The first quartile of a data set is 51, and the third quartile is 67. Which of these values in the data set is an outlier?A. 49
B. 83
C. 93
D. 29

Answers

Answer 1

Answer: Given:
Quartile 1 = 51
Quartile 3 = 67

Interquartile range = Q₃ - Q₁
IQR = 67 - 51
IQR = 16

Inner fence of the data set:
16 x 1.5 = 24

67 + 24 = 91
51 - 24 = 27

Boundaries of inner fence are 27 and 91

16 x 3 = 48

67 + 48 = 115
51 - 48 = 3

Boundaries for outer fence are 3 and 115

C. 93 is an outlier. It is a minor outlier based on the boundaries of the inner fence.

Answer 2

Answer:

Answer: 93

Step-by-step explanation: Apex said so

Related Questions

PLEASE HELP!!!!! theo is renting 2 kinds of tables for his party.one type of table seats 4 ppl and the other seats 6 ppl. if 36 ppl will be at his party and he rents 7 tables,how many of each type of table does he rent
Jordan signed up for annual cross Florida bike ride which is a 170 mile bike ride. After weeks of training he rides at an average of 15 miles per hour.
Two numbers have a product of 48 and a sum of 19 what are the numbers and how do you know
Graph each function. Identify the domain and range of g(x)=|-3|
Pablo has $4,200 to invest for college. Pablo's goal is to have $5,000 after 4 years. Is this possible if he invests with a rate of return of 6%?

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. margin of error: 0.040.04; confidence level 9595%; modifyingabove p with caretp and modifyingabove q with caretq unknown

Answers

The minimum sample size required to estimate a population proportion or percentage is 306.

What is random sampling?

In statistics, a simple random sample is a subset of individuals chosen from a larger set in which a subset of individuals are chosen randomly, all with the same probability. It is a process of selecting a sample in a random way.

In order to determine the minimum sample size required to estimate a population proportion or percentage, we will use the following formula:

n = (z×p×q)/m²

where is the minimum sample size, z is the z-score corresponding to the desired confidence level, p is the population proportion, q is 1-p, and m is the desired margin of error.

In this case, the confidence level is 95%, so the corresponding z-score is 1.96. Since we don't know the population proportion, we will use the symbol p and q to represent it. Therefore, the formula becomes:

n = (1.96×p×q)/(0.04)²

To determine the minimum sample size, we need to determine the value of p and q. Since p + q = 1, if we set p to 0.5, then q will also be 0.5. Therefore, the minimum sample size is:

n = (1.96×0.5×0.5)/(0.04)² = 306.25

≈ 306

Therefore, the minimum sample size required to estimate a population proportion or percentage is 306.

Learn more about the random sample here:

brainly.com/question/12719656.

#SPJ2

Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2÷margin of error2)*p-hat*q-hat

The maximum value of p-hat*q-hat occurs where p-hat = .5 (found by taking the derivative of (p-hat)*(1-p-hat) and setting it equal to 0 to find the maximum. n = ( 2.5762( for 99% confidence interval)÷.0482 )*.5*.5 = 720.028 or 721

Solve the system of equations using cramer's rule -x+y-3z=-4 3x-2y+8z=14 2x-2y+5z=7

Answers

System of Equations
$-1x + 1y - 3z = -4 \n3x - 2y + 8z = 14 \n2x - 2y + 5z = 7$

Coefficient Matrix's Determinant
$D = \left[\begin{array}{ccc}-1&1&-3\n3&-2&8\n2&-2&5\end{array}\right]$

Answer Column
$\left[\begin{array}{ccc}-4\n14\n7\end{array}\right]$

Dx: Coefficient Determinant with Answer-Column values in X-Column
$D_(x) = \left[\begin{array}{ccc}-4&1&-3\n14&-2&8\n7&-2&5\end{array}\right]$

Dy: Coefficient Determinant with Answer-Column Values in Y-Column
$D_(y) = \left[\begin{array}{ccc}-1&-4&-3\n3&14&8\n2&7&5\end{array}\right]$

Dz: Coefficient Determinant with Answer-Column Values in Z-Column
$D_(z) = \left[\begin{array}{ccc}-1&1&-4\n3&-2&14\n2&-2&7\end{array}\right]$

Evaluating each Determinant
$D= \left[\begin{array}{ccc}-1&1&-3\n3&-2&8\n2&-2&5\end{array}\right] \nD = (-1 * (-2) * 5) + (1 * 8 * 2) + (-3 * 3 * (-2)) - (2 * (-2) * (-3)) - (-2 * 8 * (-1)) - (5 * 3 * 1) \nD = (10) + (16) + (18) - (12) - (16) - (15) \nD = 10 + 16 + 18 - 12 - 16 - 15 \nD = 26 + 18 - 12 - 16 - 15 \nD = 44 - 12 - 16 - 15 \nD = 32 - 16 - 15 \nD = 16 - 15 \nD = 1$

$D_(x) = \left[\begin{array}{ccc}-4&1&-3\n14&-2&8\n7&-2&5\end{array}\right] \nD_(x) = (-4 * (-2) * 5) + (1 * 8 * 7) + (-3 * 14 * (-2)) - (7 * (-2) * (-3)) - (-2 * 8 * (-4)) - (5 * 14 * 1)) \nD_(x) = (40) + (56) + (84) - (42) - (64) - (70) \nD_(x) = 40 + 56 + 84 - 42 - 64 - 70 \nD_(x) = 96 + 84 - 42 - 64 - 70 \nD_(x) = 180 - 42 - 64 - 70 \nD_(x) = 138 - 64 - 70 \nD_(x) = 74 - 70 \nD_(x) = 4$

$D_(y) = \left[\begin{array}{ccc}-1&-4&-3\n3&14&8\n2&7&5\end{array}\right] \nD_(y) = (-1 * 14 * 5) + (-4 * 8 * 2) + (-3 * 3 * 7) - (2 * 14 * (-3)) - (7 * 8 * (-1)) * (5 * 3 * (-4)) \nD_(y) = (-70)+ (-64) + (-63) - (-84) - (-56) - (-60) \nD_(y) = -70 - 64 - 63 + 84 + 56 + 60 \nD_(y) = -134 - 63 + 84 + 56 + 60 \nD_(y) = -197 + 84 + 56 + 60 \nD_(y) = -113 + 56 + 60 \nD_(y) = -57 + 60 \nD_(y) = 3$

$D_(z) = \left[\begin{array}{ccc}-1&1&-4\n3&-2&14\n2&-2&7\end{array}\right] \nD_(z) = (-1 * (-2) * 7) + (1 * 14 * 2) + (-4 * 3 * (-2)) - (2 * (-2) * (-4)) - (-2 * 14 * (-1)) - (7 * 3 * 1) \nD_(z) = (14) + (28) + (24) - (16) - (28) - (21) \nD_(z) = 14 + 28 + 24 - 16 - 28 - 24 \nD_(z) = 42 + 24 - 16 - 28 - 21 \nD_(z) = 66 - 16 - 28 - 21 \nD_(z) = 50 - 28 - 21 \nD_(z) = 22 - 21 \nD_(z) = 1$

$x = (D_(x))/(D) = (4)/(1) = 4 \ny = (D_(y))/(D) = (3)/(1) = 3 \nz = (D_(x))/(D) = (1)/(1) = 1 \n(x, y, z) = (4, 3, 1)$

A Roast is taken from the refrigerator (where it had been for several days) and placed immediately in a preheated oven to cook. The temperature R = R(t) of the roast t minutes after being placed in the oven is given bya. What is the temperature of the refrigerator?

b. Express the temperature of the roast 30 minutes after being put in the oven in functional notation, and then calculate its value.

c. By how much did the temperature of the roast increase during the first 10 minutes of cooking?

d. By how much did the temperature of the roast increase from the first hour to 10 minutes after the first hour of cooking?

Answers

Answer:

Step-by-step explanation:

a. We are not given enough information to determine the temperature of the refrigerator.

b. We can express the temperature of the roast 30 minutes after being put in the oven as R(30). Its value depends on the specific function R(t) given in the problem.

c. To find the increase in temperature during the first 10 minutes of cooking, we need to find the difference between the temperature of the roast after 10 minutes and the temperature of the roast when it was put in the oven. This is given by:

R(10) - R(0)

d. To find the increase in temperature from the first hour to 10 minutes after the first hour of cooking, we need to find the difference between the temperature of the roast at 1 hour and 10 minutes and the temperature of the roast at 1 hour. This is given by:

R(70) - R(60)

Final answer:

The temperature of the refrigerator is the initial temperature of the roast. The temperature of the roast 30 minutes after being put in the oven can be expressed as R(30), but its value cannot be determined without a specific function. The temperature increase during specific time intervals can be calculated by finding the difference between the temperatures at the respective times.

Explanation:

a. To find the temperature of the refrigerator, we need to use the given information. Since the roast was in the refrigerator for several days before being placed in the oven, we can assume that the temperature of the refrigerator matches the temperature of the roast initially, which is denoted as R(0). Therefore, the temperature of the refrigerator is R(0).

b. Expressing the temperature of the roast 30 minutes after being put in the oven in functional notation is R(30). To calculate its value, we need the specific function or equation that relates the temperature to time. Without this information, we cannot determine the exact numerical value of R(30).

c. To determine the temperature increase during the first 10 minutes of cooking, we need the temperature difference between the initial temperature of the roast (R(0)) and the temperature after 10 minutes of cooking (R(10)). The increase is given by R(10) - R(0).

d. To find the temperature increase from the first hour to 10 minutes after the first hour of cooking, we need the temperature at the start of the first hour (R(60)) and the temperature at 10 minutes after the first hour (R(60 + 10)). The increase is given by R(60 + 10) - R(60).

Learn more about temperature of the roast here:

brainly.com/question/37575094

#SPJ2

How do you work out 5x + 5 = 2x + 11 in steps with a lot of detail?

Answers

first we have to get the variables on one side and the numbers on the other
5x+5=2x+11
-5 -5
5x=2x+6
-2x -2x

3x=6

now that we have that we can solve for x

since divition undos multiplication we can divide

3x=6
-- --
3 3

x=2 is our final answer

Draw a graph that shows the equation V = 4 + 2t, where V is the total volume of water in a bucket and t is the elapsed time in minutes?

Answers

Since v=4+2t its linear equation in the graph is a straight line. Put t=0,1,2.....give value of v and draw it. For example, if t=-2, v= 0 so the point on XOY axes is A(-2, 0). I hope that this is the answer that you were looking for and it has helped you.

Answer: The graph is attached.

Step-by-step explanation: We are given to draw the graph of the following equation:

$V=4+2t~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i),$

where 'V' is the total volume of water in a bucket and 't' is the elapsed time in minutes.

Since equation (i) is a linear equation in two unknown variables, so the graph will be a straight line.

To draw the graph of a straight line, we need at least two points to be plotted on the graph paper and then joined straight.

If t = 0, then from equation (i), we have

$V=4+2* 0=4.$

If t = -2, then from equation (i), we have

$V=4+2* (-2)=0.$

So, (t. V) = (0, 4) and (-2, 0) are two points on the graph, if 't' is plotted along X-axis and 'V' is plotted along Y-axis.

These two points are joined to draw the graph of the given equation. Please see the attached graph below.

111777
+ 999
can you strike out 6 of these digits so that the total of the remaing numbers shall be 20?

Answers

The total of the remaining numbers shall be 20 by taking out 6 digit as

11 + 9 = 20.

What is addition?

One of the four fundamental operations of mathematics is addition, which is typically denoted by the plus sign (+). The other three are subtraction, multiplication, and division. The entire amount or sum of the two whole numbers is obtained by adding them.

Make 111, 777, and 999 smaller because they are all more than 20.

Now, Five digits, minus one 1, two 7, and two 9, equals twenty 11 + 7 + 9 ≠ 20 (it equals 27).

Now, Remove number 7 now.

If you take out number 1 then

1+7+9=17, not 20

and of if we take out number 9 then

= 11+7=18, not 20

So, 11 + 9 = 20 (we took out numbers: 1, 7, 7, 7, 9 and 9 [6 numbers]).

Learn more about Addition here:

brainly.com/question/29560851

#SPJ7

Since 111, 777, and 999 are all bigger than 20, make them smaller. Take out one 1, two 7, and two 9 (5 numbers): 11 + 7 + 9 ≠ 20 (it equals 27). Now take out number 7. (If you take out number 1 [1+7+9=17, not 20] and of you take out number 9 [11+7=18, not 20].

11 + 9 = 20 (you took out numbers: 1, 7, 7, 7, 9 and 9 [6 numbers]).

Other Questions

How many sides does a parallelogram have?

A four-sided polygon has these properties of rotation and reflection:When it rotates 360°, it maps onto itself at four different angles of rotation. It can be reflected onto itself across four different lines of reflection. Which kind of polygon must it be?

Carson has $450 in his bank account and deposits $70 per month out of his babysitting money. Construct a linear function that models Carson’s bank balance for any given month.

How many different ways can you write a fraction that has a numerator of 2 as a sum of fractions