The basic unit for mass is thea. gram.
c. cubic meter.
b. metric ton.
d. meter.

Answers

Answer 1
Answer:

Answer: The correct answer is option a.

Explanation:

Basic unit to measure mass is defined as the unit which is commonly used to measure the mass of an object.

From the given options,

Option a: Grams is a unit which is used to measure mass and it is the commonly used unit.

Option b: Cubic meter is the unit which is used to measure the volume of an object.

Option c: Metric ton is a unit which is used to measure the mass of an object but this unit is not commonly used. hence, this is not  basic unit to measure mass.

Option d: Meter is the unit which is used to measure length.

From the above information, the correct answer is option a.

Answer 2
Answer: gram according to the metric system

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What is an example of a sport related activity A .Weight lifting B.Soccer C.Jumping rope D.Running A Race

Answers

The correct answer is B. Soccer.
Hope this helps and have a good night! :3
sports are games so lets do process of elimination
A.) weight lifting (exercise)
B.) Soccer (sport)
C.) jump rope (exercise)
D.) Running a race (exercise) but questionable 

i would say B.) soccer
hehe

A 1200 kg car starts from rest and travels 100m in a time of 10 seconds . A) what is the acceleration of the car? B) what force must have acted on the car during this time? C) what is the velocity of the car after 10 seconds? D) what work was done on the car? E) what minimum power did the engine produce?

Answers

Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
velocity (v) =  (distance)/(time)

                         = (100~ m)/(10~seconds)

                         = 10 m/s
Note that this one is the final velocity.
We also know that, 
initial velocity (u) = 0 m/s .......because the car starts from rest.
Now,
acceleration (a)= (change~in~velocity)/(time)

                               = (v-u)/(t)

                               = (10-0)/(10)

                               = 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
                = 1200 kg * 1 m/s²
                = 1200 kg.m/s²
                = 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....note that displacement is                                                                                                      same as distance.
                         = 1200 N * 100 m
                          = 120000 N.m
                          = 120000 J
Now,
Power (P) = (Work~done(W))/(time(t))

                 = (120000~J)/(10s)

                 = 12000 J/s
                 = 12000 watt
SO,
 A) The acceleration of the car is 1 m/s².
 B) 1200 Newton (N) force must have acted on the car.
 C) The velocity of the car after 10 seconds is 10 m/s.
 D) 120000 Joule (J) work was done on the car.
 E) The engine produced a minimum power of 12000 watt.

Density is given in ____.
a. Pa/cm3
c. g/s2
b. N/m2
d. g/cm3

Answers

Density is defined as  [mass] / [volume] .

The only choice listed with those physical dimensions is 'd' .

In economics, _________ is the amount of a resource that firms and producers are willing and able to provide to the marketplace

Answers

sectors are the amount of resources

A sprinter can run 100.0 meters in 10.4 seconds. Find the velocity of this runner. (Please put answer into ladder cancellation format!!)

Answers

Hope you get it thank you :)

An object that has a height of 0.4 meter is placed at a distance of 0.7 meter from a concave spherical mirror. An image is formed in front of the mirror and has a height of 0.35 meter. How far from the mirror is the image located?A. 0.2000 m
B. 0.4275 m
C. 0.6125 m
D. 0.8000 m

Answers

Answer

C. 0.6125 m

Explanation

The magnification of an image produced by curved mirrors can be given in two ways;

Magnification, M = (Height of the image) / (height if the object) and

M = (image distance,V) / (Object distance, U).

Using the first formula,

M = 0.35/0.4

= 0.875

Now from the second formula,

M = V/U

0.875 = V/0.7

V = 0.875 × 0.7

= 0.6125 m



Answer : v = 0.1625 m.

Explanation :

It is given that,

Height of an object, h_o=0.4\ m

Object distance, u=-0.7\ m

Height of an image, h_i=0.35\ m

We have to find the image distance (v).

We know that the magnification of mirror is the ratio of height of image to the height of object.

i.e. m=(h_i)/(h_o)..............(1)

Also, magnification is the ratio of image distance to that of object distance.

i.e m=(-v)/(u)............(2)

So, from equation (1) and (2)

(-v)/(u)=(h_i)/(h_o)

(-v)/(-0.7\ m)=(0.35\ m)/(0.4\ m)

v=0.6125\ m

So, image is located at a distance of 0.6125 m.