PHYSICS HIGH SCHOOL

Explain the law of conservation of energy.

Answers

Answer 1

Answer: Energy cannot be created or lost, but only changes form.

Answer 2

Answer:

Answer:

Energy cant be created or lost, it only changes form.

Explanation:

The answer above is correct.

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A 0.145-kg baseball pitched at 37.5 m/s is hit on a horizontal line drive straight back toward the pitcher at 57.0 m/s . If the contact time between bat and ball is 2.50×10−3 s , calculate the average force between the ball and bat during contact.

For a winter fair, some students decide to build 30.0 kg wooden pull carts on sled skids. If two 90.0 kg passengers get in, how much force will the puller have to exert to move a pull cart? The coefficient of maximum static friction between the sled skids and the road is 0.15

Answers

Explanation:

Total mass = 90 + 90 + 30 kg = 210 kg

Normal force = 210 kg ( 9.81 m/s^2) = 2060.1 N

Force of friction to overcome = normal force x coeff of static friction

F = 2060.1 x .15 = ~ 309 N to get the cart moving...

A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to the bottle and the pressure increases to 2.05 atm, what is the change in temperature of the gas mixture?The initial temperature of the gas is ______ K.

Answers

These are inert gases, so we can assume they don't react with one another. Because the two gases are also subject to all the same conditions, we can pretend there's only "one" gas, of which we have 0.458+0.713=1.171 moles total. Now we can use PV=nRT to solve for what we want.

The initial temperature and the change in temperature. You can find the initial temperature easily using PV=nRT and the information provided in the question (before Ar is added) and solving for T.

You can use PV=nRT again after Ar is added to solve for T, which will give you the final temperature. The difference between the initial and final temperatures is the change. When you're solving just be careful with the units!

SIDE NOTE: If you want to solve for change in temperature right away, you can do it in one step. Rearrange both PV=nRT equations to solve for T, then subtract the first (initial, i) from the second (final, f):

PiVi=niRTi --> Ti=(PiVi)/(niR)

PfVf=nfRTf --> Tf=(PfVf)/(nfR)

ΔT=Tf-Ti=(PfVf)/(nfR)-(PiVi)/(niR)=(V/R)(Pf/nf-Pi/ni)

In that last step I just made it easier by factoring out the V/R since V and R are the same for the initial and final conditions.

The initial temperature of the gas is

wrong 137

⇒ 122 K. correct on E.D.G

Middle c has a speed of 1500 m/s in water and 340 m/s in air. does it have a longer or shorter wavelength in water than in air and why?

Answers

yes, it has a longer wavelength in water than in air.

Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of mass 2m hanging from it. Part A If the energies of the two systems are the same, what is the ratio of the oscillation amplitudes?

Answers

Answer:

$(A_1)/(A_2)=1$

Explanation:

given,

two identical spring have identical spring constant

mass 'm' is hanging on one spring and mass of '2m' on another wall.

energy of the two system is same

energy of the system having mass 'm'

$E = (1)/(2)m\omega_1^2A_1^2$

energy of the system having mass '2m'

$E = (1)/(2)(2m)\omega_1^2A_1^2$

now, Energy are same

$(1)/(2)m\omega_1^2A_1^2= (1)/(2)(2m)\omega_1^2A_1^2$

$(A_1^2)/(A_2^2)=(2\omega_2^2)/(\omega_1^2)$

we know $k = mw^2$

$(A_1)/(A_2)=\sqrt{\frac{2(k)/(m_2)}{{(k)/(m_1)}}$

$(A_1)/(A_2)=\sqrt{(2m_1)/(m_2)}$

$(A_1)/(A_2)=\sqrt{(2m)/(2m)}$

$(A_1)/(A_2)=1$

List 3 pieces of evidence for the Earth’s spherical shape

Answers

Answer:

1.time zones

2.The coriolis effect

3. triangles

Explanation:

1. day and night happen at different times at different places; it's always day somewhere and night another.

2. the coriolis effect means freely moving things (like cannonballs or hurricane winds) are deflected to the right - but only if your north of the equator if you're south of the equator they're deflected left.

3. if you walk a certain distance and make three right angle you can successfully make a triangles with three 90 degree angles which is impossible on a flat surface.

Which change decreases the resistance of a pieceof copper wire?
(1) increasing the wire’s length
(2) increasing the wire’s resistivity
(3) decreasing the wire’s temperature
(4) decreasing the wire’s diameter

Answers

Explanation :

We know that the resistance of the wire is given by :

$R=\rho (l)/(A)$

Where

$\rho$ is the resistivity

l is the length of the wire

A is the area of the wire.

Another factor on which the resistance of wire depends is temperature. It is given by :

$R=R_(ref)[1+\alpha (T-T_(ref))]$

So, it is clear that the resistance of the wire is directly proportional to the temperature. It we want to decrease the resistance of the piece, its temperature should be decreased.

So, the correct option is (3) " decreasing the wire’s temperature ".

Decreasing the wire’s temperature decreases the resistance of a piece of copper wire.

What is resistance?

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The relation of resistance with length and thickness is given by ;

$\rm R= (\rho L)/(A)$

The value of resistance is directly propotional to length and inversly propotional to the area or thickness of the wire.

As the value of temperature increases, the value of resistance in the material is increasing. Length, temperature, and thickness are the factors that affect the resistance of a material.

Resistance of the wire is directly propotional to the temperature. On decreasing the temperature the resistance of the wire is also decreasing.

Hence decreasing the wire’s temperature decreases the resistance of a piece of copper wire.

To learn more about the resistance refer to the link;

brainly.com/question/20708652

Other Questions

You pull a sled with a package on it across a snow-covered flat lawn. If youapply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. What is thecombined mass of the package and the sled? (Assume there is no friction.)

A ball is at rest at the top of a hill. It rolls down the hill. At the bottom of the hill the ball hits a wall and stops. Which energy changes occur? A) Gravitational potential energy, internal energy, kinetic energy B) Gravitational potential energy, kinetic energy, internal energy C) Kinetic energy, gravitational potential energy, internal energy D) Kinetic energy, internal energy, gravitational potential energy

Which of the following bodies has a brightness that surpasses Venus’? My options are Jupiter, Mars, the stars, and the Moon. Jupiter and mars are obviously out and Venus is brighter than all the stars in the sky (besides the sun lol) so it would be the moon right? just a lil confused. btw i'm not sure what subject to post this in since there's no astronomy subject.

Which object has the least momentum? Object A: m = 1 kg, v = 100 m/s Object B: m = 10 kg, v = 12 m/s Object C: m = 0.5 kg, v = 1000 m/s Object D: m = 100 kg, v = 2 m/s