Which object has the least momentum? Object A: m = 1 kg, v = 100 m/s
Object B: m = 10 kg, v = 12 m/s
Object C: m = 0.5 kg, v = 1000 m/s
Object D: m = 100 kg, v = 2 m/s
Answers
that one
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Answers
b. lamp
c. resistor
d. ammeter
Answers
In a battery we can able to find the voltage gain.
The following information should be considered;
- Since the battery is treated as the active device.
- But the lamp, resistor, ammeter are considered to be the passive devices that result to the potential drops instead of the voltage gain.
Learn more: brainly.com/question/1691136?referrer=searchResults
Answer:
A
Explanation:
Answers
Answer:
0.044 seconds
Explanation:
Parameters given:
Length of nerve cell = 1.2m
Nerve impulse speed = 27m/s
Speed is given as:
Speed = distance/time
Therefore, we can make time the subject of the formula. We have:
Time = distance/speed
Hence, time taken for the nerve cell to travel this distance is:
Time = 1.2 / 27
Time = 0.044 seconds
It takes 0.044 seconds for the nerve signal to travel the distance of the nerve connecting the spinal cord to the feet.
Answers
OK, here we go. Fossen your seat belt, mon,
it's going to be eh boompy rade !
E = energy equivalent of mass
m = the mass of the mass
c = the speed of light
E = (m) (c)²
= (100 mg) (3 x 10⁸ m/s)²
= (1 x 10⁻⁴ kg) (9 x 10¹⁶ m²/s²)
= 9 x 10¹² (kg-m²/s²)
= 9 x 10¹² (kg-m/s²) (m)
= 9 x 10¹² (newton) (m)
= 9 x 10¹² joules .
The car can go 30 km on 10⁸ J of energy.
How far can it go on 9 x 10¹² J ?
(9 x 10¹² J) x (30 km / 10⁸J)
= (9 x 10⁴) x (30 km) = 2,700,000 km
= roughly 7.3 times the distance to the moon.
Answers
Answers
Answer:
1. T₁ is approximately 100.33 N
T₂ is approximately -51.674 N
2. 230°F is 383.15 K
3. Part A
The total torque on the bolt is -4.2 N·m
Part B
Negative anticlockwise
Explanation:
1. The given horizontal force = 86 N
The direction of the given 86 N force = To the left (negative) and along the x-axis
(The magnitude and direction of the 86 N force = -86·i)
The state of the system of forces = In equilibrium
The angle of elevation of the direction of the force T₁ = 31° above the x-axis
The direction of the force T₂ = Downwards, along the y-axis (Perpendicular to the x-axis)
Given that the system is in equilibrium, we have;
At equilibrium, the sum of the horizontal forces = 0
Therefore;
T₁ × cos(31°) - 86 = 0
T₁ = 86/(cos(31°)) ≈ 100.33
T₁ ≈ 100.33 N
Similarly, at equilibrium, the sum of the vertical forces = 0
∴ T₁×sin(31°) + T₂ = 0
Which gives;
100.33 × sin(31°) + T₂ = 0
T₂ = -100.33 × sin(31°) ≈ -51.674
T₂ ≈-51.674 N
2. 230° F to Kelvin
To convert degrees Fahrenheit (°F) to K, we use;
Pluggining in the given temperature value gives;
230°F = 383.15 K
3. Part A
Torque = Force × perpendicular distance from the line of action of the force
Therefore, the clockwise torque = 9 N × 0.4 m = 3.6 N·m (clocwise)
The anticlockeisre torque = 13 N × 0.6 m = 7.8 N·m (anticlockwise)
The total torque o the bolt = 3.6 N·m - 7.8 N·m = -4.2 N·m (clockwise) = 4.2 N·m anticlockwise
Part B
The torque is negative anticlockwise.