Answers
Answer: In calcium chloride there is one calcium atom and two chloride atoms attached to it, it has an ionic bond with chlorine and calcium. A bond is said to be an ionic bond if it is formed by the electrostatic attraction between one negatively charged and one positively charged ions. Ions are the atoms which are formed on the gain or loss of electrons to an atom. All the other molecules have covalent bonds, which forms on sharing of electron pairs.
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Answer : Acid-base reaction is determined when hydrogen ion of an acid neutralize by the hydroxide ion of a base then it gives water.
Explanation :
Acid-base reaction : It is defined as the reaction in which an acid reacts with a base to give salt and water.
Acid-base reaction is determined when hydrogen ion of an acid neutralize by the hydroxide ion of a base then it gives water.
For example: When hydrochloric acid react with sodium hydroxide base to give sodium chloride salt and water.
The balanced acid-base reaction is:
B) 1.77 m
C) 6.39 m
D) 2.41 m
E) none of these
Answers
Answer: D) 2.41 m
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in kg
moles of solute =
volume of solution = 1L = 1000 ml (1L=1000ml)
Mass of solution=
mass of solute = 292 g
mass of solvent = mass of solution - mass of solute = (1108- 292) g = 816g = 0.816 kg
Now put all the given values in the formula of molality, we get
Therefore, the molality of solution will be 2.41 mole/kg
Final answer:
In this problem, we calculate molality by using the given mass of the solute, the mass of the solvent, and the molar mass of the solute. After performing the necessary calculations, we find that the molality is 2.41 m.
Explanation:
The subject of this student's question is molality, which is a measure of the concentration of a solute in a solution. It is defined as the number of moles of solute per kilogram of solvent. To find the molality (m), we need to know the mass of the solute and the mass of the solvent in the solution.
Given, that the solution contains 292g of Mg(NO3)2 per liter (which is the mass of the solute). The density of the solution is 1.108g/mL. We know that 1L = 1000mL, so the mass of the solution is density x volume = 1.108g/mL x 1000mL = 1108g.
We need to find the mass of the solvent (water). The mass of the solution is the mass of the solute + the mass of the solvent. So, the mass of the solvent is 1108g(mass of the solution) - 292g(mass of solute) = 816g or 0.816gkg.
The molar mass of Mg(NO3)2 is 148.31452 g/mol. So, the number of moles of Mg(NO3)2 in the solution is moles = mass / molar mass = 292g / 148.31452 g/mol = 1.97 moles.
Now we can calculate molality (m) = moles of solute/mass of solvent in kg = 1.97 moles / 0.816 kg = 2.41 m. Therefore, the answer is D) 2.41 m.
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C. Which of the two substances will have a greater density?
d. Why? Your explanation must include the terms "mass" and "volume", and it must include the definition you provided in #2
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I don't understand the question
Can you elaborate further
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Answer:
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Explanation:
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Explanation:
..(1)
Manganese (II) carbonate and oxygen reacts to give manganses (III) oxide with carbon-dioxide gas.
..(2)
Manganese (III) oxide reacts with aluminum metal to give aluminum oxide and manganese metal
On adding (1) and 2(2) we will get the net net chemical equation for the production of manganese. So,
The net balanced equation we got:
Final answer:
The production of manganese from manganese (II) carbonate, oxygen, and aluminum involves two chemical reactions. Heating manganese (II) carbonate with oxygen yields manganese(III) oxide and carbon dioxide. This manganese (III) oxide then reacts with aluminum to produce manganese and aluminum oxide.
Explanation:
The chemical reaction can be described in terms of a net chemical equation after properly balancing the chemicals involved on both sides of the equation. The first step is to understand and correctly write down the formula of reactants and products for the reaction. Here: Manganese (II) Carbonate (MnCO3), Oxygen (O2), and Aluminum (Al).
In the process of manganese production, Manganese (II) Carbonate is first heated in the presence of oxygen to yield Manganese (III) Oxide (Mn2O3) and Carbon Dioxide (CO2):
MnCO3 + 1/2 O2 -> Mn2O3 + CO2.
The resulting Manganese (III) Oxide reacts with Aluminum (which acts as a reducing agent in this case) to generate Manganese and Aluminum Oxide:
3 Mn2O3 + 4 Al -> 6 Mn + 2 Al2O3.
These two equations combined represent the net chemical equation for the production of manganese from manganese (ii) carbonate, oxygen, and aluminum.
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general formula
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Answer:
Explanation:
Hello!
In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:
In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:
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