A basketball is shipped in a cube-shaped box. The basketball just want touches the sides of the box. About what percent of the space in the cube is occupied by the basketball?

Answers

Answer 1
Answer: volume
cube and sphere

the diameter of the sphere=height of box=legnth of box=width of box

volume of cube=side^3
volume of sphere=(4/3)pir^3

side=d=2r
Vcube=d^3

vsphere=(4/3)pi(d/2)^3
Vsphere=(pid^3)/6

percent
basketballV/boxV=( (pid^3)/6)/(d^3)=(pid^3)/(6d^3)=pi/3=aprox 0.523599=52.3599% (round if nececary)

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Let f(x)=4x+1 and g(x)=3/4. evaluate each expression symbolically.a) (f+g)(4)b) (f-g)(1/4)c) (fg)(5)d) (f/g)(0)​
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What factor makes the number sentence true 7×4 = ?×7

Answers

The answer is 4. According to the commutative property, you can commutate (swap) numbers over and get the same result. However, it only works for addition and multiplication. For instance, x + y = y + x. Or, x * y = y * x. In our example, we have 7 * 4 = ? * 7. Because we already have 7 on the right side of the expression, the missing number will be 4.

How do you graph 10x-3y=15

Answers

10x-3y=15, this will be:
(15/-3)+(-10/-3)x=y
-5+3x=y.
if you want to graph it, you will draw coefficient 3 in the graph as x=1 from x-axis and y=3 from y-axis. m=-5 in y-axis as graph intersect.
this is an exemple

Round 34.4567 to the nearest cent

Answers

Because 34.4567 is closer to 34.46 than to 34.45, so the answer is 34.46.

SOLVE BY SUBSTITUTION:3x-2y=14
y=5x
solve by substitution
x-2y=-2
y=2x+4
solve by elimination
x+2y=-7
x-5y=7
PLEASE HELP WORTH 10 POINTS! AKA SHOW WORK:)

Answers

1)
3x-2y=14
y=5x

So we plug in y=5x into 3x-2y=14

We get:

3x-2(5x)=14
3x -10x=14
-7x=14
x=-2

So we found x, now we need to find y. We can simply plug in x into the equation and get y.

y=5x
y=5(-2)
y=-10

So your answer will be (-2,-10).

2) 
x-2y= -2
y= 2x+4

Once again plug in y=2x+4 into x-2y=-2

x-2(2x+4) = -2
x-4x-8=-2
-3x-8=-2
-3x = 6
x= -2

Now we plug back in x and solve for y :)

y=2x+4
y=2(-2)+4
y=-4+4
y=0

So our solution would be (-2,0).

3)
x+2y=-7
x-5y=7

Multiply the second equation by -1

-x+5y=-7

Now add that equation with the other one:

   x+2y=-7
+
   -x+5y=-7
-----------------
7y=-14
y=-2

Now plug in y=-2 and solve for x

x+2y=-7
x+2(-2)=-7
x+(-4)=-7
x-4=-7
x=-3

So your solution would be (-3,-2).

1)

3x-2y=14\n \n y=5x

We know y's value. Let's plug it in the equation.

y=5x\n \n 3x-2\cdot (5x)=14\n \n 3x-10x=14\n \n -7x=14

Divide both sides by -7.

x=-2

Now we have x's value. Let's plug it in the equation to find y.

x=-2\n \n y=5x\n \n y=5\cdot -2\n \n y=-10

Solution,

(-2, -10)

2)
x-2y=-2\n \n y=2x+4

Again we have y's value. Let's plug and solve.

y=2x+4\n \n x-2\cdot (2x+4)=-2\n \n x-(2\cdot 2x+2\cdot 4)=-2\n \n x-4x-8=-2\n \n -3x-8=-2\n \n -3x=-2+8\n \n -3x=6\n \n x=\frac { 6 }{ -3 } \n \n x=-2

Now we have x's value let's solve for y.

x=-2\n \n y=2x+4\n \n y=2\cdot (-2)+4\n \n y=-4+4\n \n y=0

Solution,

(-2, 0)

3)

x+2y=-7\n \n x-5y=7

Let's first multiply the first equation by -1

-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7

Then let's add these new equation and the second equation.

-1\cdot (x+2y)=-1\cdot -7\n \n -x-2y=7\n \n x-5y=7\n \n (-x-2y)+(x-5y)=7+7\n \n -x+x-2y-5y=14\n \n -7y=14\n \n y=\frac { 14 }{ -7 } \n \n y=-2

Now we have y's value let's plug it and solve for x.

y=-2\n \n x+2y=-7\n \n x+2\cdot (-2)=-7\n \n x-4=-7\n \n x=-7+4\n \n x=-3

Solution,

(-3, -2)


1.Find the constant of variation for the relationship f(x)= 30x.  A.10  B.30  C.x  D.f(x)
2.Find the constant of variation for the relationship shown in the following table:
 
x 1 2  3  4
y 4  8 12 16
 
  

A.
1
  B.2  C.3  D.4

3.If f(x) varies directly with x, and f(x) = 8 when x = 6, write the direct linear variation equation.  A. f(x) = x  B.f(x) = 6x  C.f(x) = 8x  D.f(x) = x

4.If f(x) varies directly with x, and f(x) = 56 when x = 8, find the value of f(x) when x = 2  
A.
4
  B.7  C.8  D.14

5.
Which does not show a direct variation between x and y? 
 A.
y = 
  B.y = 2x  C.y = 0.5x  D.y = 

Answers

(1)\n f(x)=30x\ \ \ \Leftrightarrow\ \ \ (f(x))/(x) =30\ \ \ \Rightarrow\ \ \ constant=30\ \ \ \Rightarrow\ \ \ Ans.\ B.\n\n(2)\nconsatnt= (y)/(x) = (4)/(1) =4\ \ \ \Rightarrow\ \ \ Ans.\ D.\n\n(3)\nf(x)=m\cdot x\ \ \ and\ \ \ f(6)=8\n\nm\cdot6=8\ \ \ \Rightarrow\ \ \ m= (8)/(6) = (4)/(3) \ \ \ \Rightarrow\ \ \ y= (4)/(3)x\ \ \ \ Ans.\ (?)

(4)\nf(x)=m\cdot x\ \ and\ \ f(8)=56\n\nm\cdot8=56\ \ \Leftrightarrow\ \ m= (56)/(8) =7\ \ \Rightarrow\ \ \ f(x)=7x\ \ \ \Rightarrow\ \ \ f(2)=7\cdot2=14\n\nAns.\ D.\n\n(5)\ndirect:\ \ y=m\cdot x\ \ \ and\ \ \ m\in R\ne.g.:\ \ y=2x,\ \ y=0.5x,\ \ y= (x)/(7)= (1)/(7)x,\ ...\n\nNOT\ direct:\ \ \ e.g.:\ \ y= √(x) ,\ \ y= (1)/(x),\ \ y=x^2,\ ...

the answer is D i have this test and its the right answer for 2 reasons

1,its the only thing that looks like english

2,its always the right answer in anime logic

A rational number can be written as the ratio of one blank to another and can be represented by a repeating or blank decimal

Answers

we know that

A rational number is the quotient of two integers with a denominator that is not zero , and can be represented by a repeating or terminating decimal.

Repeating Decimal is a decimal number that has digits that go on forever

Terminating decimal is a decimal number that has digits that do not go on forever.

examples

(1)/(3) = 0.333... (the 3 repeats forever)----> Is a Repeating Decimal

0.25 (it has two decimal digits)----> Is a Terminating Decimal

therefore

the answer is

A rational number can be written as the ratio of oneinteger to another and can be represented by a repeating or terminating decimal

A rational number can be written in the form:

(p)/(q); \ called \ the \ ratio \n \n where \ p \ and \ q \ are \ whole \ numbers

The number $q$ isn't equal to zero because the division by zero is not defined. So we can represent rational numbers by a repeating or terminating decimal, for instance in the following four exercises we have:

(2)/(3)=0.6666...=0.\stackrel{\frown}{6} \n \n (5)/(8)=0.625000...=0.625\stackrel{\frown}{0} \n \n (3)/(1)=3.000...=3.\stackrel{\frown}{0} \n \n (3446)/(2475)=1.392323...=1.39\stackrel{\frown}{23}