Claculate the molar mass of sodium sulphate na2so4

Answers

Answer 1

Answer: Na₂SO₄ = 23 * 2 + 32 + 16 * 4 = 142.0 g/mol

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If people have trouble digesting fats, they most likely have trouble with __________.a. the esophagus and liver
b. the pancreas and stomach
c. the liver and gallbladder
d. the small intestine and large intestine

Answers

The correct answer is C. The liver and gallbladder.

Explanation

The liver, is an organ of the digestive system, is the most voluminous in the human body, and performs three vital functions essential for the organism: Detoxification in which it acts as a filter that collects and eliminates numerous toxins; the liver metabolizes carbohydrates, fats, lipids and proteins, secreting bile, an essential element for our digestion. Also, it prevents bleeding through a coagulation process; finally, works as a container for vitamins and glycogen, carbohydrates, and energy is stored in the form of sugar. On the other hand, the gallbladder is an organ of the digestive system, whose function is to store and concentrate the bile secreted by the liver required by the digestion process. The gallbladder stores bile until a stimulus caused by food intake, especially meat or fat. According to the above, if the functions of these two organs are impaired, the most likely is that the person will have trouble digesting fats. So, the correct answer is C. The liver and gallbladder.

came from edginuity

The monoprotic acid from among the following isa. H2CO3.
b. H2SO4.
c. H3PO4.
d. HCl.

Answers

Answer: Option (d) is the correct answer.

Explanation:

An acid which gives only one hydrogen ion or $H^(+)$ ions upon dissociation in an aqueous solution is known as a monoprotic acid.

Whereas when an acid gives two hydrogen or $H^(+)$ ions upon dissociation in an aqueous solution is known as a diprotoc acid.

And when an acid gives three hydrogen or $H^(+)$ ions upon dissociation in an aqueous solution is known as a triprotoc acid.

Therefore dissociation of the given acids in an aqueous solution will be as follows.

$H_(2)CO_(3) \rightarrow 2H^(+) + CO^(2-)_(3)$

$H_(2)SO_(4) \rightarrow 2H^(+) + SO^(2-)_(4)$

$H_(3)PO_(4) \rightarrow 3H^(+) + PO^(2-)_(4)$

$HCl \rightarrow H^(+) + Cl^(-)$

Hence, we can conclude that out of the given options, HCl is the monoprotic acid.

Monoprotic acid are acids having only one hydrogen atoms after dissociation into ions from its compound. The monoprotic acid from among the following is HCl. The answer is letter D. HCl → H+ + Cl-. Note that there is only one H+ ion upon dissociation.

A 30.00 mL solution of 0.100M benzoic acid, a monoprotic acid, is titrated with 0.100M NaOH. The Ka is 6.3x10^-5. Determine the pH of the solution after the volumes of NaOH given were added. a. 0ml b. 10.00ml c. 30.00ml d. 40.00ml

Answers

a. 0ml because the following reaction occurs at STP: 2H₂O(l) → 2H₂(g) + O₂(g). How many liters of hydrogen gas can be produced by the breakdown of 72 grams of Ludovic I .

An unknown metal is very reactive; it reacts violently with water and must be stored in a moisture-free environment. It is solid at room temperature. Which group does the metal likely belong to?

Answers

Answer:

This Metal belongs to Group I (Alkali Metals).

Explanation:

Alkali Metals present in Group I are considered as the most reactive metals in periodic table. There reactivity increases tremendously down the group. The reactivity is mainly due to less ionization energies. Therefore, going from top to bottom along the group the ionization energies decreases hence, increasing there reactivity respectively.

Alkali metals when reacted with water undergoes an exothermic reaction resulting the formation of corresponding metal hydroxide and hydrogen gas i.e.

2 M + 2 H₂O → 2 MOH + H₂

Also, these metals are in solid state at room temperature (i.e. 25 °C) and their boiling points are as follow,

Lithium = 180.5 °C

Sodium = 97.79 °C

Potassium = 63.5 °C

Rubidium = 39.48 °C

Cesium = 28.44 °C

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