CHEMISTRY HIGH SCHOOL

My sister is a peach" is a metaphor.

TrueFalse

Answers

Answer 1

Answer: yes that is a metaphor

Answer 2

Answer:

Answer:

True it is a metaphor

Explanation:

Related Questions

Which of the following would you expect to have the highest value for entropy? CO2 (s) H2O (s) CO2 (g) H2O (l)
How many phases does a solution have?explain
What is the molecular weight for H3PO4
6. when multiplying and dividing measured quantities, the number of significant figures in the result should be equal to the number significant figures in___. a) all of the measurements b) at least and most precise measurements c) the most precise measurement d) the least precise measurement
You need to make 3-bromo-5-isopropyltoluene starting with m-isopropyltoluene. Supply the reagent needed in the order it is needed and draw the resulting product.

What occurs when there are oh ions in a solution

Answers

the solution is considered basic. The more H⁺ a solution has the more acidic it is and the more OH⁻ a solution has the more basic it is. pH=-Log[H⁺] and pOH=-log[OH⁻]. pOH+pH=14

What is the chemical formula for one phosphorus atom, three chlorine atoms, one oxygen atom?

Answers

O=PCL3 that is what it is

How much aluminum is needed to replace all of iron from 27.8 g of iron 3 oxide

Answers

You would need 9.40 grams

_____ is the time required for one-half of the atoms of a radioisotope to decay to products. a. fusion
b. radioactivity
c. half-life
d. fission

Answers

C half life..............................

What is the percent composition by mass of nitrogen in NH4NO3 (gram-formula mass = 80.0 grams/mole)?(1) 17.5% (3) 52.5%
(2) 35.0% (4) 60.0%

Answers

Answer:

The correct option is (2) 35.0%

Explanation:

If we want to calculate the percent composition by mass of nitrogen in NH4NO3 we first need to calculate the mass of nitrogen in one mole of NH4NO3.

Because of the molecular form of NH4NO3 (it has 2 ''N'') we know that one mole of NH4NO3 contains 2 moles of N.

The molar mass of N (nitrogen) is $14.0067(g)/(mole)$

This means that 1 mole of N contains 14.0067 grams of N.

Because we have 2 moles of N ⇒ $(2moles).(14.0067(g)/(mole))=28.0134g$

We know that in 1 mole of NH4NO3 we have 2 moles of N(28.0134 g of N).

To calculate the percent composition by mass of nitrogen we need to divide the mass of nitrogen in one mole of NH4NO3 by the mass of one mole of NH4NO3 and then multiply it by 100.

We know that in 1 mole of NH4NO3 there are 80.0 g of NH4NO3 (Because of the molar mass data) ⇒

$((28.0134g)/(80.0g)).100=35.016$ % ≅ 35.0%

We find that the percent composition by mass of nitrogen in NH4NO3 is 35.0%

We conclude that the correct option is (2) 35.0%

gram-formula=80.0grams/mole will be 35.0%

A 700.0 mL gas sample at STP is compressed to a volume of 200.0 mL, and the temperature is increased to 30.0 degrees Celsius. What is the new pressure of gas at kPa?

Answers

According to the ideal gas law, there is equation PV=nRT. So the same gas has the relationship of P1V1/T1=P2V2/T2. The unit of temperature is K. Then the answer is 385.4 kPa.

Final answer:

Using the combined gas law, we find that the new pressure of the gas sample, after it's compressed and heated, is approximately 353.8 kPa.

Explanation:

The subject of this question is gas laws, specifically the combined gas law which states that the ratio of the product of pressure and volume and the absolute temperature of a gas is constant. We apply this law to calculate the new pressure of the gas sample. Starting from the conditions of STP (Standard Temperature and Pressure, defined as 273.15 K and 1 atm i.e., 101.325 kPa), the volume of gas is decreased from 700.0 mL to 200.0 mL and the temperature is increased from 273.15 K to 30.0 degrees Celsius (or 303.15 K in absolute terms).

We set up the equation P1*V1/T1 = P2*V2/T2, where P1 = 101.325 kPa, V1 = 700.0 mL, T1 = 273.15 K, V2 = 200.0 mL, and T2 = 303.15 K. Plugging in these numbers and solving for P2 (the new pressure), we get P2 = P1*V1*T2 / (T1*V2) = 101.325 kPa * 700.0 mL * 303.15 K / (273.15 K * 200.0 mL) = approximately 353.8 kPa.