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Answer 1

Answer: Your answer is correct! Of the students who live more than one mile away, about 32% ride a bike!

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A construction worker tosses a brick from a tall building. The brick's height (in meters above the ground) t tt seconds after being thrown is modeled by h ( t ) = − 5 t 2 + 20 t + 105 h(t)=−5t 2 +20t+105h, left parenthesis, t, right parenthesis, equals, minus, 5, t, squared, plus, 20, t, plus, 105 Suppose we want to know the height of the brick above the ground at its highest point. 1) Rewrite the function in a different form (factored or vertex) where the answer appears as a number in the equation. h ( t ) = h(t)=h, left parenthesis, t, right parenthesis, equals 2) At its highest point, how far above the ground was the brick?
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Answer:

Step-by-step explanation:

$2(3x-7)=4x+8\nx=11\n4(11)+8=52$

Y=3x 2x+y=15
Can you please help with this? It's confusing. It's soling systems of equations by substitution

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so you subtitute y=3x into
2x+y=15
so
2x+(3x)=15
add like terms
5x=15
divide both sides by 5
x=3

subtitute x=3 into first equation (y=3x)
y=3(3)
y=9

it's simple jus plug in 3x into Y and u will have 2x+3x=15
5x=15
the answer(x=3)

Which expression is equivalent to 9^-2?
–81
–18
1/81
1/18

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Answer:

Step-by-step explanation:

The given expression is:

$f(x)=9^-2$

Upon solving the above expression, which can be written as:

$f(x)=({(1)/(9)})^2$

$f(x)={(1)/(81)}$

which is same as the expression given in the option (C) that is $f(x)={(1)/(81)}$ , hence the option C is correct.

(9)^-2 = (1/9)^2 = 1/81

What comes after 2- on the number line

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Answer:

If you're going to the left, 1, if you're going to the right 3.

If you meant to write -2, then to the left -3 and to the right =-1

<-------------------------------------------------------------->

-3 -2 -1 0 1 2 3

If you’re going to the left of the number line -3 comes after but if you’re going to the right -1 comes after

If a cube has a volume of 343 cubic yards, what is its surface area?

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hope this helps-------------

Pls help....................

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$b^2+6b=0\nb(b+6)=0\nb=0 \vee b=-6\n\n5x^2-5x=0\n5x(x-1)=0\nx=0 \vee x=1\n\n-10x+35x=0\n25x=0\nx=0\n\n2x+15x=0\n17x=0\nx=0\n\n18x^2+6x=0\n6x(3x+1)=0\nx=0 \vee x=-(1)/(3)\n\n-32x^2-24x=0\n-8x(4x+3)=0\nx=0 \vee x=-(3)/(4)$

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Ok what next helppp i need 2

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