the formula, we have;

$4.90 =4.76+ log_(10) (A^-)/(HA)\n\n4.90 -4.76+ log_(10) (A^-)/(HA)\n\n(A^-)/(HA)=1.38\n\nA^- = 1.38[HA]$

For the concentration of both acids, we have:

$[HA]+[A^-]=0.300M\n\n[HA]+1.38[HA]=0.300M\n\n2.38[HA]=0.300M\n\nHA = 0.126$

For acetate ion:

$A^- = 1.38[HA] = 1.38 * 0.126\n\nA^- =0.174$

At a volume of 0.5 liters, we have:

$HA = 0.5 * 0.126\n\nHA = 0.063 \;moles$

$A^- = 0.5 * 0.174\n\nA^- =0.087 \;moles$

By stoichiometry:

Total moles = $0.063 + 0.087$ = 0.15 moles.

$Mass = number \;of \;moles * molar\;mass\n\nMass =0.15 * 60.05$

Mass = 9.0075 grams.

Read more on moles here: brainly.com/question/3173452

Answer:

You will need 9,0 g of acetic acid

Explanation:

The equilibrium acetate-acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka = 4,76

Using Henderson-Hasselbalch you will obtain:

pH = pka + log₁₀ $([A^(-)])/([HA])$

Where HA is acetic acid and A⁻ is acetate ion

4,90 = 4,76 + log₁₀ $([A^(-)])/([HA])$

1,38 = $([A^(-)])/([HA])$ (1)

As acetate concentration is 0,300M:

0,300M = [HA] + [A⁻] (2)

Replacing (2) in (1):

[HA] = 0,126 M

And:

[A⁻] = 0,174 M

As you need to produce 500 mL:

0,5 L × 0,126 M = 0,063 moles of acetic acid

0,5 L × 0,174 M = 0,087 moles of acetate

To produce moles of acetate from acetic acid:

CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O

Thus, moles of acetate are equivalents to moles of NaOH and all acetates comes from acetic acid, thus:

0,087 moles of acetate + 0,063 moles of acetic acid ≡ 0,15 moles of acetic acid × $(60,05 g)/(1mol)$ = 9,0 g of acetic acid

I hope it helps!

In basic enzyme kinetics, a large Km indicates that the substrate binds A. Permanently B. Transiently C. Covalently D. with low specificity E. Weakly

Answers

Answer: D

Explanation:

Km value is a signature of the enzyme. It is the characteristic feature of a particular enzymes for a specific substrate. Km denotes the affinity of the enzyme for substrate. The lesser the numerical value of Km, the affinity of the enzyme for the substrate is more.

In the velocity x substrate graph in a fixed quantity if enzyme. As substrate concentration is increase, the velocity is also increasing at the initial phase but the curve fatten afterwards. This is because as more substrate is added, all enzymes molecules become saturated. Further increase in substrate cannot make any effect in the reaction velocity.

The maximum velocity is called Vmax. Km is the concentration of substrate that Vmax is half.

The larger the numerical value of Km, the lesser the enzyme binds the substrate

Group/family 18 on the periodic table is calledO alkaline earth metals
Onoble gases
O halogens
O transitional metals

Answers

Final answer:

Group/Family 18 on the periodic table is called the noble gases.

Explanation:

Group/Family 18 on the periodic table is called the noble gases. The noble gases are a group of chemical elements that have full valence electron shells, which makes them stable and nonreactive. This group includes elements like helium, neon, argon, krypton, xenon, and radon.

Learn more about Noble gases on the periodic table here:

brainly.com/question/20587748

The periodic table displaysOA. all of the known elements that exist in the world today.
OB. only the important elements that exist in the world.
OC. only the important compounds that exist in the world.

Answers

OA. all the known elements that exist in the world today.

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