I don't know what calculation to use, can someone help me?
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Hope this helps
displacement from station A to station B is __km
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Here, we are required to find the magnitude of the bus
displacement from station A to station B.
The magnitude of the bus
displacement from station A to station B is 5km.
The magnitude of the displacement is the "distance between the starting position of a body or object and the end position of that body or object".
The bus moves 4kmnorth and then moves 3km west, forming a right triangle. Its displacement is therefore the length of the hypotenuse.
let
x = length of the hypotenuse.
x² = 3² + 4²
x² = 9 + 16
x² = 25
Then remove the square on x by adding square roots to both sides
√x² = √25
x = √25
x = 5
The magnitude of the bus's displacement from station A to station B is 5 km.
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Explanation:
The magnitude of the displacement is the distance between the starting position and the end position.
The bus moves north, then west, forming a right triangle. Its displacement is therefore the length of the hypotenuse.
x² = 3² + 4²
x = 5
The magnitude of the bus's displacement from station A to station B is 5 km.
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Explanation:
Newton's second law of motion states that when a certain force is acted on an object then it is equal to the mass m of that object multiplied by the acceleration a of the object.
Mathematically, the relation is as follows.
F = m × a
Thus, we can conclude that when an object is acted on by an unbalanced force then the object will start to accelerate.