At this location, it is summer in the Northern Hemisphere because the North Pole is tiltedAway from the sun

Towards the sun

Answers

Answer 1

Answer:

Answer:

This happens twice a year during Earth's orbit. Near June 21 the north pole is tilted 23.5 degrees toward our Sun and the northern hemisphere experiences summer solstice, the longest day of the northern hemisphere year.

...

Do other planets have seasons?

Uranus

30,589

97.8

Spring Equinox* 2050

Summer Solstice*

Answer 2

Answer:

points toward the sun.

closer the earth is to the sun the more hot it will be the closer it is to summer,

you can see at D northern hemisphere is closest to sun and the north pole is pointing toward the sun.

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g n the following three compounds(1,2,3) arrange their relative reactivity towards the reagent CH3Cl / AlCl3. Justify your order
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Whose measurements are more precise?20.3 cm and 21.0cm
The information below describes a redox reaction.Cr3+(aq)+2Cl-(aq)---->Cr(s)+Cl2(s) 2Cl-(aq)--->Cl2(g)+2e- Cr3+(aq)+3e- ---->Cr(s) What is the final, balanced equation for this reaction? 1.) 2cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g) 2.) 2Cr3(aq)+2Cl-(aq)+6e- --->Cl2(g)+2Cr(s) 3.) Cr3+(aq)+6Cl-(aq)+3e- ---->2Cr(g)+3Cl2(g) 4.) Cr3+(aq)+2Cl-(aq)------>Cr(s)+Cl2(g)
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Oil is a fossil fuel used to run cars, heat up homes, and produce electricity. Oil can be removed from the bottom of the ocean through drilling. Drilling machines dig deep down into the Earth. When oil is found, pipes carry it to the surface. Sometimes, accidents happen that cause the oil to spill into the oceans. The oil can not only kill marine organisms, but when it reaches the surface of the water, some chemicals evaporate, become part of the atmosphere, and pollute the air.Based on the passage, which resources and organisms are affected by oil spills? Select three options.

a) air
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e) trees on land
f) organisms in the water

Answers

The resources and organisms are affected by oil spillages are Air, Water, and Organisms in water

Effect of oil spillage

Oil spillage can cause to the general environment and the organisms in the environment.

Based on the passage, the resources and organisms are affected by oil spillages include the following;

Air
Water, and
Organisms in water

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Answer:

A,C,F/Air,water,orginisams in water

Explanation:

5.0 liters of a gas are at an initial pressure of 5.0 atmospheres. If the temperature and amount of a gas are kept constant, what is the new volume of the gas when pressure is increased to 7.0 atmospheres?

Answers

Final answer:

Using Boyle's Law of gases which states that the pressure and volume of a gas have an inverse relationship when temperature is kept constant, we find that when the pressure of the gas increases from 5.0 to 7.0 atmospheres, the volume of the gas decreases to approximately 3.57 liters.

Explanation:

The question pertains to the application of Boyle's Law, a fundamental concept in the field of physics dealing with gases. Boyle's Law states that the pressure and volume of a gas have an inverse relationship when the temperature is held constant. This means if the pressure of a gas increases, the volume decreases, and vice versa.

In this case, you have 5.0 liters of a gas under an initial pressure of 5.0 atmospheres. The pressure is then increased to 7.0 atmospheres, and you are asked to determine the new volume of the gas. To solve this problem, we use the formula for Boyle's Law, which is P1V1 = P2V2. We know P1 (initial pressure) is 5.0 atmospheres and V1 (initial volume) is 5.0 liters. P2 (final pressure) is increased to 7.0 atmospheres and V2 (final volume) is what we are trying to find.

So, we plug the numbers into the equation and get: 5.0 atmospheres * 5.0 liters = 7.0 atmospheres * V2. Solving for V2, we find V2 to be approximately 3.57 liters. Therefore, when the pressure of the gas is increased from 5.0 atmospheres to 7.0 atmospheres, the volume decreases to around 3.57 liters, while the temperature remains constant.

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Consider the following reaction: Br2(g) + Cl2(g) ⇌ 2BrCl(g), Kp=1.112 at 150 K.
A reaction mixture initially contains a Br2 partial pressure of 751 torr and a Cl2 partial pressure of 737 torr at 150 K.
Calculate the equilibrium partial pressure of BrCl.

Answers

Answer:

the equilibrium partial pressure of BrCl is pBC = 784.52 torr

Explanation:

Since

Br₂(g) + Cl₂(g) ⇌ 2BrCl(g) , Kp=1.112 at 150 K

denoting BC as BrCl , B as Br₂ , C as Cl₂, p as partial pressure , then

Kp = pBC²/[pB*pC]

solving for pBC

pBC = √(Kp*pB*pC)

replacing values

pBC = √(Kp*pB*pC) = √(1.112*751 torr*737 torr) = 784.52 torr

pBC = 784.52 torr

then the equilibrium partial pressure of BrCl is pBC = 784.52 torr

Final answer:

To calculate the equilibrium partial pressure of BrCl, use the equilibrium constant expression and substitute the given partial pressures of Br2 and Cl2. The equilibrium partial pressure of BrCl is approximately 0.0375 atm.

Explanation:

To calculate the equilibrium partial pressure of BrCl, we need to use the equilibrium constant expression:

Kp = ([BrCl]^2) / ([Br2] * [Cl2])

Given that the equilibrium partial pressures of Br2 and Cl2 are 0.450 atm and 0.115 atm, respectively, we can substitute these values into the expression:

1.112 = ([BrCl]^2) / (0.450 * 0.115)

Simplifying the expression, we find that the equilibrium partial pressure of BrCl is approximately 0.0375 atm.

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Draw a line-bond structure for CBrN. Explicitly draw all H atoms. You do not have to include lone pairs in your answer. In cases where there is more than one answer, just draw one.

Answers

Answer:

Br - C ≡ N

Explanation:

To draw the Lewis line-bond structure we need to bear in mind the octet rule, which states that in order to gain stability each atom tends to share electrons until it has 8 electrons in its valence shell.

C has 4 e⁻ in its valence shell so it will form 4 covalent bonds.

Br has 7 e⁻ in its valence shell so it will form 1 covalent bond.

N has 5 e⁻ in its valence shell so it will form 3 covalent bonds.

The most stable structure that respects these premises is:

Br - C ≡ N

It does not have any H atom.

A single replacement reaction is a reaction in which one element replaces a similar element within a compound. TRUE OR FALSE

Answers

Answer:

true

Explanation:

Which of the following species is amphoteric? A)HCO32- B) HF O C) NH4+ D) P042-

Answers

Answer:

$HCO_(3)^(-)$

Explanation:

Chemical species which can behave as both acids and bases are known as amphoteric species.

$HCO_(3)^(-)$ can behave as both acid and base.

$HCO_(3)^(-)$ can donate H+:

$HCO_3^(-) \rightarrow CO_3^(2-) + H^+$

$HCO_(3)^(-)$ can accept H+ as well:

$HCO_3^(-) + H^+ \rightarrow H_2CO_3$

HF can only behave as acid, as it can only donate H+.

$HF(aq) \rightarrow H^(+)(aq) + F^(-)(aq)$

$NH_4^(+)$ is a conjugate acid of $NH_3$ .

$PO_4^(2-)$ is a conjugate base.

Final answer:

In chemistry, an amphoteric species can act as both a base and an acid. Among the given options, HCO3- (bicarbonate ion) is amphoteric because it can either donate or accept protons.

Explanation:

Among the provided options, the species that are amphoteric are HCO3- (bicarbonate ion). The term amphoteric refers to substances that can act both as an acid and a base. In other words, they can either donate or accept protons. Let's take HCO3- as an example. This ion can act as a base by accepting H+, forming H2CO3, or it can act as an acid by donating H+, forming CO32-. This dual behavior makes it an amphoteric species.