Which one of the following temperatures is equal to 5°C?
Answers
5°C = 41°F = 278 K .
Answer:
278 K
Explanation:
Related Questions
Water near the poles would most likely be stored as
Suppose that now you want to make a scale model of the solar system using the same ball bearing to represent the sun. How far from it would you place a sphere representing the earth? (Center to center distance please.) The distance from the center of the sun to the center of the earth is 1.496×10111.496×1011 m and the radius of the sun is 6.96×1086.96×108 m.
The best evidence of Earths rotation is provided by
How much net force is required to accelerate a 50.00kg mass at 4.00 m/s^2
Answers
in order to answer this question:
1 full circle ==> 360 degrees .
Got that ?
Now you could set up a proportion:
(30 degrees) / (0.01 second) = (360 degrees) / (time for full period)
Cross-multiply the proportion:
(30°) · (period) = (360°) · (0.01 sec)
Divide each side by (30°) : Period = (360° · 0.01 sec) / (30°)
= (3.6° · sec) / (30°)
= (3.6 / 30) sec
= 0.12 sec .
___________________________________
Another way to look at it:
30° takes 0.01 second
60° takes 0.02 second
90° takes 0.03 second
120° takes 0.04 second
150° takes 0.05 second
180° takes 0.06 second
210° takes 0.07 second
240° takes 0.08 second
270° takes 0.09 second
300° takes 0.10 second
330° takes 0.11 second
360° takes 0.12 second
Answers
The distance of the image observed by th girl is 2.77 cm.
Focal length of the lens
The focal length of the lens is calculated as follows;
F = R/2
where;
- R is the radius of lens
R = 9 cm/2 = 4.5 cm
F = R/2
F = 4.5/2
F = 2.25 cm
Image distance
The distance of the image observed by th girl is caculated as follows;
1/f = 1/v + 1/u
1/v = 1/f - 1/u
1/v = 1/2.25 - 1/12
1/v = 0.3611
v = 2.77 cm
Thus, the distance of the image observed by th girl is 2.77 cm.
Learn more about image formed by lens here: brainly.com/question/6722295
(9/2)/2 = 2.25 cm
i = 1/(1/f - 1/o)
1/(1/2.25 - 1/12) = 1/2.769 ⇒ 0.36
I believe the image would appear upright.
Answers
mass = density x volume
We are told the density and must find the volume from the dimensions given
the volume of the washer will be the area x thickness (remembering to convert all measurements to meters)
if the washer had no hole, its area would be pi (0.0225m)^2 (remember to convert to meters and to use radius)
the area of the hole is pi(0.00625m)^2
so the area of the washer is pi[(0.0225m)^2 - (0.00625m)^2] = 1.5x10^-3 m
the volume of the washer is 1.5x10^-3 m x 1.5x10^-3 m = 2.25x10^-6 m^3 (the thickness of the washer is 1.5 mm = 1.5x10^-3m)
thus, the mass of the washer = 8598kg/m^3 x 2.25x10^-6m^3 = 0.0189kg = 18.9 grams
Answers
it would take the same time to accelerate from rest to top speed
as it would take to decelerate from top speed to zero
so
instead of
d = Vi t + 1/2 a t^2 where Vi is positive and a is negative
we'll use
Vi = 0 and a is positive
giving
85 = 0 + 1/2 (0.43) t^2 = 0.215 t^2
t^2 = 395.345
t = 19.88s or 20. s to 2 sig figs
or we ccould find Vi from
Vf*2 = Vi^2 + 2 a d
0 = Vi^2 + 2 (0.43) 85
Vi^2 = 71.4
Vi = 8.45m/s
then
85 = 8.45 t + 1/2 (-0.43) t^2
85 = 8.45 t - 0.215 t^2
0.215 t^2 - 8.45 + 85 = 0
t = 19.65s or 20. s to 2 s.f.(minor difference arises from rounding Vi)
or another cheap trick
when a is constant
Vavg = (Vf + Vi) /2 = 8.45/2 = 4.225
and
d = Vavg t
85 = 4.225 t
t = 20.12 or 20. s to 2 s.f. (minor differences from intermidiate roundings)
anyway you choose you get 20. s
Answers
Answer:
500 m
Explanation:
The size of a nucleus is about
Instead, the size of the electron cloud extends at the order of
This means that the ratio between the size of the electron cloud and the size of the nucleus is about
So, the electron cloud is about 10,000 bigger than the nucleus of the atom.
Here we want to build a scale-model atom, in which the nucleus is the size of a tennis ball, so a size of approximately
Therefore, since the proportions must be respected, the electron clouds must be 10,000 bigger, so its size in this model would be:
So, the size of the electron cloud would be 500 m.
Final answer:
The cloud of electrons in a scale-model atom would extend about 100 meters.
Explanation:
The nucleus is a central, positively charged region within an atom. It contains protons, which have a positive electric charge, and neutrons, which are electrically neutral. Nuclei make up the majority of an atom's mass and are held together by the strong nuclear force, while electrons orbit the nucleus in electron shells.
In a scale-model atom where the nucleus is the size of a tennis ball, the cloud of electrons would extend about 100 meters. This can be calculated by comparing the size of the nucleus to the actual size of an atom. The diameter of a tennis ball is approximately 6.7 cm, while the diameter of an atom is on the order of 0.1 nm. By scaling up, we find that the electron cloud would extend around 100 meters.
Learn more about Scale-model atom here:
#SPJ12
45°
90°
180°
50°
I'll report you if you don't actually help. I'd like an actual explanation, please.
Answers
Hey
So first we need to know what the direction of the force is, using your right hand rule point your right hand in the direction of the velocity. You're saying its the z direction, not telling me whether it's into the page or out? Since its a positive z im assuming its coming out. The magnetic field is pushing it upwards, so the force is going in the negative x direction.
The force of a magnetic field is
F = Qv X B
What's weird is that you don't need mass in this equation. Actually you don't even need the formula, its telling you that they're all going in perpendicar directions. the answer is 90 degrees.
Now if you want to know the F just multiply the charge, velocity and magnetic field .
F = GVB
F = 6.048 E -15
Answer : 90 degrees, sin(90) = 1
Final answer:
To find the magnitude and direction of the magnetic force on a proton moving in a magnetic field, you can use the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field. The magnitude of the magnetic force can be calculated using the equation, and its direction can be determined using the right-hand rule. In this case, the angle between the proton's velocity and the magnetic field is 90°.
Explanation:
To determine the magnitude of the magnetic force on the proton, we need to use the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field.
Plugging in the values, we have F = (1.6 × 10-19 C)(1.8 × 105 m/s)(2.1 × 10-1 T)sinθ.
To find the angle θ, we can use the fact that the force is perpendicular to both the velocity and the magnetic field, which means that sinθ = 1.
Therefore, the magnitude of the magnetic force on the proton is F = (1.6 × 10-19 C)(1.8 × 105 m/s)(2.1 × 10-1 T) = 6.048 × 10-14 N. The direction of the magnetic force is given by the right-hand rule, which shows that the force is perpendicular to both the velocity and the magnetic field, pointing in the positive x-direction.
The angle between the proton's velocity and the magnetic field is 90°.
Learn more about magnetic force on a charged particle here:
#SPJ3