CHEMISTRY HIGH SCHOOL

How many grams of CU are required to replace 45.0 grams of silver nitrate?1Cu + 2AgNO3 -> 1Cu (No3)2 +2Ag

Answers

Answer 1
Answer: Molar mass Cu = 63.546 g/mol  and AgNO₃ = 169.87

1 Cu + 2 AgNO₃ -> 1 Cu (NO₃)₂ +2 Ag

63,546 -------- 2 * 169.87
? g Cu ------- 45.0 

Mass ( Cu ) = 45.0 * 63,546 / 2 * 169.87

Mass ( Cu ) = 2859,57 / 339,74

Mass = 8.4169 g of Cu

hope this helps!

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Which pair of compounds will form a buffer in aqueous solution?

Answers

Buffer solutions consist of an aqueous solution of a weak acid and its conjugate base or a weak base and its conjugate acid. Buffer solutions are used to have better control of the pH of solutions.

An example of a weak acid and its conjugate base is acetic acid (CH3COOH) and sodium acetate (CH3COONa).

Which of the following is NOT a method of transferring heat?a. convection
c. reduction
b. radiation
d. conduction

Answers

The answer is Reduction. All three methods (convection, radiation, and conduction) are all ways of transferring heat. Convection is the transfer of heat by means of a medium such as air. Conduction is the transfer of heat from the contact of two surfaces at different temperatures. Radiation is the transfer of heat via electromagnetic waves.

Reduction is a chemical reaction that involves the gain of electrons. It is the opposite of oxidation which involves the loss of electrons.

Under which conditions of temperate and pressure does oxygen gas behave least like an ideal gas

Answers

Under extremely high pressure and extremely low temperature. This is because part of the requirements of an ideal gas is that the atoms/molecules don't interact which brakes down at low temperatures and the atoms/molecules are point masses that have insignificant volumes compared to the volume the gas is in which breaks down at high pressures.

If I add 25mL of water to 125 mL of 0.25 M NaOH solution, what will the molarity of the diluted solution be?

Answers

Answer:

0.208333 M

Explanation:

M2=M1V1/V2=(0.25 M)(125mL)/(125mL+25 mL)= 0.208333 M

Explain why all ores are minerals but all minerals are not ores.

Answers

An ore is a type of rock that contains many minerals. But a mineral is just a part of the ore. So all ores are minerals but all minerals are not ores.
Minerals:Metal bearing substance, found in earth's crust are called minerals
Ore:the Minerals which metals can be obtained on a commercial scale are called Ores
   form this definitions we can understand that ores are minerals which is used to obtain metals so, only all ores are minerals but all minerals are not ores.

How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3?

Answers

Considering the definition of molar mass, 1.26 moles are in 98.3 grams of aluminum hydroxide, Al(OH)₃.

The given molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

In this case, you know the molar mass of the elements is:

  • Al= 27 g/mole
  • O= 16 g/mole
  • H= 1 g/mole

So, the molar mass of the compound Al(OH)₃ is calculated as:

Al(OH)₃= 27 g/mole + 3× (16 g/mole + 1 g/mole)

Solving:

Al(OH)₃= 78 g/mole

Next, you can apply the following rule of three: if 78 grams of the compound are contained in 1 mole, 98.3 grams are contained in how many moles?

amount of moles=(98.3 gramsx1 mole)/(78 grams)

amount of moles= 1.26 moles

1.26 moles are in 98.3 grams of aluminum hydroxide, Al(OH)₃.

Learn more:
We have to calculate the molar mass of  AL(OH)₃
Atomic mass (Al)=27 amu
Atomic mass (O)=16 amu
Atomic mass (H)=1 amu

molecular weight= 27 amu+3(16 amu + 1 amu) =78 amu.

Therefore, the molar mass of Al (OH)₃ is 78 g/ mol

Now, we calculate the number of moles in 98.3 g of aluminum hydroxide.

78 g-------------------1 mol
98.3 g-----------------  x

x=(98.3 g * 1 mol) / 78 g=1.26 moles.

Answer: 1.26 moles.
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