B. There are two carbon atoms and a double carbon bond.
C. There are three carbon atoms and a double carbon bond that starts on the second carbon atom.
D. There are four carbon atoms and a double carbon bond that starts on the second carbon atom.
Gradpoint answer: a four-carbon hydrocarbon with a double bond between the second and third carbon atoms
(2) 1670 J (4) 11 300 J
Answer:
It’s 2)
Explanation:
(2) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
(3) N2(g) + 3H2(g) → 2NH3(g)
(4) N2(g) + O2(g) → 2NO(g)
Answer:
4) N2(g) + O2(g) → 2NO(g)
Explanation:
In a chemical equation, the location of the word "heat" can be used to quickly determine whether the reaction is endothermic or exothermic. If heat is released as a product of the reaction, the reaction is exothermic. If heat is listed on the side of the reactants, the reaction is endothermic.
However in the options given, heat was not mentioned. this means we would have to undergo elimination process.
Option 2 represents combustion of methane, heat is a natural by product of any combustion reaction. hence, the correct answer cannot be 2.
Option 1 - The C=O bonds in CO2 have a high bond energy (the energy you would need to break them) which is more than either of the C-C or O=O bonds in the elements and their sum. Thus to create C and O2 from CO2 you would have to put in energy to break the two C=O bonds. You would get some back from the C-C and O=O bonds but less. Thus you need to add a lot of energy to convert CO2 into its elements. (You can decompose it at high temperatures.)
The reverse process gives off heat. So again, the correct answer cannot be 1.
Option 3 - The heat of formation of H2 ( g ) and N2( gas) under the standard condition is zero ( 0), and heat of formation of NH3 ( g ) is -46.11 kj / mol, so for the formation of 2 moles of NH3( g ) it would be - 92.22 kj,
The -ve symbol is indicative of the above reaction is exothermic in nature. So again, the correct answer cannot be 3.
Our only option left is 4 - The standard enthalpy of formation of nitric oxide (NO) in the gas phase is about +90 kJ/mol, which is endothermic. The primary reason for this is that the nitrogen-nitrogen triple bond is very strong (941 kJ/mol). The energy cost to break that bond as well as the oxygen-oxygen double bond (495 kJ/mol) is not compensated by the forming of the nitrogen-oxygen double bond (607 kJ/mol). Endothermic reactions are the result of breaking strong bonds and forming weaker ones.
70 Determine the number of moles of copper in the bracelet. [1]
71 Show a numerical setup for calculating the amount of heat released by the bracelet as it cooled on the desk. [1]
72 Explain, in terms of chemical activity, why copper is a better choice than iron to make the bracelet. [1]
69. The student's skin was obviously warmer than the initial temperature of the bracelet. According to the second law of thermodynamics, heat transfers from a higher temperature to a lower temperature. Hence, heat transfers from the student's skin to the bracelet warming up the bracelet.
70. To determine number of moles of copper:
Given mass=30.1 grams
Molar mass= 63.55 g/mol
Thus, the number of moles of copper is 0.4736.
71. Calculating the amount of heat released:
ΔH( heat released) = m Cp(ΔT)
= 30.1g(0.385 J/g. K)(33-19)K
ΔH= 162.23J
Thus, the amount of heat released is 162.23 J.
72. Copper is chemically less active than iron.
Copperdoes notdisplace iron from its solution since it is less reactive than iron. A more reactive metal displaces a less reactive metal from its solution.
Learn more:
Which of the following tasks might they ask a
chemist to do? Explain your answer.
a. Determine the materials used to make the pots.
b. Explain what the designs on the pots represent.
c. Recommend how to store the pots to prevent
further damage.
Answer:
a. Determine the materials used to make the pots.
Explanation:
Workers digging a tunnel through a city who find some ancient pots decorated with geometric designs will employ the services of a chemist.
The chemist would help to determine the materials which were used to make the pots . This is usually done by various type of experiments and observations. After the constituent of the pot is gotten then more information would be derived from the possible source and use of the pot