Sorry the picture quality isn't great..Light bends, as shown in the illustration,because it____
A. Speeds up
B. Reflects light
C. Slows down
D. Gains energy
Sorry the picture quality isn't great.. Light bends, as shown - 1

Answers

Answer 1
Answer:

Answer : The correct option is, C.

Explanation :

  • Refraction : When light is passing from rarer medium to denser medium then the light bends towards the normal line due to change in the speed of the light.
  • Reflection : When light ray falling on the surface then the refracted ray coming out from the surface. In reflection, the incident angle is equal to the reflected angle.

In a given diagram, refraction phenomenon is observed in which an incident angle of a light ray is 45^0 and the refracted angle of a light ray is 32^0 which means the light bends towards the normal.

From this we can say that the light is passing through rarer medium to denser medium. In denser medium, the speed of light slows down.


Answer 2
Answer: according to my research C seems to be the answer because when light bens it tends the slow down 

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According to the electron-cloud model of the atom, an orbital is a(1) circular path traveled by an electron around the nucleus
(2) spiral path traveled by an electron toward the nucleus
(3) region of the most probable proton location
(4) region of the most probable electron location

Answers

Answer : Option 4) Region of the most probable electron location.


Explanation : As per the electron cloud model of the atom, an orbital is a region where the probability of finding an electron is highest. According to this model which was used to identify the probable location of the electrons when they go around the nucleus of an atom.


This electron cloud model was different from the older Bohr atomic model by Niels Bohr.

According to the electron-cloud model of the atom, an orbital is a "region of the most probable electron location" In this mode, an electron can actually be in two places at once. 

Would the following errors increase, decrease, or have no effect on the calculated moles of gas collected in the experiment? Explain your answers in complete sentences.a) The measured mass of the magnesium was smaller than the true mass.
b) The actual temperature of the hydrogen gas is less than room temperature.

Answers

a. If the actual mass of Magnesium used was larger then the measured and the amount of gas produced should be greater
b. when gas was cooler than its surroundings its density would be greater and the volume would appear to be smaller. This is because the gas molecules are very active and when heated they will expand.
so they both bound increase the calculated moles of gas collected in the experiment

true or false: ionic bonding involves the shareing of electrons, oxide ions have a 2+ charge , electrons have a negative charge , a hydrogen molecule is held together by a strong covalent bond between two hydrogen atoms, a covalent bond is a shared pair of electrons.

Answers

Ionic bonding does not involve the sharing of electrons, that one is false. In ionic bonding, the metal's electrons are given to the non-metal, so that they're both like the nearest noble gas (full electron shells.) They are then drawn together because one has a negative charge (the non-metal) and one has a positive charge (the metal.)

Oxide ions have a 2+ charge: This is false, oxide ions have a 2- charge.

Electrons do have a negative charge, this is true.

Hydrogen molecule: pretty sure this is true. We know this because both atoms are non-metals.

The last one is true: a covalent bond is a shared pair of electrons between two atoms, however be aware that there can be more than one covalent bond between two molecules.


Answer:

  1. False , shared electrons cause covalent bonds
  2. False , they have 2- charge
  3. True
  4. True
  5. Truw

How could you safely determine if a base is stronger than an acid?

Answers

Combine the two solutions. If the resulting salt is basic, you know the base was stronger. If you end up with an acidic salt, the acid was stronger.

Answer:

B) Use a conductivity apparatus

Explanation:

I got it right on Plato. Strong acids and strong bases will conduct more than weak acids and weak bases, so you can tell if one is stronger than the other by seeing which one conducts more.

What is the volume of 0.30 M NaOH(aq) neededto completely neutralize 15.0 milliliters of
0.80 M HCl(aq)?
(1) 3.6 mL (3) 20. mL
(2) 5.6 mL (4) 40. mL

Answers

Answer:  4) 40 ml

Solution :

According to the neutralization law,

M_1V_1=M_2V_2

where,

M_1 = molarity of NaOH solution = 0.30 M

V_1 = volume of NaOH solution = ?

M_2 = molarity of HCl solution = 0.80 M

V_2 = volume of HCl solution = 15 ml

Now put all the given values in the above law, we get the volume of NaOH solution.

(0.30M)* V_1=(0.80M)* (15ml)

V_1=40ml

Therefore, the volume of 0.30 M NaOH required to neutralize 15 ml of 0.80 M HCl is 40 ml.

Final answer:

The volume of 0.30 M NaOH(aq) needed to neutralize 15.0 milliliters of 0.80 M HCl(aq) is 40 milliliters.

Explanation:

The volume of 0.30 M NaOH(aq) needed to neutralize 15.0 milliliters of 0.80 M HCl(aq) can be determined using the concept of stoichiometry and the balanced equation for the reaction between NaOH and HCl. The balanced equation is:

NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

From the balanced equation, we can see that 1 mole of NaOH reacts with 1 mole of HCl. Therefore, the number of moles of HCl in 15.0 milliliters of 0.80 M HCl solution can be calculated as:

Moles of HCl = Volume (in liters) × Molarity = 0.015 liters × 0.80 moles/liter = 0.012 moles

Since 1 mole of NaOH reacts with 1 mole of HCl, we need 0.012 moles of NaOH. The volume of 0.30 M NaOH solution can be determined by rearranging the equation:

Volume (in liters) = Moles / Molarity = 0.012 moles / 0.30 moles/liter = 0.04 liters = 40 milliliters

Therefore, the volume of 0.30 M NaOH(aq) needed to completely neutralize 15.0 milliliters of 0.80 M HCl(aq) is 40 milliliters.

Learn more about Volume calculation here:

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Of all boron atoms, 19.9%% are boron-10, which have a mass of 10.01294 amu. The other 80.1% of boron atoms are boron-11 and these have a mass of 11.00931. Calculate the average atomic mass of boron.

Answers

Answer:

10.81 amu

Explanation:

The average atomic mass of Boron can be calculated as follows :

A=19.9\%\ \text{of}\ 10.01294 +80.1\%\ \text{of}\ 11.00931\n\nA=(19.9)/(100)* 10.01294 +(80.1)/(100)* 11.00931\n\nA=10.81\ \text{amu}

So, the average atomic mass of boron is 10.81 amu.