PHYSICS HIGH SCHOOL

Two vertical springs have identical spring constants, but one has a ball of mass m hanging from it and the other has a ball of mass 2m hanging from it. Part A If the energies of the two systems are the same, what is the ratio of the oscillation amplitudes?

Answers

Answer 1

Answer:

Answer:

$(A_1)/(A_2)=1$

Explanation:

given,

two identical spring have identical spring constant

mass 'm' is hanging on one spring and mass of '2m' on another wall.

energy of the two system is same

energy of the system having mass 'm'

$E = (1)/(2)m\omega_1^2A_1^2$

energy of the system having mass '2m'

$E = (1)/(2)(2m)\omega_1^2A_1^2$

now, Energy are same

$(1)/(2)m\omega_1^2A_1^2= (1)/(2)(2m)\omega_1^2A_1^2$

$(A_1^2)/(A_2^2)=(2\omega_2^2)/(\omega_1^2)$

we know $k = mw^2$

$(A_1)/(A_2)=\sqrt{\frac{2(k)/(m_2)}{{(k)/(m_1)}}$

$(A_1)/(A_2)=\sqrt{(2m_1)/(m_2)}$

$(A_1)/(A_2)=\sqrt{(2m)/(2m)}$

$(A_1)/(A_2)=1$

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Answers

Answer:

option A

Explanation:

given,

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A bicyclist bikes the 56 mi to a city averaging a certain speed. The return trip is made at a speed that is 6 mph slower. Total time for the round trip is 11 hr. Find the bicyclist's average speed on each part of the trip.

Answers

Answer:

Speed of the bicyclist when going to city = 14 miles per hour.

Speed while return trip = 8 miles per hour.

Explanation:

Let the speed of the bicyclist when going to city = x miles per hour.

Speed while return trip = x - 6 miles per hour.

Total time taken = 11 hrs = Time for the trip to city + time taken for return trip.

Also, Time = Distance / Time.

So,

56 / x + 56 / ( x -6) = 11

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Solving for x we get:

Acceptable x = 14 miles per hour.

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Final answer:

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Explanation:

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56/x + 56/(x - 6) = 11

Now, we can solve this equation to find the value of x, which represents the average speed on the first part of the trip. Once we have x, we can find the average speed on the second part of the trip by subtracting 6 from x.

Learn more about Average speed here:

brainly.com/question/12322912

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Answers

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Answers

Answer

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