Which of the following is the conjugate of a complex number with 2 as the real part and −8i as the imaginary part?(A. -2+8i; B. 2+8i; C. 2-8i; D.-2-8i)

Answers

Answer 1

Answer: Hi,

The complex number is

z = a+bi

For a = 2 and b = -8

z = 2+(-8)i
z = 2-8i

The conjugate is

z = a-bi

For a = 2 and b = -8

z = 2-(-8)i
z = 2+8i

Answer:

B. 2+8i

Related Questions

If a roof's slope is 0.5, how high will the roof rise over a 17-foot run?a). 8 1/2 feetb). 17feetc). 1/34 feetd). 34 feet
How to delete brainly accout
An ice chest contains cans of apple juice, cans of grape juice, cans of orange juice, and cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting three cans of juice.
PLEASE HELP ASAP!!!!!
Need help I'm super confused

What formula tells the cost, in dollars, if chocolate chip cookies are $2.50/ dozen and lemon frosteds are $1.50/dozen? let c=number of dozens of chocolate chip cookies;L=number of dozens of lemon frosted; T= total charge

Answers

c= # of dozens chocolate chip cookies= $2.50/dozen

L= # of dozens of lemon frosted= $1.50/dozen

T= total charge

Multiply the number of dozens of chocolate chip cookies by the cost per dozen. Multiply the number of lemon frosted by the cost per dozen. Add those two together to equal the total cost.

T= ($2.50 * c) + ($1.50 * L)
T= $2.50c + $1.50L

ANSWER: T= $2.50c + $1.50L

Hope this helps! :)

The following are angles in a convex quadrilateral: Angle A = 34 degrees Angle B = 108 degree Angle C = 65 degrees What is the measure of the missing angle?

Answers

In a quadrilateral all angels must equal 360 degress. So by adding your angels up and then subtracting them from 360, you will find the missing angle.

34 + 108 + 65 = 207

360-207 = 153

Your unknown angle is 153 degrees

Well since it is a quadrilateral, the degrees equal 360. So add 108 + 34 + 65 = 207. Then subtract 207 from 360. 360 - 207 = 153. So 153 is your missing angle. To check just add 153 + 65 + 34 + 108 = 360.

4 cards are drawn from a well-shuffled deck of 52 cards. What is the probability of obtaining 3 diamonds and one spade?

Answers

The probability is 286 20825.

Final answer:

The probability of drawing three diamonds and one spade from a well-shuffled deck of 52 cards is about 0.0137 or 1.37%.

Explanation:

The subject of this question is the probability in a deck of 52 cards. In a deck, there are 13 cards for each suit: diamonds, spades, clubs, and hearts. In drawing 4 cards, we want to find out the likelihood of picking 3 diamonds and one spade. This type of question deals with combinatorics and probability rules.

First, let's compute the number of ways we can draw 3 diamonds from 13. This is done through a combination, denoted as C(13,3), which equals 286. Next, the number of ways to draw one spade from the 13 available is C(13,1), which equals 13. Therefore, the total favourable outcomes are 286 x 13 = 3718.

Second, let's compute the total number of outcomes which is C(52,4) = 270,725. Therefore, the probability of obtaining 3 diamonds and one spade is 3718/270725, which simplifies to approximately 0.0137 or 1.37% when expressed as a percentage.

Learn more about Combination Probability here:

brainly.com/question/3901018

#SPJ11

Find the GCF of the following monomials. -50m 4 n 7 and 40m 2 n 10

Answers

Answer:

$10m^2n^7$

Step-by-step explanation:

$-50m^4n^7 \ and \ 40m^2n^(10)$

WE need to find GCf for both monomials. GCF is the greatest common factor

$-50 ->-1 \cdot 5 \cdot 5 \cdot 2$

$40 ->2 \cdot 2 \cdot 5 \cdot 2$

GCF is 2 times 5 =10

GCF of exponent is the lowest exponent

GCF of m^4 and m^2 is m^2

GCF of n^7 and n^10 is n^7

$-50m^4n^7 \ and \ 40m^2n^(10)$

GCF is $10m^2n^7$

2 , 1, , 2 if it helps <3

Which sum is equal to x^2+6x-5/x^2-25

Answers

Answer: The sum will be given as

$1+(6x+20)/(x^2-25)$

Step-by-step explanation:

Since we have given that

$(x^2+6x-5)/(x^2-25)$

We just need to simplify and get the sum :

$\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}x^2+6x-5\mathrm{\:and\:the\:divisor\:}x^2-25\mathrm{\::\:}(x^2)/(x^2)=1\n\n\mathrm{Quotient}=1\n\n\mathrm{Multiply\:}x^2-25\mathrm{\:by\:}1:\:x^2-25\n\n\mathrm{Subtract\:}x^2-25\mathrm{\:from\:}x^2+6x-5\mathrm{\:to\:get\:new\:remainder}\n\n\mathrm{Remainder}=6x+20\n\n(x^2+6x-5)/(x^2-25)=1+(6x+20)/(x^2-25)$

Hence, the sum will be given as

$1+(6x+20)/(x^2-25)$

1/x+5 + x/x-5 i think so

Explain how a division problem is like an unknown factor?

Answers

A division problem is unsolved, so it is an unknown factor until ithe problem is solved.

Other Questions

Oscar is sealing his boat with a special type of sealent. he needs to mix the sealant with water at a ratio of 3:2. How many gallons of water will he need if he planes to use 9 gallons of sealant?

Which function in vertex form is equivalent to f(x) = 4 + x2 – 2x?

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Edwards aquifer was 700.7 feet. Rounded to the nearest foot how would this depth be expressed?