Differentiate between the formation of biochemical rocks and the formation of inorganic chemical rocks.Biochemical rocks form from organisms that were once alive, such as limestone from marine shells, whereas inorganic chemical rocks form from non-biological processes, such as salt that is left behind when a lake evaporates.

Answers

Answer 1
Answer:

In contrast to inorganic chemical rocks, which result from non-biological processes such as salt left over when a lake evaporates, biochemical rocks are formed by once-living creatures, such as limestone from marine shells.

The process, which is inorganic and frequently the consequence of a body of water evaporating and concentrating the ions, occurs in chemical sedimentary rocks. The formation of one kind of sedimentary rock may be mediated by both chemical (inorganic) and biological (organic) processes. Aragonite and calcite make up limestone. The majority of limestone is biological in origin, while it can also occur as a chemical sedimentary rock that forms inorganically as a result of precipitation. In actuality, limestone is the biochemical sedimentary rock that is found most frequently. In marine (i.e., oceanic or salty sea) settings, nearly all limestone

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Which of the following statements is true with regard to transverse and longitudinal waves?Group of answer choices Both transverse waves and longitudinal waves have motion parallel to velocity. Both transverse waves and longitudinal waves have motion perpendicular to velocity. Transverse waves have motion parallel to velocity, while longitudinal waves have motion perpendicular to velocity. Transverse waves have motion perpendicular to velocity, while longitudinal waves have motion parallel to velocity.

PLEASE HELP IMMEDIATELY ​

Answers

Answer:

Ability to move

Must be able to eat

grow and develop

reproduce

respond to environment

taking in food

Explanation:

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Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equation.

Answers

Answer:

30 cm³

Explanation:

Step 1: Given data

  • Density of aluminum (ρ): 2.7 g/cm³
  • Mass of aluminum (m): 81 g
  • Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

G write the symbols for the cation and anion that make up each ionic compound Co(NO3)2

Answers

Answer:

Co(NO_3)_2 is formed of cation, Co^(2+) and anion,NO_3^(-)

Explanation:

Naming of the ionic compounds:-

  • The name of the cation is written first and the the name of the anion is written after the name of the cation separated by single space.
  • The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
  • In case of transition metals, the oxidation state are written in roman numerals in bracket in front of positive ions.

Hence, given ionic compound:-

Co(NO_3)_2 is formed of cation, Co^(2+) and anion,NO_3^(-)

Thus, the name must be Cobalt(II) nitrate.

Which of the following describes a way in which chemistry affects how youuse a computer?
A. The colors in the computer display are the result of substances
that glow.
B. By clicking a mouse, you can select an object or text on a
computer screen.
C. Eye stress can be reduced by sitting a certain distance from the
Screen.
D. You are able to play video games by moving your body instead of a
joystick

Answers

A way in which chemistry affects how To use a computer is  The colors in the computer display are the result of substances that glow. Option A

In modern computers, the display technology commonly used is Liquid Crystal Display (LCD) or Light Emitting Diode (LED) technology. These displays rely on the principles of chemistry to produce the colors that we see on the screen.

In LCD screens, tiny liquid crystal cells are controlled by an electric current, which causes them to either block or allow the passage of light. Each cell represents a pixel on the screen, and by controlling the intensity of light passing through each pixel, different colors can be produced.

The liquid crystals used in LCD screens are organic compounds that exhibit unique optical properties, allowing them to manipulate light in a controlled manner.

LED screens, on the other hand, use arrays of light-emitting diodes to generate light. These diodes are made of semiconducting materials, often composed of compounds like gallium, arsenic, and phosphorus. When an electric current passes through these compounds, they emit light of a specific wavelength, resulting in the different colors displayed on the screen.

So, the colors we see on a computer display are a direct result of the chemical properties and behavior of the substances used in the LCD or LED technology. Chemistry plays a crucial role in the design and functionality of computer displays, enabling us to view vibrant and accurate colors while using our computers.

Option A

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What effect does salt have on most metals?

Answers

the combination of moisture, oxygen and salt ,especially sodium chloride, damages metal worse than rust does. This combination corrodes, or eats away at, the metal, weakening it and causing it to fall apart.

The half-life of a pesticide determines its persistence in the environment. A common pesticide degrades in a first-order process with a rate constant of 6.5 1/hours. What is the half-life in hours of the breakdown reaction? Enter to 4 decimal places.

Answers

Answer:

0.1066 hours

Explanation:

A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.

t1/2 = ln2/k

t1/2 = ln2/6.5 h⁻¹

t1/2 = 0.1066 h

The half-life of the pesticide is 0.1066 hours.

The half-life of the breakdown reaction is 0.1066 h

The half-life of a substance is simply defined as the time taken for half of the original substance to decay.

The half-life of a first order reaction can be obtained by the following equation:

t_(1/2)  = (0.693)/(K)

Where:

t_(1/2) is the half-life

K is the decay constant

With the above formula, we can obtain the half-life of the breakdown reaction as follow:

Rate constant (K) = 6.5 h¯¹

Half-life (t_(1/2)) =.?

t_(1/2) = (0.693)/(K) \n\nt_(1/2) = (0.693)/(6.5)\n\nt_(1/2) = 0.1066 h

Therefore, the half-life of the breakdown reaction is 0.1066 h

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