Arc Length and Radians question- please help! Will mark brainliest! Is 20pts!The answer is shown but please give me an explanation so I can show my work!
Answers
Answer:
59
Step-by-step explanation:
If we convert from degrees into radians, we can use the formula
, where s is the arc length, r is the radius and θ is the angle in radians.
To convert from degrees to radians, we multiply by
So is our angle in radians, and we have the radius - we can now plug in these two values into our equation.
Answer:
Step-by-step explanation:
length of arc= (arc angle/360) * 2πr
length= 140/360 *2*22/7*24
length=58.88 feet ~59 feet(approx)
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Insert < or > to form a true statement -17/18,3/5
Answers
Answer:
B.
Step-by-step explanation:
In the attached file
Answer:
B
Step-by-step explanation:
I put the answer in an atachement
Answers
Answer:
(m-(1/3))(m^2+(1/3)m+(1/9)
Step-by-step explanation:
Just use the difference of cubes
Please show your work, thank you.
Answers
x=-6*-4=24
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Answer:
95.02% of squirrels have a weight between 3 and 5 pounds.
Step-by-step explanation:
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 4.1 pounds
Standard Deviation, σ = 0.5 pounds
We are given that the distribution of weight is a bell shaped distribution that is a normal distribution.
Formula:
P(weight between 3 and 5 pounds)
95.02% of squirrels have a weight between 3 and 5 pounds.
Final answer:
Using the concepts of normal distribution and Z-scores, it is found that approximately 95% of the squirrels have weights between 3 and 5 pounds.
Explanation:
The problem involves the use of the concept of normal distribution in statistics. In this case, we have a mean of 4.1 pounds and a standard deviation of 0.5 pounds. We have two weight points, namely 3 pounds and 5 pounds. To find out the percentage in this interval, we need to convert the weights into z-scores, which standardizes them. The formula for this is Z = (X - μ) / σ, where X is the weight point, μ is the mean, and σ is the standard deviation.
The Z-score for 3 pounds is Z1 = (3 - 4.1) / 0.5 = -2.2, and the Z-score for 5 pounds is Z2 = (5 - 4.1) / 0.5 = 1.8. Looking these Z-scores up in the standard normal table (or using a calculator with a normal distribution function), we get 0.9857 for Z1 and 0.9641 for Z2. The difference between these values gives the percentage of squirrels within the interval, which is 0.9641 - (1 - 0.9857) = 0.950 or 95%. Hence, approximately 95% of the squirrels have a weight between 3 and 5 pounds.
Learn more about Normal Distribution here:
#SPJ3
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Answers
a. 297
b. 567
c. 837
d. I added the tens together and the units
4. a. 10
i don't know the rest
5. a. 0.68
b. 1.34
6. a. ???
b. 1 2/5
7. a. 0.50 - 1 - 06.00? - 700.00
b. 0.80 - 9 - 31.00? - 600.00
I think that's correct ;)