What is the molarity of a solution prepared from 25.0 grams of methanol (CH3OH, density = 0.792 g/mL) with 100.0 milliliters of ethanol (CH3CH2OH)? Assume the volumes are additive.

Answers

Answer 1

Answer:

Final answer:

The molarity of a solution prepared from 25.0 grams of methanol and 100.0 milliliters of ethanol is approximately 7.80 M.

Explanation:

This is a question about calculating molarity, which is a measure of concentration using moles per liter. To calculate the molarity of a methanol in ethanol, we first have to convert the mass of methanol into moles. The molar mass of methanol (CH3OH) is about 32.04 g/mol. Therefore, 25.0 g of methanol equals about 0.780 moles (25.0 g ÷ 32.04 g/mol).

Next, the volume of ethanol needs to be converted from milliliters to liters. Thus, 100.0 mL becomes 0.100 L. Finally, the molarity is calculated by dividing the moles of methanol by the volume of the ethanol in liters, resulting in a molarity of approximately 7.80 M (0.780 moles ÷ 0.100 L).

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Which hybridization scheme occurs about phosphorus when nitrogen forms a triple bond?

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Jun 21, 2015 · 3 posts · 1 author

Most of the time when nitrogen forms a double bond it will be sp2 hybridised. permalink; embed; save.

What is the chemical formula for the ionic compound formed by Au3+ and
HSO3-?

Answers

Answer:

The chemical formula for the ionic compound formed by Au3+ and

HSO3-compound is Au(HSO3)3

Explanation:

The charge on Au ion is $+3$

And the charge on HSO3- is $-1$

Thus, the number of atoms required by HSO3- to complete its octate is 1. On the other hand Au has 3 excess ions and hence it is to be released to reach the stable state.

So three molecules of HSO3- will combine with one atom of Au 3+

Thus, the compound formed by these two is Au(HSO3)3

Final answer:

The chemical formula for the ionic compound formed by Au3+ and HSO3- is Au(HSO3)3, as ionic compounds are always neutral.

Explanation:

The ionic compound formed by Au3+ (Gold ion) and HSO3- (Bisulfite ion) must have a net charge of zero since ionic compounds are neutral. Hence, we need 3 bisulfite ions to balance out one gold ion, which gives us the chemical formula as Au(HSO3)3.

Indeed, the formation of ionic compounds is a fascinating process. It involves the transfer of electrons from one atom (usually a metal) to another (usually a nonmetal), resulting in the formation of ions. These ions are then attracted to each other due to their opposite charges, forming an ionic compound. In this case, the gold ion (Au3+) donates three electrons, which are accepted by three bisulfite ions (HSO3-). This results in a neutral compound, as the positive and negative charges balance each other out. The resulting compound, Au(HSO3)3, is an example of how elements can combine in specific ratios to form neutral compounds.

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What is the value for the kinetic energyfor a n = 2 Bohr orbit electron in Joules?

Answers

Answer:

K.E. = 5.4362 × 10⁻¹⁹ J

Explanation:

The expression for Bohr velocity is:

$v=(Ze^2)/(2 \epsilon_0* n* h)$

Applying values for hydrogen atom,

Z = 1

Mass of the electron ( $m_e$ ) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

$\epsilon_0$ = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

$v=\frac {2.185* 10^6}{n}\ m/s$

Given, n = 2

So,

$v=\frac {2.185* 10^6}{2}\ m/s$

$v=1.0925* 10^6\ m/s$

Kinetic energy is:

$K.E.=\frac {1}{2}* mv^2$

So,

$K.E.=\frac {1}{2}* 9.1093* 10^(-31)* ({1.0925* 10^6})^2$

K.E. = 5.4362 × 10⁻¹⁹ J

What is the molarity of the following solutions?a. 19.5 g NaHCO3 in 460.0 ml solution
b. 26.0 g H2SO4 in 200.0 mL solution
c. 15.0 g NaCl dissolved to make 420.0 mL solution

Answers

Answer:

a) NaHCO3 = 0.504 M

b) H2SO4 = 1.325 M

c) NaCl = 0.610 M

Explanation:

Step 1: Data given

Moles = mass / molar mass

Molarity = moles / volume

a. 19.5 g NaHCO3 in 460.0 ml solution

Step 1: Data given

Mass NaHCO3 = 19.5 grams

Volume = 460.0 mL = 0.460 L

Molar mass NaHCO3 = 84.0 g/mol

Step 2: Calculate moles NaHCO3

Moles NaHCO3 = 19.5 grams / 84.0 g/mol

Moles NaHCO3 = 0.232 moles

Step 3: Calculate molarity

Molarity = 0.232 moles / 0.460 L

Molarity = 0.504 M

b. 26.0 g H2SO4 in 200.0 mL solution

Step 1: Data given

Mass H2SO4 = 26.0 grams

Volume = 200.0 mL = 0.200 L

Molar mass H2SO4 = 98.08 g/mol

Step 2: Calculate moles H2SO4

Moles H2SO4 = 26.0 grams / 98.08 g/mol

Moles H2SO4 = 0.265 moles

Step 3: Calculate molarity

Molarity = 0.265 moles / 0.200 L

Molarity =1.325 M

c. 15.0 g NaCl dissolved to make 420.0 mL solution

Step 1: Data given

Mass NaCl = 15.0 grams

Volume = 420.0 mL = 0.420 L

Molar mass NaCl = 58.44 g/mol

Step 2: Calculate moles NaCl

Moles NaCl = 15.0 grams / 58.44 g/mol

Moles NaCl = 0.256 moles

Step 3: Calculate molarity

Molarity = 0.256 moles / 0.420 L

Molarity =0.610 M

How many moles of atoms are in 9.00 g of 13c? express your answer numerically in moles?

Answers

Number of moles is defined as the ratio of given mass in grams to the molar mass of compound.

Number of moles = $(Given mass in g)/(Molar mass)$

Now, put the value of given mass of $^(13)C$ in grams and molar mass of $^(13)C$ in g/mol i.e. 13 g/mol.

Thus,

number of moles = $(9.00 g)/(13 g/mol)$

= 0.692 mol

Hence, number of moles of $^(13)C$ = 0.692 mol

Molecular compounds result from covalent bonding which are called _______.This is for high school physical science

Answers

Answer:

Diatomic Molecule

Explanation:

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