This experiment involves the reaction of Ba(OH)2 with H2SO4. Which of the following gives the balanced chemical reaction used in the experiment?Ba(OH)2 (aq) + H2SO4(aq) → H2Ba(s) + SO4(OH)2(l)
Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + H2O(l)
BaSO4(s) + 2 H2O(l) → Ba(OH)2 (aq) + H2SO4(aq)
Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + 2 H2O(l)
Answers
Answer:
Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + 2 H2O(l)
That's the right one.
Explanation:
You should see that this equation is balanced, not as
Ba(OH)2 (aq) + H2SO4(aq) → BaSO4(s) + H2O(l)
(on reactive we have 4 H, on products, we have only 2)
Ba(OH)2 (aq) + H2SO4(aq) → H2Ba(s) + SO4(OH)2(l)
(this is impossible, it's a nonsense)
BaSO4(s) + 2 H2O(l) → Ba(OH)2 (aq) + H2SO4(aq)
(it is the same with the right one but is the other way around. The statement says, reaction of Ba(OH)2 with H2SO4, not BaSO4 with water. Also, it is not a chemical balance.
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Answers
Answer:
5.2 × 10²² particles NaCl
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
5.0 g NaCl
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Na - 22.99 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol
Step 3: Convert
= 5.15229 × 10²² particles NaCl
Step 4: Check
We are given 2 sig figs. Follow sig fig rules and round.
5.15229 × 10²² particles NaCl ≈ 5.2 × 10²² particles NaCl
Answers
Answer:
Explanation:
Hello,
In this case, considering the reaction, we can compute the Gibbs free energy of reaction at each temperature, taking into account that the Gibbs free energy for the diatomic element is 0 kJ/mol:
Thus, at 2000 K:
And at 3000 K:
Next, since the relationship between the equilibrium constant and the Gibbs free energy of reaction is:
Thus, at each temperature we obtain:
In such a way, we can also conclude that at 2000 K reaction is unfavorable (K<1) and at 3000 K reaction is favorable (K>1).
Best regards.
Answers
Technically, there are an infinite number of possible amino acids, though we've found only 20 common ones that many organisms use and at least half a dozen obscure ones that specific organisms use. We focus only on the 20 common ones unless we're in a college level biochemistry course.
The three categories are nonpolar ones, polar ones, and charged ones. The nonpolar ones have non-polar side chains (no oxygens or nitrogens), the polar ones have polar side chains (most contain an OH group but no COOH group), the charged ones are either acidic or basic (has COOH group or a basic nitrogen).
Answers
Answer:
0.41 M
Explanation:
A -> B
rate constant (k) = 0.039L/mol s
t = 23
Final concentration, [A] = 0.30M
Initial concentration, [A]o = x
1 / [A] = kt + 1 / [A]o
1 / [A]o = 1 / [A] - kt
1 / [A]o = 1 / 0.30 - 0.039 (23)
1 / [A] = 3.33 - 0.897 = 2.433
[A] = 0.41 M
SpongeBob
SpongeBob
Patrick
Patrick
Larry
Answers
Final answer:
In the experiment, SpongeBob is the control group because regular lotion is used instead of the muscle cream. This allows a comparison with Patrick(rightly known as the experimental group) who uses the special muscle cream.
Explanation:
In the given scenario, SpongeBob represents the control group. In any experiment, the control group is the one that is kept normal or unchanged to be able to compare the effects of the variable being tested. In this case, it's the use of the special muscle cream. Patrick, whose arms and back are lathered with the muscle cream before each session, represents the experimental group because he is exposed to the variable being tested, which is the muscle cream. On the other hand, SpongeBob, who is given regular lotion instead of the special muscle cream, is part of the control group because he helps to provide a baseline for comparison.
Learn more about Control Group here:
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Answers
As per the balanced equation the amount of hydrogen peroxide required completely reacts with 265 g of lead sulphide is 150.6 g.
What is hydrogen peroxide ?
Hydrogen peroxide is covalent compound formed by two hydrogen and two oxygens. It is used as an oxidising agent. Hydrogen peroxide reacts with lead sulphide to give lead sulphate and water and the balanced reaction is given below:
As per the balanced equation 4 moles of hydrogen peroxide is required to react with one mole of lead sulphide. One mole of lead sulphide is 239.30 g and one mole of hydrogen peroxide is 34 g/mol
4 moles of hydrogen peroxides weighs 4 ×34 = 136 g. Thus, 136 g of hydrogen peroxide is needed for 239.3 g of PbS. Therefore, the mass of hydrogen peroxide needed to react with 265 g of PbS is calculated as follows:
mass = (136 ×265 g ) / 239.3
= 150.6 g.
Hence, amount of hydrogen peroxide required completely reacts with 265 g of lead sulphide is 150.6 g.
To find more about hydrogen peroxide, refer the link below;
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