CHEMISTRY COLLEGE

Part D 2ClO2(g)+2I−(aq)→2ClO−2(aq)+I2(s) Drag the appropriate labels to their respective targets. ResetHelp e−→e Superscript- rightarrow ←e−leftarrow e Superscript- Cathode Cathode Anode Anode II Superscript- ClO−2C l O Subscript 2 Superscript- Request Answer Part E Indicate the half-reaction occurring at Anode. Express your answer as a chemical equation. Identify all of the phases in your answer. nothing

Answers

Answer 1

Answer:

The half reaction occurring at anode is:

$2I^-(aq)---- > I_2(s)+2e^-$

Half reaction for the cell:

The substance having highest positive potential will always get reduced and will undergo reduction reaction.

Balanced chemical equation:

$2ClO_2(g)+2I^-(aq)----- > 2ClO^(2-)(aq)+I_2(s)$

The half reaction follows:

Oxidation half reaction: $2I^-(aq)---- > I_2(s)+2e^-$ , Reduction potential is 0.53V

Reduction half reaction: $ClO_2(g)+e^----- > ClO_2^-$ ( × 2 ), Oxidation potential is +0.954 V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

Hence, the half reaction occurring at anode is :

$2I^-(aq)---- > I_2(s)+2e^-$

Find more information about Reduction potential here:

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Answer 2

Answer:

Answer: The half reaction occurring at anode is $2I^-(aq.)\rightarrow I_2(s)+2e^-$

Explanation:

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction.

For the given chemical equation:

$2ClO_2(g)+2I^-(aq)\rightarrow 2ClO^(-2)(aq.)+I_2(s)$

The half reaction follows:

Oxidation half reaction: $2I^-(aq.)\rightarrow I_2(s)+2e^-;E^o_(I_2/I^-)=0.53V$

Reduction half reaction: $ClO_2(g)+e^-\rightarrow ClO_2^-(aq.);E^o_(ClO_2/ClO_2^-)=+0.954V$ ( × 2 )

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

Hence, the half reaction occurring at anode is $2I^-(aq.)\rightarrow I_2(s)+2e^-$

Related Questions

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How much energy in joules does it take to raise the temperature of 255g of water by 12.5C
Find the density of an object that has a volume of 2.3 x 10^2 and a mass of3.5 x 10^3. *

What is molarity a measure of?OA. Density
OB. Concentration
OC. Mass
OD. Volume

Answers

Final answer:

Molarity is a measure of concentration in a solution.

Explanation:

Molarity is a measure of concentration in a solution. It represents the amount of a solute dissolved in a given volume of solvent. Molarity is calculated by dividing the moles of solute by the volume of the solution in liters.

Learn more about Molarity here:

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Which is not a product of the fractional distillation of petroleum?A) Gasoline
B) Jet Fuel
C) steel

Answers

Answer:
Option-C, STEEL is not a product of the fractional distillation of petroleum.

Explanation:
Petroleum is the mixture of Hydrocarbons *carbon and hydrogen containing compounds) present beneath the Earth's surface. Petroleum is formed from the remains of animals and plants beneath earth's surface in an anaerobic conditions.
Petroleum contains from small hydrocarbons (gases) to medium (liquids) and long chain hydrocarbons (Solids). These hydrocarbons are separated from each other by Fractional Distillation method (separation due to difference in boiling points)
Gasoline is a derivative of one of the fraction of petroleum used in internal combustion engines.
Jet Fuel is also derived from Kerosene and Naphtha fractions of petroleum.
While, Steel is inorganic Alloy (mixture of metals) composed of mainly Iron, Carbon and other elements.

In a constantvolume bomb calorimeter, the combustion of 0.6654 gof an organic
compound with a molecular mass of 46.07 amu causesthe temperature
in the calorimeter to rise from 25.000oC to 30.589
oC. The total heat capacity ofthe calorimeter and all
its contents is 3576 JoC-1. What is
the energy of combustion ofthe organic compound,
DU/ kJ
mol-1?

Answers

Answer:

1383.34 kJ/mol is the energy released on combustion of the organic compound.

Explanation:

Mass of an organic compound = 0.6654 g

Molar mass of organic compound = 46.07 g/mol

Moles of an organic compound = $(0.6654 g)/(46.07 g/mol)=0.01444 mol$

Let heat evolved during burning of 0.6654 grams of an organic compound be -Q.

Heat absorbed by calorimeter = Q' = -Q

The total heat capacity of the calorimeter all its contents = C

C = 3576 J/°C

Change in temperature of the calorimeter =

ΔT = 30.589°C - 25.000°C = 5.589°C

$Q'=C* \Delta T$

$Q'=3576 J/^oC* 5.589^oC=19,975.536 J=19.975 kJ$

Q' = 19.975 kJ

Q = -19.975 kJ (negative sign; energy released)

0.01444 moles of an organic compound gives 19.975 kilo Joule.

The 1 mole of an organic compound will give : $\Delta H_(comb)$

$\Delta H_(comb)=(-19.975 kilo Joule)/(0.01444 mol)$

$=-1383.34 kJ/mol$

What are the components of DNA? A. ribose sugar, cytosine, guanine, adenine, thymine, and phosphate group

B. ribose sugar, cytosine, guanine, adenine, uracil, and phosphate group

C. deoxyribose sugar, cytosine, guanine, adenine, thymine, and phosphate group

D. deoxyribose sugar, cytosine, guanine, adenine, uracil, and phosphate group

Answers

Answer:

Explanation:

A-T G-C

If there is direct variation and y=75 when x=25, find x when y=48.A. x=16

B. x=10

C. x=12

D. x=14

Answers

If there is direct variation and y=75 when x=25,when y=48 X = 16. Therefore, option A is correct.

What is direct variation ?

link between two variables that can be described mathematically by an equation where one variable equals a constant multiplied by the other. For instance, the constant of variation is k = = 3 if y varies straight as x and y = 6 when x = 2. Consequently, y = 3x is the equation that describes this directvariation.

When x is not equal to zero, an equation of the form y = kx describes the linear function known as direct variation. When x is not equal to zero and k is a nonzero real number constant, the equation of the form xy = k describes the nonlinear function known as inverse variation.

x = ky

where k is constant

25 = k × 75

25 / 75 = k

k = 1 / 3

now when y = 48 then substitute the values

x = ky

x = 1 ÷ 3 × 48

x = 16

Thus, option A is correct.

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x = ky where k is a constant

first u find k so :
25 = k * 75
25/75 = k
k = 1/3

now when y = 48 just substitute the values
x = ky
x = 1/3 * 48
x = 16

the answer is A) x=16

The entropy of a substance above absolute zero will always be: a. Negative
b. Positive
c. Neither Negative nor positive

Answers

i will be positive. just because it’s positive

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