What happens along a stationary front?a. Cold air rises over warm air.
b. The flow of air is neither toward the warm air mass nor toward the cold air mass.
c. Air moves so rapidly upward that hurricanes form.
d. Wind stops completely.

Answers

Answer 1

Answer:

Answer: b. The flow of air is neither toward the warm air mass nor toward the cold air mass.

A stationary front forms between two air masses. A stationary front results when the warm front or cold front air stops moving. This occurs due to the fact that warm front and cold front air masses being opposite to each other but neither of them are able to repel the other. This affects the climatic conditions of the region. The weather is often cloudy along a stationary front and also supported with fall of rain and snow especially if the air in the front is cold with low atmospheric pressure.

Therefore, along a stationary front the flow of air is neither toward the warm air mass nor toward the cold air mass.

Answer 2

Answer:

Final answer:

A stationary front is formed when a cold air mass and a warm air mass meet, but neither is strong enough to displace the other. The air flow is generally neither towards the cold nor warm air mass, often resulting in prolonged cloudiness and precipitation

Explanation:

Along a stationary front, option b best describes what happens. Generally, stationary fronts occur when a cold air mass and a warm air mass meet, but neither is strong enough to move the other. As a result, the flow of air is typically neither toward the warm air mass nor toward the cold air mass. Instead, both air masses essentially stay where they are, often resulting in prolonged periods of cloudiness and precipitation in the area surrounding the front.

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The demand for your hand-made skateboards, in weekly sales, is q = −3p + 700 if the selling price is $p. You are prepared to supply q = 2p − 500 per week at the price $p. What price should you sell your skateboards for so that there is neither a shortage nor a surplus?

Value that is measured by the slope of a position-time graph

Answers

The slope is the change in y over change in x.
In a position vs time graph, the position is the y-axis, and the time is the x-axis.
So the slope would be position over time. Position is a distance. So the slope is distance/time, which is velocity.
And also looking at units, distance is in meters (m), and time is in seconds (s). The unit m/s is a unit for velocity.

A water balloon is launched with a speed of 40 m/s at an angle of 60 degrees to the horizontal. What is the vertical component of the velocity? a 40 m/s
b 34.6 m/s
c 0 m/s
d 20 m/s

Answers

Vertical component = 40 m/s x sin(60) = 34.6 m/s

Answer: b. 34.6 m/s

The vertical component of velocity is approximately 34.64 m/s. Therefore option B is correct.

When an object is launched at an angle, its velocity can be divided into horizontal and vertical components. The vertical component is found by multiplying the initial velocity by the sine of the launch angle.

To find the vertical component of the velocity, we use trigonometric relationships based on the given launch angle of 60 degrees and initial velocity of 40 m/s.

The vertical component $\rm ($v_y$)$ can be calculated as $\rm $v_y = v \cdot \sin(\theta)$$ , where v is the initial velocity and $\theta$ is the launch angle.

Calculation:

Given:

Initialvelocity (v) = 40 m/s

Launch angle $($\theta$)$ = 60 degrees

Vertical component:

$\rm \[ v_y = v \cdot \sin(\theta) \n= 40 \, \text{m/s} \cdot \sin(60^\circ) \approx 34.64 \, \text{m/s} \]$

In this case, with an initial velocity of 40 m/s and a launch angle of 60 degrees, the vertical component of velocity is approximately 34.64 m/s (option b).

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Timers at a swim meet used four different clocks to time an event. Which recorded time is the least precise?a. 48.9107 s
b. 48.91 s
c. 48.910 s
d. 48.9 s

Answers

Answer:

Least precise recorded time is 48.9 seconds.

Explanation:

Here, we need to write the recorded time that is least precise. The given options are (a) 48.9107 s (b) 48.91 s (c) 48.910 s (d) 48.9 s. The precision in any measurement is defined as closeness in any measurement.

First option is most precise as it is precised to four decimal places. Second option is precised to two decimal places. Third option is precised to 3 decimal places. But in option fourth, the recorded time is precised to one decimal place.

Hence, the correct option is (d).

the answer should be D due to the fact that A,B,andC are showing the exact time in which it took for the event while D is vary general on the time the event stoped

Which of the following is true about the action and reaction force referred in Newton's Third Law of Motion? a. I. They have equal magnitude but directed in opposite direction. b. II. They act on the same object simultaneously. c. III. They act on different bodies. d. IV. They act simultaneously.

Answers

Answer:

Option A

Explanation:

Newton's third law : They have equal magnitude but directed in opposite direction.

Why can velocity and speed be interchanged in the formulas

Answers

Because in high school physics, all the problems you're given to deal with
involve motion in a straight line, so you never have to deal with changes in
the direction of motion. If it's OK to ignore direction, then speed and velocity
appear to be the same thing.

A 1200 kg automobile is traveling at a velocity of 100 m/s is its energy potential or kinetic? How much energy does it possess?

Answers

The energy possess is 6,000,000 J

The kinetic energy is a energy by which an object can move and potential energy is a stored energy which depends upon the relative position of various parts of the body.

Given:

The mass of automobile is $m=1200\:\rm kg$ .

The velocity of the automobile is $100\;\rm m/s$ .

How to calculate potential energy and kinetic energy?

Write the formula to calculate the potential energy of the body.

$P.E=mgh$

Since the automobile is on ground so the height $h$ will be 0.

$P.E=1200* 9.81* 0\nP.E=0$

Write the formula to calculate the kinetic energy.

$K.E=(1)/(2)mv^2$

Substitute the value.

$K.E=(1)/(2)* 1200* 100^2\nK.E= 6,000,000 J.$

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Answer:

6,000,000 J (6 million)

Explanation:

Refer to the equations for potential and kinetic energy.

$KE = (1)/(2)mv^(2)\nPE = mgh$

Because the automobile is on the ground (it does not give a height above the ground, therefore we can assume that it is on the ground), height = 0. If you plug in 0 for h in the potential energy equation, we get PE = 0 J.

Therefore, all of the energy is kinetic. Plug in the given information into the kinetic energy equation. M = 1200 kg and v = 100 m/s

$KE = (1)/(2)mv^(2) = (1)/(2)(1200)(100^(2)) = 6,000,000\ J$