Rank cesium, chlorine, and chromium in order of increasing electron affinityA) Cs < Cr < Cl
B) Cl < Cr < Ce
C) Ce < Cl < Co
D) Ca < Cu < Cl

Answers

Answer 1
Answer: The correct answer is A. Cesium has the lowest electron affinity among the three while Chlorine has the highest. 

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Which element is a liquid at 758 K and standard pressure?(1) gold (3) platinum
(2) silver (4) thallium

Answers

The answer would be Thallium. This is an element with Tl as its chemical symbol and atomic number 81. This soft gray post-transition steel is not originate free in nature. When inaccessible, thallium look like tin, but tarnishes when unprotected to air.

Answer: option (4) thallium.


Explanation:


1) You have to look at the normal boling and mleting points of the elements.


2) To be liquid the normal melting point must be lower than 758 K and the normal boiling point must be greater than 758 K.


3) The look at the data in a handbook of properties or in internet, and build a table.


4) The given temperature, 758K, is 758 - 273.15 = 484.85 °C.



Element                 Normal melting         Normal boiling        State at 484.85 °C

                               point (°C)                   point (°C)


(1) gold                    1064                           2700                      solid

(2) silver                   961.8                          2162                      solid

(3) platinum             1768                            3825                      solid

(4) thallium               303.5                          1457.8                   liquid


Then, the only element of the choices whose melting point is less than 758 K (484.85) and its boiling point is greater than that, at 1 atm is thallium. So, it is liquid.

What mass of a 60.0-gram sample of N-16 will remain unchanged after 28.8 seconds?

Answers

The answer is 3.75 g.

Half-life is the time required for the amount of a sample to half its value.
To calculate the fraction of the sample remained unchanged, we will use the following formulas:
1. (1/2)^(n) = x,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. t_(1/2) = (t)/(n)
where:
t_(1/2) - half-life
t - total time elapsed
n - a number of half-lives

The half-life of N-16 is 7.13.
So, we know:
t = 28.8 s
t_(1/2) = 7.13 s

We need:
n = ?
x = ?

We could first use the second equation, to calculate n:
If:
t_(1/2) = (t)/(n),
Then: 
n = (t)/( t_(1/2) )
⇒ n = (28.8 s)/(7.13 s)
⇒ n=4.04
⇒ n ≈ 4

Now we can use the first equation to calculate the remained amount of the sample.
(1/2)^(n) = x
⇒ x=(1/2)^4
x= (1)/(16)


If the fraction of the sample is 1/16 = 6.25%, then the mass of the sample could be calculated as:
x g : 6.25% = 60 g : 100% 
x = 

A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?

Answers

The specific heat of the unknown sample has been \rm \bold{0.192\;\;J/g^\circ C}.

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat (c) for a substance can be given by:

Q=mc\Delta T ......(i)

Where, the heat required by the substance, Q=345.2\;\text J

The mass of the substance has been, m=89.5\;\text g

The change in temperature of the system has been, \Delta T

The change in temperature has been given as:

\Delta T=T_f-T_i

The initial temperature of the substance, T_i=285\;\text K

The final temperature of the substance, T_f=305\;\text K

Substituting the values for the change in temperature, \Delta T:

\Delta T=305\;-\;285\;K\n\Delta T=20\;\text K

Substituting the values in equation (i):

345.2=89.5\;*\;c\;*\;20\n345.2=1,790c\nc=0.192\rm \;J/g^\circ C

The specific heat of the unknown sample has been \rm \bold{0.192\;\;J/g^\circ C}.

For more information about specific heat, refer to the link:

brainly.com/question/2094845

The specific heat is the heat needed per unit mass to raise the temperature by 1 degree celsius. So the specific heat = heat/(mass*ΔT) = 345.2/[89.5*(305-285)]=0.193 J/(g*℃). When using ΔT, the unit K and ℃ are the same.

Absolute zero is A. the temperature at which the motion of particles theoretically ceases. B. defined as 0°C. C. the triple point for water. D. all of the above

Answers

The correct answer is A. The temperature at which the motion of particles theoretically ceases.

Explanation:

The term "absolute zero" is used to refer to a temperature (degree of heat) in which particles have no movement or only minimal vibration as in this temperature the energy of particles is affected. Due to this, the absolute zero is one of the lowest temperatures that exists as it is equivalent to -273 °C or -459 °F, although it has been proved temperature can be even lower at certain circumstances. According to this, "absolute zero" is mainly defined by the lack of motion in particles and thus, the correct answer is "he temperature at which the motion of particles theoretically ceases".

Absolute zero is the temperature at which the motion of particles that constitute heat will be minimal. The answer is A. It is the lowest temperature that is theoretically possible. It is zero on the kelvin scale, but equivalent to -273.15°C. Hope i helped.

All funguslike protists are able to do this at some point in their lives

Answers

Protists belong to the group eukaryotes (having their DNA enclosed inside the nucleus). They are not plants, animals or fungi but they act like one. They can be in general subgroups such as unicellular algae, protozoa and molds. 

What is a disadvantage of using a structural model to show a chemical compound? Structural models provide minimal three-dimensional information. Structural models do not identify the number and type of each atom. Structural models cannot distinguish between single, double, and triple bonds. Structural models cannot distinguish between different isomers of a compound.

Answers

The answer is the first: that structural models provide minimal three-dimensional information. This is because the ball-and-stick model cannot show the actual size of the atoms depicted in the model. You also cannot see the actual bond lengths between the atoms. This, then, limits the accuracy of the model and fails to precisely portray how the chemical compounds being shown are like in all actuality. Thus, though you do see a three-dimensional picture of the chemical compound, this picture is not completely accurate and is not scaled to size. 

Answer: A - Structural models provide minimal three-dimensional information.

Explanation: