A flashlight has a resistance of 30 Q and is connectedby a wire to a 90 V source of voltage. What is the
current in the flashlight?

Answers

Answer 1
Answer:

Answer:

3 A

Explanation:

The relationship between voltage, current and resistance in a conductor is expressed by Ohm's law, which states that:

V=RI

where:

V is the potential difference across the conductor

R is the resistance of the conductor

I is the current flowing through it

In this problem, for this flashlight we have:

V = 90 V is the potential difference

R=30 \Omega is the resistance of the flashlight

Solving for I, we find the current:

I=(V)/(R)=(90)/(30)=3 A


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Answers


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Answers

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Answers

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1. 4

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Answers


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