How is a combustion reaction like the respiration reaction? list as many similarities as you can

Answers

Answer 1

Answer: They both have produce oxides, use up oxygen, and release energy as well.

Related Questions

Through the process of transpiration, plants do what?
If an object is to rest on an incline without slipping, then friction must equal the component of the weight of the object parallel to the incline. This requires greater and greater friction for steeper slopes. Show that the maximum angle of an incline above the horizontal for which an object will not slide down is θ.
when the temperature of the air is 25 degrees Celsius the velocity of a sound wave traveling through the air is approximately
True or false : Scientific theories have withstood the test of time and are accepted as proven fact.
What is the definition of dynamics in physics

How do the units of work and power compare? a) The unit for work is a watt. The unit for power is a joule, which is a watt-second. b)The unit for work is a watt. The unit for power is a joule, which is a watt per second. c)The unit for work is a joule. The unit for power is a watt, which is a joule-second.
d)The unit for work is a joule. The unit for power is a watt, which is a joule per second.

Answers

Answer:

Option (d) is correct.

Explanation:

Work done is given by :

W = Fd, where F is force and d is displacement

Unit of work done :

The SI unit of force is Newton (N) and that of displacement is meter (m). So, the unit of work done is N-m. It is call Joule. It means that the unit of work done is Joule.

Power is given by rate at which the work is done. It is given by :

P = W/t, W is work done and t is time

Unit of power:

Unit of work is Joule (J) and that of time is second (s). It means that the unit of power is Watt and it is equal to Joule/second

Hence, the correct option is (d) "The unit for work is a joule. The unit for power is a watt, which is a joule per second".

Answer: The unit for work is a joule. The unit for power is a watt, which is a joule per second.

Explanation:

A spherical raindrop 2.7 mm in diameter falls through a vertical distance of 3950 m. take the cross-sectional area of a raindrop = πr2, drag coefficient = 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m3. (a) calculate the speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag.

Answers

Final answer:

The speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag is calculated by firstly finding the time it takes for the raindrop to fall this distance using equations of motion, and then using this time in the equation for final velocity. The calculated speed is approximately 2785.30 m/s.

Explanation:

To calculate the speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag, we must recall the equations of motion. The relevant equation here is Final velocity (v) = Initial velocity (u) + Acceleration (gravity, g) * time (t). However, since initial velocity (u) is 0 (when the drop starts falling, it's stationary), the equation simplifies to Final velocity (v) = g * t.

In free fall, a body accelerates under gravity (approximated as 9.81 m/s^2). In terms of time, difficulties arise because we don't know exactly when the raindrop will hit the ground. We can, however, calculate the time it would take for the raindrop to fall 3950 m by rearranging the equation distance (s) = ut + 0.5 * g * t^2 to solve for time. Removing (u), for the reasons explained earlier, we have the equation s = 0.5 * g * t^2. Solving this for time gives t = sqrt(s / (0.5 * g)). Substituting the given fall distance for s we get t = sqrt(3950 / (0.5 * 9.81)) or approximately 284.10 seconds.

Finally, we use this calculated time in our simplified velocity equation which gives v = g * t or 9.81 * 284.10, which equals approximately 2785.30 m/s.

Learn more about Physics of Free Fall here:

brainly.com/question/33923697

#SPJ12

A 4kg block sitting on the floor, how much potential energy does it have?

Answers

Well, there you have a very important principle wrapped up in that question.

There's actually no such thing as a real, actual amount of potential energy.
There's only potential relative to some place. It's the work you have to do
to lift the object from that reference place to wherever it is now. It's also
the kinetic energy the object would have if it fell down to the reference place
from where it is now.

Here's the formula for potential energy: PE = (mass) x (gravity) x (height) .

So naturally, when you use that formula, you need to decide "height above what ?"

If you're reading a book while you're flying in a passenger jet, the book's PE is
(M x G x 0 meters) relative to your lap, (M x G x 1 meter) relative to the floor of the
plane, (M x G x 10,000 meters) relative to the ground, and maybe (M x G x 25,000 meters)
relative to the bottom of the ocean.

Let's say that gravity is 9.8 m/s² .

Then a 4kg block sitting on the floor has (39.2 x 0 meters) PE relative to the floor
it's sitting on, also (39.2 x 3 meters) relative to the floor that's one floor downstairs,
also (39.2 x 30 meters) relative to 10 floors downstairs, and if it's on the top floor of
the Amoco/Aon Center in Chicago, maybe (39.2 x 345 meters) relative to the floor
in the coffee shop that's off the lobby on the ground floor.

P.E.=mgh

P.E.= mass×gravity×height, therefore 4kg×10×0= 0 J

K.E. is also equal to 0 because the block is not moving, is in the state of Inertia

What is the expression of the chemical composition of a compound?

Answers

The correct answer is the chemical formula. The chemical formula is the expression of the chemical composition of a compound. It is the way of expressing the details about the atoms' proportion that constitutes a specific chemical compound.

Your shopping cart has a mass of 65 kilograms. In order to accelerate the shopping cart down an aisle at 0.30 m/s2 What force would you need to use or apply to the cart. I don't know how to solve this

Answers

Justin ! Justin ! ! You're in high school Physics. You've done Newton's Laws until you saw them in your sleep. When the wind rustles through the trees, you almost hear it whispering to you "F = M A". Now is the time to use that ! M=65kg. A=0.3m/s^2. F = (65)(0.3)=19.5 newtons.

What are three examples of circular motion?

Answers

Motion of fan, stone tied to a string and is being swung in circles and motion of electrons around nucleus.

Other Questions

. If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circularpath were reduced, what would happen?

Process of changing a liquid into a gas

If an elephant is chasing you in a straight line, its mass is threatening but if you zigzag, you have an advantage why?

Using a cathode ray tube, Thomson confirmed thatatoms must have an overall positive charge. atoms are made of particles that have a negative charge. electrons in atoms must have varying amounts of energy. electrons are only found in the nucleus.