The pressure of a fluid at a specific depth depends only on the type of fluid?

Answers

Answer 1

Answer: i think yes the density

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A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that an emf of 0.43 V and a current of 3.1 A are induced in the coil. The wire is then re-formed into a single-turn square coil, which is used in the same magnetic field (again perpendicular to the plane of the coil and with a magnitude changing at the same rate). What (a) emf and (b) current are induced in the square coil

Answers

Answer:

2.62A

Explanation:

Given

V = 0.43 V

I = 3.1 A

Then, V = IR, R = V/I

R = 0.43/3.1

R = 0.14 Ω

The induced emf = dB/dt * A

So that, dB/dt = emf/A

Since dB/dt is constant then Emf/A(circle) = Emf/A square

So Emf (square)/Emf (circle) = A square / A circle

A circle = πr². The perimeter of the square is 2πr which also is the circumference of the square.

Since the perimeter is 2πr, then each side would be πr/2. Thus, the area of the square would be, (πr/2)² = π²r²/4

So A square/Acircle = (π²r²/4) / πr² = π/4 = 0.79

this means that, emf square = emf circle * 0.79

emf square = 0.43*0.79 = 0.34V

I = V/R

I = 0.34/0.13

I = 2.62A

A small package is attached to a helium-filled balloon rising at 2 m/s. The package drops from the balloon when it is 14 meters above the ground. What is the velocity of the package just before it hits the ground?

Answers

The velocity of the package just before it hits the ground is 16.7 m/s.

What is velocity?

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

Initial velocity(u)=2 m/s

V(velocity of hitting)=?

S(distance travelled)= 14 meters

The velocity of the package just before it hits the ground is found as;

From the Newton's third equation of motion;

v²=u²+2as.

v²=(-2)²+2(9.81)(14)

v=16.7 m/s

Hence,the velocity of the package just before it hits the ground is 16.7 m/s.

To learn more about the velocity, refer to the link;

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I would assume air resistance is negligible and so the acceleration of the package would be approximately 9.81 m/s².

Taking downwards as positive, use v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s

A research paper isA. creative, unstructured, first-person writing.
B. casual, third-person, entertaining writing.
C. thoughtful, analytical, academic writing.
D. bullet-pointed, technical, factual writing.

Answers

A research paper is considered to be the work that is a culmination of hundreds of hours of work put into one technical writeup which serves as the groundwork for what was done in that particular research. For that reason, the asnwer to your question would be C - thoughtful, analytical and academic writing.

Electrically charged flares that arch up from the Sun are known as _______.

Answers

Electrically charged flares that arch up from the Sun are known as the solar flare or solar prominence. The Solar flare is the sudden brightness of the Sun near its surface. It is mostly accompanied by coronal mass ejection.

Answer:

prominences

Explanation:

Momentum is a measure of ____.a. how hard it is to stop an object
b. the amount of matter in an object
c. the tendency of an object to change its motion
d. the amount of force acting on an object

Answers

Answer: Option (a) is the correct answer.

Explanation:

Momentum is the ability of an object to continue its motion. It can be measured by multiplying mass of the object and its velocity.

Mathematically, p = m × v

where p = momentum

m = mass

v = velocity

Therefore, we can conclude that out of the given options, momentum is a measure of how hard it is to stop an object.

Final answer:

Momentum is a measure of how hard it is to stop an object.

Explanation:

Momentum is a measure of how hard it is to stop an object. It depends on the mass and velocity of the object.

The formula for momentum is:
Momentum = mass x velocity.

Therefore, option a. 'how hard it is to stop an object' is the correct answer.

Learn more about Momentum here:

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In the Niagara Falls hydroelectric generating plant, the energy of falling water is converted into electricity. The height of the falls is about 48 meters. Assuming that the energy conversion is highly efficient, approximately how much energy is obtained from one kilogram of falling water? Therefore, approximately how many kilograms of water must go through the generators every second to produce a megawatt of power (106 watts)?