In a fission reaction of U-235, there was a release of 9.20 × 1011 kJ of energy. What amount of mass in kilograms would have been lost?Recall that c = 3 × 108 m/s.
Answers
m = e / c^2
Plug in your numbers in the appropriate units.
m=1.02 × 10^-5
Answer : The amount of mass in kilograms lost would be,
Solution : Given,
Energy of released in the reaction =
Speed of light = c =
Formula used :
where,
E = energy released
m = mass
c = speed of light
Now put all the given values in the above formula, we get the amount of mass would have been lost.
conversion :
Therefore, the amount of mass in kilograms lost would be,
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Planck's constant relates the Joules of energy absorbed/released by matter to the:A. atomic number of the element B. observed wavelength of light C. speed of lightD. mass of the particulate matter
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The shape of the nucleus is maintained byA. the nucleolus.B. the nuclear lamina.C. the nuclear envelope.D. the endoplasmic reticulum.
Which of the following shows the equation balanced?
A. 3 O2 + CS2 → CO2 + 2 SO2
B. 3 O2 + CS2 → 2 CO2 + SO2
C. O2 + CS2 → CO2 + SO2
D. 4 O2 + 4 CS2 → 4 CO2 + 4 SO2
Answers
Answer:
Look at the equation below.
→
The equation balanced is:
A. →
Explanation:
The equation balanced is:
→
This can be proved with the amount of atoms of each element in reagents and products:
Reagents:
O=6
C=1
S=2
Products:
O=6
C=1
S=2
The option that shows the that the equation is balanced is:
3O₂ + CS₂ → CO₂ + 2SO₂ (option A)
How to balance the equation?
The equation O₂ + CS₂ → CO₂ + SO₂ can be balanced as shown below:
O₂ + CS₂ → CO₂ + SO₂
There are 2 atoms of S on the left side and 1 atom on the right. It can be balanced by writing 2 before SO₂ as shown below:
O₂ + CS₂ → CO₂ + 2SO₂
There are 2 atoms of O on the left side and a total of 6 atoms on the right. It can be balanced by writing 3 before as shown below:
3O₂ + CS₂ → CO₂ + 2SO₂
Now, we can see that the equation is balanced. Thus, the correct answer to the question is 3O₂ + CS₂ → CO₂ + 2SO₂ (option A)
Learn more about balancing equation:
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Answers
Fe³⁺ +e⁻ -> Fe²⁺ is the half reaction equation represents the reduction of an iron(II) ion
What is Reduction Reaction ?
When an element or a compound gain electron , decreasing its oxidation number is called reduced and the half cell reaction is called Reduction reaction.
Fe³⁺ +e⁻ -> Fe²⁺ , Option C
In this reaction the Iron is gaining electron and the charge is getting reduced from +3 to +2 .
Therefore this half reaction equation represents the reduction of an iron(II) ion.
To know more about Reduction Reaction
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reduction of an iron(II) ion
Answer b
- Use 6.022x1023 for avogadro’s number
- Ignore sig figs and do not round the final answer.
- Keep it to 1 decimal place.
Answers
Answer:
a) 13.2 moles
b) 79.33 grams of
Explanation:
First, we'll need to balance the equation
→
There are 2 (O) on the left and only one on the right, so we'll add a 2 coefficient to the right.
→
Now there are 4 (H) on the right and only 2 on the left, so we'll add a 2 coefficient to the () on the left.
→
The equation is now balanced.
a) This can be solved with a simple mole ratio.
4.6 moles ×
= 13.2 moles
b) This problem is solved the same way!
2.2 moles ×
= 2.2 moles
However, this problem wants the mass of , not the moles.
The molecular weight of is the weight of 4 (H) molecules and 2 (O) molecules (found on the periodic table). So,
4(1.008) + 2(15.999) = 36.03 g/mol
2.2 moles ×
= 79.33 grams of
Answers
CIO4-=-1
CI=4O=-1
O has a 2- oxidation change so
CI+4(-2)=-1
CI+(-8)=-1
CI=-1+8=7
So the oxidation number of chlorine is 7 in this case
Answers
hope this helps
Answers
? mol H₂O --------- 2.0x10²² molecules
Number of moles = Number of molecules / Avogadro's number
moles = 2.0x10²² * 1 / 6.02x10²³
= 2.0x10²² / 6.02x10²³
= 0.3322 moles
hope this helps!