Rod is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than usual. When he weighs one of the sticks, he finds that it is 2.66 oz. The manufacturer's website states that the average weight of each stick is 2.25 oz with a standard deviation of 0.17 oz. Assume that the weight of the drumsticks is normally distributed.What is the probability of the stick's weight being 2.66 oz or greater

Answers

Answer 1

Answer:

Answer: 0.0080

Step-by-step explanation:

Given : The manufacturer's website states that the average weight of each stick is $\mu=2.25$ oz with a standard deviation of $\sigma=0.17$ oz.

We assume the weight of the drumsticks is normally distributed.

Using formula $z=(x-\mu)/(\sigma)$ , the z-value corresponds x=2.66 will be :-

$z=(2.66-2.25)/(0.17)\approx2.41$

By using the standard normal distribution table for z, we get

P-value = $P(z\geq2.41)=1-P(z<2.41)$

$\n\n=1-0.9920237=0.0079763\approx0.0080$

Hence, the probability of the stick's weight being 2.66 oz or greater=0.0080

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Answers

Hey there!

The “average” is your “total” or your “mean” of a data set. To find out the average you have to ADD the total numbers in your data & DIVIDE it by the amount of numbers you have in your data.

EXAMPLE:

SET:

10, 20, 30, 40, 50, 60

EQUATION: 10 + 20 + 30 + 40 + 50 + 60 / 6

10 + 20 + 30 + 40 + 50 + 60 / 6

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An advertising agency is estimating costs for promoting a music festival. The job will require 200 direct labor hours at a cost of $50 per hour. Overhead costs are applied at a rate of $65 per direct labor hour.1. What is the total estimated cost for this job?
2. If the company applies a markup of 20% of total costs (price quote is 120% of total costs), what price should it quote for this job?

Answers

Answer:

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Step-by-step explanation:

To find the total cost of the job, we do the equation: $50 x 200

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Answers

Answer:

Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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