Blue ribbon taxis offers shuttle service to the nearest airport. You loop up online reviews for blue ribbon taxis and find that there are 17 reviews, six of which report that the taxi never showed up. Is this a biased sampling method for obtaining customer opinion on the taxi service?
If so, what is the likely direction of bias?
explain your reasoning carefully.

Answers

Answer 1

Answer:

Answer:

In order for a sample to be considered biased, some members of the total population must have either a larger or lower chance of being included in the sample. In this case, your sample contained 17 reviews. It is biased because it was completely voluntary and customers who have a bad experience with a product or service generally tend to express more their dissatisfaction than satisfied customers show their satisfaction.

In marketing, there is a saying that unsatisfied clients talk bad about our product or service 4 times more than satisfied clients. I'm not sure if this saying is exact or not, but all marketing research point in the same direction.

This means that clients that did not get a good service or got no service at all, are more likely to post a review about the company than clients who got a good service. This is what makes the sample biased.

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1260=(n-2)x180find the value of ncan you please give me a explaination

Someone please give me all the answers!

Answers

Answer:

Step-by-step explanation:

1.=71

2.=25

3.=28

4.=15 (is the sybmbol at the end is division it is 8)

5.=68/17

6.=48/9

7.=96 (if the symbol at the end is division it is 106)

8.=30

Suppose you have a random variable that is uniformly distributed between 80 and 667. What is the probability of observing a random draw greater than or equal to 314? Answer to three decimal place if necessary.

Answers

Answer:

P(x>=314) = 354/588 = 0.602

Step-by-step explanation:

At first, we will find the sample space S

S = 667-80+1. i.e 80 and 667 are included

S= 588, so we have total of 588 numbers in the series

now comes the number greater or equal to 314

we will get total of 354 number greater than or equal to 314

x = 667-314+1 = 354

p( number >= 314) = (numbers >= 314)/total sample space

p= 354/588

p= 0.602

Calculate S37 for the arithmetic sequence in which a7 = 25 and the common difference is d=-1.7

Answers

The value of 37th term of the arithmetic sequence will be;

⇒ - 26

What is Arithmetic sequence?

An arithmetic sequence is the sequence of numbers where each consecutive numbers have same difference.

Given that;

The values are,

⇒ a₇ = 25

And, The common difference is d = -1.7

Now,

Since, The nth term of arithmetic sequence is;

⇒ a(n) = a + (n - 1)d

And, ⇒ a₇ = 25

So, We get;

⇒ a₇ = a + (7 - 1) (- 1.7)

⇒ 25 = a + 6 × - 1.7

⇒ 25 = a - 10.2

⇒ 25 + 10.2 = a

⇒ a = 35.2

So, The 37th term of the arithmetic sequence is;

⇒ a₃₇ = 35.2 + (37 - 1) (- 1.7)

⇒ a₃₇ = 35.2 + 36 × - 1.7

⇒ a₃₇ = 35.2 - 61.2

⇒ a₃₇ = - 26

Thus, The value of 37th term of the arithmetic sequence will be;

⇒ - 26

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Answer:

-26

Step-by-step explanation:

25 is a7. if you subtract 1.7 each time then at 37 the number will be -26.

Consider the following functions. f(x) = x − 3, g(x) = x2 Find (f + g)(x). Find the domain of (f + g)(x). (Enter your answer using interval notation.) Find (f − g)(x). Find the domain of (f − g)(x). (Enter your answer using interval notation.) Find (fg)(x). Find the domain of (fg)(x). (Enter your answer using interval notation.) Find f g (x). Find the domain of f g (x). (Enter your answer using interval notation.)

Answers

Answer:

$(f+g)(x)=x-3+x^2$ ; Domain = (-∞, ∞)

$(f-g)(x)=x-3-x^2$ ; Domain = (-∞, ∞)

$(fg)(x)=x^3-3x^2$ ; Domain = (-∞, ∞)

$((f)/(g))(x)=(x-3)/(x^2)$ ; Domain = (-∞,0)∪(0, ∞)

Step-by-step explanation:

The given functions are

$f(x)=x-3$

$g(x)=x^2$

$(f+g)(x)=f(x)+g(x)$

Substitute the values of the given functions.

$(f+g)(x)=(x-3)+x^2$

$(f+g)(x)=x-3+x^2$

The function $(f+g)(x)=x-3+x^2$ is a polynomial which is defined for all real values x.

Domain of (f+g)(x) = (-∞, ∞)

$(f-g)(x)=f(x)-g(x)$

Substitute the values of the given functions.

$(f-g)(x)=(x-3)-x^2$

$(f-g)(x)=x-3-x^2$

The function $(f-g)(x)=x-3-x^2$ is a polynomial which is defined for all real values x.

Domain of (f-g)(x) = (-∞, ∞)

$(fg)(x)=f(x)g(x)$

Substitute the values of the given functions.

$(fg)(x)=(x-3)x^2$

$(fg)(x)=x^3-3x^2$

The function $(fg)(x)=x^3-3x^2$ is a polynomial which is defined for all real values x.

Domain of (fg)(x) = (-∞, ∞)

$((f)/(g))(x)=(f(x))/(g(x))$

Substitute the values of the given functions.

$((f)/(g))(x)=(x-3)/(x^2)$

The function $((f)/(g))(x)=(x-3)/(x^2)$ is a rational function which is defined for all real values x except 0.

Domain of (f/g)(x) = (-∞,0)∪(0, ∞)

$(f + g)(x) = x^2 + x - 3$ , domain: all real numbers.

$(f - g)(x) = -x^2 + x - 3$ , domain: all real numbers.

$(fg)(x) = x^3 - 3x^2$ , domain: all real numbers.

$f(g(x)) = x^2 - 3$ , domain: all real numbers.

To find (f + g)(x), we need to add the functions f(x) and g(x).

The function f(x) = x - 3 and the function $g(x) = x^2.$

So, $(f + g)(x) = f(x) + g(x) = (x - 3) + (x^2).$

Expanding this equation, we get $(f + g)(x) = x^2 + x - 3.$

To find the domain of (f + g)(x), we need to consider the domain of the individual functions f(x) and g(x).

Since both f(x) = x - 3 and $g(x) = x^2$ are defined for all real numbers, the domain of (f + g)(x) is also all real numbers.

To find (f - g)(x), we need to subtract the function g(x) from f(x).

So, $(f - g)(x) = f(x) - g(x) = (x - 3) - (x^2).$

Expanding this equation, we get $(f - g)(x) = -x^2 + x - 3.$

The domain of (f - g)(x) is also all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find (fg)(x), we need to multiply the functions f(x) and g(x).

So, $(fg)(x) = f(x) * g(x) = (x - 3) * (x^2).$

Expanding this equation, we get $(fg)(x) = x^3 - 3x^2.$

The domain of (fg)(x) is all real numbers, since both f(x) and g(x) are defined for all real numbers.

To find f(g(x)), we need to substitute g(x) into the function f(x).

So, $f(g(x)) = f(x^2) = x^2 - 3.$

The domain of f(g(x)) is also all real numbers, as $g(x) = x^2$ is defined for all real numbers, and f(x) = x - 3 is defined for all real numbers.

In summary:

- $(f + g)(x) = x^2 + x - 3$ , domain: all real numbers.

- $(f - g)(x) = -x^2 + x - 3$ , domain: all real numbers.

- $(fg)(x) = x^3 - 3x^2$ , domain: all real numbers.

- $f(g(x)) = x^2 - 3$ , domain: all real numbers.

To Learn more about real numbers here:

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Find the critical points, domain endpoints, and local extreme values for the functiony=x^2/5(x+3)

a. What is/are the critical point(s) and domain endpoint(s) where f' is undefined?
b. What is/are the critical point(s) and domain endpoint(s) where f' is 0?
c. From the critical point(s) and domain endpoint(s), what is/are the points corresponding to local maxima?
d. From the critical point(s) and domain endpoint(s), what is/are the points corresponding to local minima?

Answers

Answer:

a) $x = -3$ , b) $x = 0$ , $x = -6$ , c) $x = 0$ , d) $x = -6$

Step-by-step explanation:

a) Let derive the function:

$f'(x) = (10\cdot x \cdot (x+3)-5\cdot x^(2))/(25\cdot (x+3)^(2))$

$f'(x)$ is undefined when denominator equates to zero. The critical point is:

$x = -3$

b) $f'(x) = 0$ when numerator equates to zero. That is:

$10\cdot x \cdot (x+3) - 5\cdot x^(2) = 0$

$10\cdot x^(2)+30\cdot x -5\cdot x^(2) = 0$

$5\cdot x^(2) + 30\cdot x = 0$

$5\cdot x \cdot (x+6) = 0$

This equation shows two critical points:

$x = 0$ , $x = -6$

c) The critical points found in point b) and the existence of a discontinuity in point a) lead to the conclusion of the existence local minima and maxima. By plotting the function, it is evident that $x = 0$ corresponds to a local maximum. (See Attachment)

d) By plotting the function, it is evident that $x = -6$ corresponds to a local minimum. (See Attachment)

PLS HELP BEST ANSWER GETS BRAINLIEST\A dog needs 4/3 liters of water for 2/5 of a day. How many liters of water does the dog need for an entire day? *

Answers

Answer:

A dog needs 4/3 liters of water 2/5 of a day, Therefore

he'll need 4/3 liters for 5/2 day or

4/3 * 5/2 = 20/6 = 10/3 liters or 3 and 1/3 liters per day

Step-by-step explanation:

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Points are identified in pictures by