What is the formula for nickel (II) carbonate

Answers

Answer 1

Answer:

Answer:

NiCO3

Explanation:

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For this reaction, C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O, the ∆H is –2200 kJ. If two moles of C3H8(g) reacted with excess oxygen, what would be true?

A first-order decomposition reaction has a rate constant of 0.00140 yr−1. How long does it take for [reactant] to reach 12.5% of its original value? Be sure to report your answer to the correct number of significant figures.

Answers

Reactants take 504.87 yr to reach 12.5% of their original value in first-order decomposition reaction.

Equation for the first-order decomposition reaction:-

$A_(t) =A_(0) e^(-kt)$ ....(1)

Here, $A_(t)$ is the final concentration, t is the time, $A_(0)$ is the initial concentration, and k is the rate constant.

Given:-

$A_(t) =0.125A_(0)$

k= $0.00140yr^(-1)$

Substitute the above value in equation (1) as follows:-

$0.125A_(0) =A_(0) e^(-kt) \n0.125A_(0) =A_(0) e^{-k*0.00140 yr^(-1) }\nln(0.125)/(-0.00140)=t\nt=504.87 year$

So, 504.87 yr does it take for the reactant to reach 12.5% of its original value.

Find more information about first- order decomposition reaction here:-

brainly.com/question/20607444

Final answer:

The time required for a reactant to reach 12.5% of its original value in a first-order reaction is approximately 1482 years, obtained by applying the formula for the half-life of a first-order reaction and multiplying by 3.

Explanation:

In a first-order reaction, the half-life of the reaction, which is the time it takes for half of the reactant to be consumed, is independent of the concentration of the reactant. Also, for a first-order reaction, it would take approximately 3 half-lives for the reactant to be reduced to 12.5% of its original value. The Integrated Rate Law for a First-Order Reaction can be applied to determine the time it will take.

Given the rate constant (k) is 0.00140 yr¯¹, we will use the formula for the half-life of a first-order reaction: t₁/₂ = 0.693 / k. After calculating the half-life (t₁/₂), multiply it by 3 to determine the time for the reactant concentration to reach 12.5% of its original value. Hence, it would take approximately 1482 years to reach 12.5% of the original value when rounded to the correct number of significant figures.

Learn more about First Order Reaction here:

brainly.com/question/1769080

#SPJ12

As a raindrop falls from a cloud to the surface of Earth,A. its speed increases due to gravity.
B. its speed increases due to air resistance,
C. it moves at a constant speed,
<
OD. it moves at a constant velocity

Answers

Answer:

The answer is C!

Explanation:

Hope it helps

Answer D

Explanation: did the quiz ψ(｀∇´)ψ

Convert 50g of calcium carbonate, CaCO3, into moles

Answers

Answer:
Moles = 0.5 mol

Solution:

Moles is related to mass as follow,

Moles = Mass / M.mass ----- (1)

Where;
Mass = 50 g

M.mass = Ca (40) + C (12) + O₃ (16)₃ = 100 g/mol

Putting values in equation 1,

Moles = 50 g ÷ 100 g.mol⁻¹

Moles = 0.5 mol

What are some examples of matter?

Answers

Answer:

An apple.

A person.

A table.

Air.

Water.

A computer.

Paper.

Iron.

Hope this helps you

Answer:

your boddy is made of mater and a clock too it is still a mater of time.

Explanation:

A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base (B) solution. Show all your work.pKb for the weak base = 4.82.

Molar mass of the weak base = 82.0343g/mole.

Note: pKa = -logKa

pKb = -logKb

pH + pOH = 14

[H+ ] [OH- ] = 10^-14

Answers

Answer:

11.39

Explanation:

Given that:

$pK_(b)=4.82$

$K_(b)=10^(-4.82)=1.5136* 10^(-5)$

Given that:

Mass = 1.805 g

Molar mass = 82.0343 g/mol

The formula for the calculation of moles is shown below:

$moles = (Mass\ taken)/(Molar\ mass)$

Thus,

$Moles= (1.805\ g)/(82.0343\ g/mol)$

$Moles= 0.022\ moles$

Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)

$Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)$

$Molarity=(0.022)/(0.055)$

Concentration = 0.4 M

Consider the ICE take for the dissociation of the base as:

B + H₂O ⇄ BH⁺ + OH⁻

At t=0 0.4 - -

At t =equilibrium (0.4-x) x x

The expression for dissociation constant is:

$K_(b)=\frac {\left [ BH^(+) \right ]\left [ {OH}^- \right ]}{[B]}$

$1.5136* 10^(-5)=\frac {x^2}{0.4-x}$

x is very small, so (0.4 - x) ≅ 0.4

Solving for x, we get:

x = 2.4606×10⁻³ M

pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61

pH = 14 - pOH = 14 - 2.61 = 11.39

Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21 ∘C∘C. Express the pressures in atmospheres to three significant digits separated by commas.

Answers

The question is incomplete, complete question is ;

A deep-sea diver uses a gas cylinder with a volume of 10.0 L and a content of 51.8 g of $O_2$ and 33.1 g of He. Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 21°C.Express the pressures in atmospheres to three significant digits separated by commas.