Why do minor parties have difficulty succeeding in the United States electoral system? A. tend to focus on only a single issue B. quickly join forces with the wrong party C. views are usually tied to strict religious doctrine D. seldom are given the respect from foreign officials they need to get elected

Answers

Answer 1
Answer: I think the best answer is D. Minor parties do not always get a support from foreign officials in order for them to get elected. They also have difficulties because they are a small political party. They do not have enough resources or supporters as compared to larger political parties.

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Why check dams can increase the groundwaater level in a region

The Suns ultraviolent Rays can cause skin damage including sunburn and even skin

Answers

yes , because UV rays are super harmful , the reason why you'd apply sun screen . The UV rays are blocked by the ozone layer , except when there is too much of global warming. 

At STP, oxygen exists in two forms, O2(g) and O3(g). These two forms of oxygen have 1. different molecular structures and different properties 2. different molecular structures and the same properties 3. the same molecular structure and different properties 4. the same molecular structure and the same properties

Answers

Answer: option 1. different molecular structures and different properties.

Explanation:

1) O₂ and O₃ are different forms of the same element, in the same physical state (gaseous).

2) That is what is called allotropes.

3) The definition of allotropes is different forms of an element with different structures and different properties in the same physical state.

Graphite and diamond is other example of common allotropes.

4) O₃ and O₂ have the same kind of atoms (oxygen), but they are bonded differently (different structure, one molecule has 3 atoms, other 2 atoms) which conferes them different properties (e.g. different odor, different chemical reactivity).

At STP, oxygen exists in two forms, O2(g) and O3(g). These two forms of oxygen have different molecular structures and different properties. The answer is number 1. The rest of the numbers do not answer the question above.

The specific heat of a solution is 4.18 J/(g•°C)and its density is 1.02 g/mL. The solution is formed by combining 25.0 mL of solution A with 25.0 mL of solution B with each solution initially at 21.4°C. The final temperature of the combined solution is 25.3°C. Calculate the heat of reaction, q, assuming no heat loss due to the calorimeter. I got 831 J
The part I cannot figure out is the question afterwards which is If the calorimeter has a heat capacity of 8.20 J/°C and a correction is included to account for the heat absorbed by the calorimeter what is the heat of reaction q

Answers

Answer:

a. qrxn = 831 J

b. 863 J

Explanation:

we know that density is the mass of a substance per unit volume

d=mass/volume

the volume of the solution is the combination of solution A and solution B

1.02 g/mL=mass/(25+25)

mass=50*1.02

mass=51g

Recall that Q=mCdT

mass=m, C=specific heat capacity

dT=change in temperature

qrxn = (51 g)(4.18 J/g⋅°C)(25.3 °C - 21.4 °C)

qrxn = 831 J

2.Heat=Heat capacity *change in temperature

qcal = (8.20 J/°C)((25.3 °C - 21.4 °C)

qcal = 31.98 J

qrxni + qcal = qrxn

qrxn = 831 J + 32.0 J

863 J------Heat of reaction

863 J =(51 g)(Heat Capacity)(25.3 °C - 21.4 °C)

4.34 J/g⋅°C

Okay, so, to solve for this, we're going to have to use q = mcΔT. However, the mass of the calorimeter is not important because not of it is used in the reaction, so really, we are only looking at 2 things, the temperature change and specific heat. So, here is the lightly modified equation we will use:
q = cΔT

Now, just plug in the ΔT we had for the original equation (which was 3.9) and use the specific heat of the calorimeter to get q.

q = (8.20) * (3.9)
q = 31.98, or about 32

The 32 is what was absorbed by the calorimeter, so we can add that to the original value to get our answer.
831 + 32 = 863 J

So, the answer is 863 J

Hope this helped!! :D

Based on the Periodic Table, explain why Na and Khave similar chemical properties

Answers

The Group 1 elements, which include lithium (Li), sodium (Na) and potassium (K) are also known as the alkali metals. They all have one electron in the outer shell and so they have similar properties.

Calculate the density of a rectangular metal bar that is 7.00 cm long, 4.00 cm wide, and 1.00 cm thick and has a mass of 352 g is?

Answers

Density is mass divided by volume (d=m/v)
To calculate volume you multiply the length, width, and height of the object (v=lwh)
In this example, we get a product of 28
So 352/28 is 12.57142.... Round to the nearest decimal place indicated in your instructions or keep as is

Answer:

12.58 g/cm³

Explanation:

V = 7×4×1 = 28cm³

ρ = m/V = 352/28 ≈ 12.58 g/cm³

Compounds have similar properties to the elements of which they are made.For example, FeS is magnetic and smelly, since iron (Fe) and sulfur (S) are attracted to a magnet, and possess an odor of eggs,
respectively

True
False​

Answers

Answer:

false

Explanation:

The properties of compounds are often very different from the properties of the elements that make them. For example, water is made from two atoms of hydrogen bonded to one atom of oxygen. ... The elements calcium and chlorine combine to form the compound calcium chloride. Calcium is a soft, silvery metallic solid.

Answer:

the answer is False

Explanation:

False

Hope this helps