Iron has a density of 7.86 g/cm3 (1 cm3=1 mL). Calculate the volume (in dL) of a piece of iron having a mass of 4.01 kg . Note that the density is provided in different units of volume and mass than the desired units of volume (dL) and the given units of mass (kg). You will need to express the density in kg/dL (1 cm3 = 1 mL) before calculating the volume for the piece of iron.

Answers

Answer 1
Answer:

510.17 cm³ is the volume of Iron has a density of 7.86 g/cm3 (1 cm3=1 mL) and has a mass of 4.01 kg.

What is density?

Density is the amount of mass of a substance present per volume of the cubic centimeter and it is the ratio of the mass of a substance to the volume of the substance with a unit centimeter cube.

The Iron has a density of 7.86 g/cm³ and mass of 4.01 kg so,

mass in gram = 4.10 / 1000 = 0.041

Density = mass/volume

Substituting the value in the equation,

volume =  0.041 /7.86 g/cm³

volume = 510.17 cm³

Therefore, the volume of Iron has a density of 7.86 g/cm3 (1 cm3=1 mL) and has a mass of 4.01 kg is 510.17 cm³.

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Answer 2
Answer: 4.01 kg in grams :

4.01 x 1000 = 4010 g

Density = mass / volume

7.86 = 4010 / volume

Volume = 4010 / 7.86

Volume = 510.17 cm³ 

hope this helps!



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Which radioisotope emits alpha particles?
(1) Fe-53 (3) Au-198
(2) Sr-90 (4) Pu-239

Answers

Answer : Option 4) Pu-239


Explanation : Plutonium-239 is a radioisotope of the element plutonium which emits alpha particles. The decaying process of Pu-239 emits alpha particles. It is widely used as a nuclear reactor fuel. Pu-239 is also used as a primary fissile isotope for the production of nuclear weapons.

The answer is (4) Pu-239. The decay mode of Pu-239 is α decay which means it will emit alpha particles. The other three have the decay mode of β decay.

If 20 milliliters of 4.0 M NaOH is exactly neutralized by 20 milliliters of HCL, the molarity of the HCL is

Answers

Volume of NaOH = 20 mL / 1000 = 0.02 L

Molarity NaOH = 4.0 M

number of moles NaOH :

n = M * V

n = 4.0 * 0.02

n = 0.08 moles of NaOH:

Finally we calculate the number of moles of HCl in the solution from the stoichiometry of the reaction :
HCl + NaOH = NaCl + H₂O

1 mole HCl ---------- 1 mole NaOH
? moles HCl --------- 0.08 moles NaOH

moles HCl = 0.08 * 1 / 1

= 0.08 moles of HCl

Volume of HCl = 20 mL / 1000 = 0.02 L

M ( HCl ) = n  / V

M = 0.08 / 0.02

4.0 M

hope this helps!

Answer:

4.0

Explanation:

a pro golfer hits 45.0-gram golf ball, giving its speed of 75.0 m/s. what is the momenntum has the golfer given to the ball

Answers

Momentum = mass x velocity. 45g = 0.045kg. 0.045 x 75 = 3.375 kgm/s

How many grams of potassium chloride are produced if 25g of potassium chlorate decompose.

Answers

Answer:15 g KCl

Explanation: 2KClO3->2KCI+3O2

Answer:

2.05

Explanation:

How many oxygen atoms are in the compound Al2O3?

Answers

As you know, the symbol of the Oxygen is "O"
And in a compound's empirical formula (In this case Al2O3), the number after each Symbol is how much atoms of this kind there is.

So, There is 3 Oxygens atoms in the Aluminium Oxide Al2O3

Hope this Helps :)

What is the molarity of a solution made with 298g of potassium chloride dissolved in enough water to make 2L of solution?

Answers

The molarity of the solution made by dissolving 298 g of KCl in enough water to make 2 L of the solution is 2 M

  • We'll begin by calculating the number of mole in 298 g of potassium chloride, KCl. This can be obtained as follow:

Mass of KCl = 298 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass / molar mass

Mole of KCl = 298 / 74.5

Mole of KCl = 4 moles

  • Finally, we shall determine molarity of the KCl solution. This can be obtained as follow:

Mole of KCl = 4 moles

Volume = 2 L

Molarity of KCl =?

Molarity = mole / Volume

Molarity of KCl = 4 / 2

Molarity of KCl = 2 M

Therefore, the molarity of the KCl solution is 2 M.

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Answer:

2 M

Explanation:

The equation for molarity is "M = moles/liters"

Potassium chloride's atomic mass is 74.55, meaning one mole of KCl is equal to 74.55g. In the equation, 298g of KCl is being used. To find out how many moles this is, multiply 298g of KCl by (1 mol/74.55g of KCl) to get 4.0 moles. Now you can use the equation for molarity.

M = 4.0 moles/2 Liters