MATHEMATICS HIGH SCHOOL

An infinite geometric series has 1 and 1/5 as its frist two terms:1, 1/5' 1/25' 1/125' what is the sum,s,of the infinite series?A 1/4
B1/25
c 5/4
d 1

Answers

Answer 1
Answer:  you have a geometric series 

since you are summing the powers of 1/5, this converges 
(1/5 < 1) 

it's equal to 1/(1-1/5) 
=1/(4/5) = 5/4 

for geometric series, the sum is always 
x = 1/(1-r) 
where r is the ratio of successive terms. 

if you set the sum equal to x: 
x = 1+r+r^2+r^3... 
and multiply each term by r 
rx= r+r^2+r^3+.... 
then subtract 

x-rx = 1+r-r+r^2-r^2+r^3-r^3+.... 

x-rx = 1 
x(1-r)=1 
x=1/(1-r)

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What multiplies to 42 and adds to -27

Answers

Consider ways to multiply to get 42. Then see if the numbers can be used to make -27.

42 = 21 × 2...not going to work.
42 = 14 × 3...not going to work. (Though -14 and -3 add to -17)
42 = 7 × 6...not going to work.

There are no whole number solutions to this question.

What is the average rate of change of the function f(x)=5(2)^x from x = 1 to x = 5

Answers

f′(x)=5 × 1/(xln2)
use derivation
f′(x)=5 × 1/(xln2) 
u need to use 

The z- score for a mark of 56 in a test with a mean of 60 and standard deviation of 8 is​

Answers

Answer:

z = - .5

Step-by-step explanation:

z = (x - μ)/ σ

z = 56 - 60/8 = -.5

Solve
3/4z-1/3=2/3z+1/5

Answers

3/4z - 1/3 = 2/3z + 1/5
3/4z - 2/3z = 1/5 + 1/3
9/12z - 8/12z = 3/15 + 5/15
1/12z = 8/15
z = 8/15 * 12
z = 96/15 = 32/5 or 6 2/5

Is it

A 180

B 120

C 45

D 60

Answers

Answer:

60° .

.

.

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....................

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The answer is 60.

Since angle 1 and angle three are on the same line they have to have complimentary angles. So, 180 (degrees of a straight line) minus the angle 1 would give:

180 - 120 = 60.

Triangle ABC was rotated clockwise about the originWhat is the degree of rotation to get to A"B"C"?
С
A
A
B
A
o degrees
90 degrees
180 degrees
270 degrees

Answers

Answer:

180 degrees

Step-by-step explanation:

if it was to be 270 degrees the the image should be formed opposite to triangle A'B'C'

If it was to be 360 degrees the image should be back to original triangle and if it was 90 degrees the triangle should be triangle A'B'C'
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5t-2r=25solve for t.