Refer to the example about diatomic gases A and B in the text to do problems 20-28.It was determined that 1 mole of B2 is needed to react with 3 moles of A2.
How many grams in one mole of B2?
__g

Answers

Answer 1

Answer:

Final answer:

The number of grams in one mole of B2 can be calculated using the atomic mass of element B. This is found on the periodic table and then doubled for B2 since it's diatomic. If B is Oxygen for instance, 1 mole of B2 (O2) weighs 32 grams.

Explanation:

To find the number of grams in one mole of B2, we need to know the atomic mass of element B, which isn't provided in your question. However, you can find this information on the periodic table. Once you have the atomic mass of B, you can calculate the molar mass of B2 (which is two times the atomic mass of B) since 1 mole of a substance corresponds to its molar mass in grams.

For example, if element B is Oxygen (O), its atomic mass is approximately 16 g/mol. Therefore, the molar mass of B2 (O2 in this case) would be 32 g/mol. Hence, 1 mole of B2 (or O2) would weigh 32 grams.

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A chemist fills a reaction vessel with 0.750 M lead (II) (Pb2+) aqueous solution, 0.232 M bromide (Br) aqueous solution, and 0.956 g lead (II) bromide (PbBr2 solid at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: Pb2+ (aq) + 2Br (aq) = PbBr2 (s) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule.

Which aqueous solution is colored?1.
CuSO4(aq)
2.
BaCl2(aq)
3.
KCl(aq)
4.
MgSO4(aq)

Answers

Answer: Copper (II) Sulfate! (CuSO4)

Explanation:

This is because compared to the other salts, it is the visible color blue. The other ones are plain white. Happy holidays! Don’t stress :)

In a constantvolume bomb calorimeter, the combustion of 0.6654 gof an organic
compound with a molecular mass of 46.07 amu causesthe temperature
in the calorimeter to rise from 25.000oC to 30.589
oC. The total heat capacity ofthe calorimeter and all
its contents is 3576 JoC-1. What is
the energy of combustion ofthe organic compound,
DU/ kJ
mol-1?

Answers

Answer:

1383.34 kJ/mol is the energy released on combustion of the organic compound.

Explanation:

Mass of an organic compound = 0.6654 g

Molar mass of organic compound = 46.07 g/mol

Moles of an organic compound = $(0.6654 g)/(46.07 g/mol)=0.01444 mol$

Let heat evolved during burning of 0.6654 grams of an organic compound be -Q.

Heat absorbed by calorimeter = Q' = -Q

The total heat capacity of the calorimeter all its contents = C

C = 3576 J/°C

Change in temperature of the calorimeter =

ΔT = 30.589°C - 25.000°C = 5.589°C

$Q'=C* \Delta T$

$Q'=3576 J/^oC* 5.589^oC=19,975.536 J=19.975 kJ$

Q' = 19.975 kJ

Q = -19.975 kJ (negative sign; energy released)

0.01444 moles of an organic compound gives 19.975 kilo Joule.

The 1 mole of an organic compound will give : $\Delta H_(comb)$

$\Delta H_(comb)=(-19.975 kilo Joule)/(0.01444 mol)$

$=-1383.34 kJ/mol$

At a winter carnival, a balloon is filled with 5.00 L of helium at a temperature of 1.0°C. What will be the volume of the balloon when it is brought into a warm house at 24°C?

Answers

Answer:

The volume of balloon is 5.41 L.

Explanation:

The volume of helium (V1) = 5 L

Temperature (T1) = 1 degree Celsius

Now covert the temperature into kelvin by simply adding the 273 with given temperature. Thus, 1-degree Celsius = 274 kelvin.

The volume of balloon (V2) =?

Temperature (T2) = 24 degree Celsius

Now covert degree Celsius into kelvin. Thus, 24-degree Celsius = 297 kelvin.

Using Charl’s law.

$(V1)/(T1) = (V2)/(T2) \n$

$(5)/(274) = (V2)/(297) \n$

$V2 = 5.41 \ L$

Arrange the following substances in order of increasing solubility of water. C6H14, C6H13Br, C6H13OH, C6H12(OH)2.

Answers

Answer:

C6H14 < C6H13Br < C6H13OH < C6H12(OH)2

Explanation:

Hello,

In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:

C6H14 < C6H13Br < C6H13OH < C6H12(OH)2

Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.

Best regards.

Bobby created a dilution of 1/100 of a bacterial sample by adding 1 mL of sample to 99 mL of saline. Unfortunately, after Bobby completed the dilution, he knocked the container over spilling the majority of the diluted sample out. After cleaning up the mess, he found he had 19 mL of diluted sample remaining. Can he still completed the microbial count and if so, then write out the steps on how would he determine the original cell concentration of his total remaining samp

Answers

Answer:

There is no short answer.

Explanation:

In the given example Bobby is creating a solution for his bacteria count which consists of 1% bacterial sample.

Considering that the solution was mixed homogeneously, he can apply the procedure to the remaining sample and get the results he wants.

Or if the average number of bacteria in a 1 mL sample is known, he can apply that information proportionally to the 100 mL mixture and find the original cell concentration.

I hope this answer helps.

Write the numbers in scientific notation.291.7 = 2.917
X10%
where x =
0.0960 -
X10%
where x =

Answers

The numbers in scientific notation are 291.7 = 2.917 × 10₂ and 0.0960 = 9.60 × 10⁻².

Scientific notation is commonly used in scientific and mathematical calculations, as well as when dealing with very large or very small numbers. It allows for a more compact and manageable representation of these numbers.

To write the numbers in scientific notation, we need to express them in the form of "a × 10^b," where "a" is a number between 1 and 10, and "b" is an integer.

For the number 291.7, write it in scientific notation as:

291.7 = 2.917 × 10²

For the number 0.0960, write it in scientific notation as:

0.0960 = 9.60 × 10⁻²

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2.917 x 10^2 0.960x 10^1

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