How many grams of acetylene react if 1.10 mol of CO2 are produced?

Answers

Answer 1

Answer: Combustion of acetylene :

molar mass acetylene ( C₂H₂ ) = 26.0 g/mol and CO₂ = 44.0 g/mol

2 C₂H₂ + 5 O₂ ---> 4 CO₂ + 2 H₂O

2 moles C₂H₂ --------> 4 moles CO₂
? moles C₂H₂ --------> 1.10 moles CO₂

moles C₂H₂ = 1.10 * 2 / 4

moles C₂H₂ = 0.55 moles of C₂H₂

Mass acetylene:

m = n * mm

m = 0.55 * 26.0

m = 14.3 g

hope this helps!

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Answers

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Answers

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Answers

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The reaction A→B has been experimentally determined to be second order. The initial rate is 0.0100M/s at an initial concentration of A of 0.300M. Determine the initial rate at [A]=0.900M.

Answers

Answer:

0.09 M/s is the initial rate when concentration of reactant A is 0.900 M.

Explanation:

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Rate constant of the reaction , k = ?

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2) Rate of the reaction when initial concentration of A was 0.900M be R'.

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Answers

The correct answer is physical change does not change the chemical formula of the substance.

What is a physical change?

A physical change is one in which only the physical state of matter is altered.
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Learn more about Physical change here:

brainly.com/question/25014732

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Answer:

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Explanation:

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Answers

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