NEED HELP!Every evening Jenna empties her pockets
and puts her change in a jar. At the end
of the week she counts her money. One
week she had 50 coins, all of them dimes
and quarters. When she added them up,
she had a total of $10.25.

Let d = number of dimes and
q = number of quarters.

Answers

Answer 1

Answer: d + q = 50

10d + 25q = 1025

Multiply the first equation by 10.

10(d + q = 50) --> 10d + 10q = 500

We combine this with the second equation

10d + 25q = 1025
10d + 10q = 500

--------subtract--------
15q = 525 iff
q = 35

Plug in q = 35 into any of the original equations,

d + q = 50
d + 35 = 50 iff
d = 15

There are 15 dimes, and 35 quarters.

Answer 2

Answer: the equation would be d+q=$10.25

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The fraction 9/15 is an equivalent fraction of 6/20 1/2 3/5
Hey can anyone help I'm so confused on how to this :)
Solve for x: 1 over 4 (2x − 14) = 4.
Which is equivalent to (−2m + 5n)2, and what type of special product is it4m2 + 25n2; a perfect square trinomial 4m2 + 25n2; the difference of squares 4m2 − 20mn + 25n2; a perfect square trinomial 4m2 − 20mn + 25n2; the difference of squares

What is the common ratio of the sequence?

-2, 6, -18, 54,...

Answers

a1=-2
a2=6
a3=-18

the common ratio musbe negative since the signs alternate

it is multiilied by 3 ach time

comon ratio is -3
an=-2(-3)^(n-1)

Answer:

the common ratio is -3

Step-by-step explanation:

14.2 is 35.5% of what number W

Answers

14.2 = 35.5% W
35.5% means 35.5/100 so,
0.355 W = 14.2
W = 40

Answer:

W=40

Step-by-step explanation:

S = vt + 16t2 for v.

Answers

Answer:

s = vt + 16t^2

s -16t^2 = vt

s/t -16t = v

Answer:

v = s/t -16t

Step-by-step explanation:

3x~6y=~3
2x+4y=30
Elimination using multiplication

Answers

$\left \{ {{3x-6y=-3\ \ |*2} \atop {2x+4y=30\ \ | *(-3)}} \right. \n\n \left \{ {{6x-12y=-6} \atop {-6x-12y=-90}} \right. \n+----\nelimination\n\n0 \neq -69\n\nThere\ are\ no\ solutions$

Find the equation of the tangent line to the curve y=2sinxy
2
sin
x
at the point (π/6,1)
π
6
1
.

The equation of this tangent line can be written in the form y=mx+b
y
m
x
b
where

Answers

Final answer:

To find the equation of the tangent line to the curve y=2sinx at the point (π/6,1), we take the derivative to find the slope and then use the point-slope form of the line equation. The result is y = √3x + 1 - √3π/6.

Explanation:

The subject of this question is calculus and focuses specifically on finding the equation of the tangent line to the curve y=2sinx at a given point. To do this, we use the formula y=mx+b.

Firstly, the slope of the tangent line is obtained by taking the derivative of the function at the point of tangency. The derivative of y=2sinx is y'=2cosx. For the given point (π/6,1), the slope (m) would be 2cos(π/6) = √3.

Secondly, we use the point-slope form of the line equation to find b. Inserting the values of the slope (m) and the given point into the equation, we get 1 = √3(π/6) + b. Solving for b gives b = 1 - √3π/6.

Finally, the equation of the tangent line is y = √3x + 1 - √3π/6.

Learn more about Tangent Line here:

brainly.com/question/34259771

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Hello
f(x) = 2sin(x)
f(π/6) = 1
f'(x) 2cos(x)
f'(π/6) = 2×co(π/6) = 2 × root(3)×0.5 =root(3)
The equation of this tangent line is : y= root(3)(x-π/6)+1
y = root(3)x+1 - π/6(root(x)) in the form y=mx+b
m = root(3) and b = 1 - π/6(root(x))

You grab two jelly beans from a jar at the same time. b you draw a card from a deck, replace it, and draw a second. c you draw a card and do not replace it. then you draw another. d you study english every night, and then you get an a on the next test.